{"id":41121,"date":"2019-09-26T01:30:24","date_gmt":"2019-09-26T00:30:24","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/que-es-la-primera-ley-en-terminos-de-entalpia-dh-dq-vdp-definicion\/"},"modified":"2020-01-13T13:29:50","modified_gmt":"2020-01-13T12:29:50","slug":"que-es-la-primera-ley-en-terminos-de-entalpia-dh-dq-vdp-definicion","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/es\/que-es-la-primera-ley-en-terminos-de-entalpia-dh-dq-vdp-definicion\/","title":{"rendered":"\u00bfQu\u00e9 es la primera ley en t\u00e9rminos de entalp\u00eda? DH = dQ + Vdp &#8211; Definici\u00f3n"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">La primera ley de la termodin\u00e1mica en t\u00e9rminos de entalp\u00eda (dH = dQ + Vdp) nos muestra por qu\u00e9 los ingenieros usan la entalp\u00eda en ciclos termodin\u00e1micos (por ejemplo, ciclo de Brayton o ciclo de Rankine).\u00a0Ingenieria termal<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Primera ley en t\u00e9rminos de entalp\u00eda dH = dQ + Vdp<\/h2>\n<p>La\u00a0<a title=\"\u00bfQu\u00e9 es la entalp\u00eda?\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-enthalpy\/\"><strong>entalp\u00eda<\/strong><\/a>\u00a0se define para ser la suma de la\u00a0<a href=\"https:\/\/www.thermal-engineering.org\/es\/que-es-la-energia-interna-energia-termica-definicion\/\">energ\u00eda interna<\/a>\u00a0E m\u00e1s el producto de la\u00a0<a title=\"\u00bfQu\u00e9 es la presi\u00f3n? - F\u00edsica\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/\">presi\u00f3n p<\/a>\u00a0y\u00a0<a title=\"\u00bfQu\u00e9 es el volumen? - F\u00edsica\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-volume-physics\/\">el volumen V<\/a>\u00a0.\u00a0En muchos an\u00e1lisis termodin\u00e1micos aparece la suma de la energ\u00eda interna U y el producto de la presi\u00f3n py el volumen V, por lo tanto, es conveniente dar a la combinaci\u00f3n un nombre,\u00a0<strong>entalp\u00eda<\/strong>\u00a0y un s\u00edmbolo distintivo, H.<\/p>\n<p><em><strong>H = U + pV<\/strong><\/em><\/p>\n<p>Ver tambi\u00e9n:\u00a0<a title=\"\u00bfQu\u00e9 es la entalp\u00eda?\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-enthalpy\/\">entalp\u00eda<\/a><\/p>\n<p>La\u00a0<strong>primera ley de la termodin\u00e1mica<\/strong>\u00a0en t\u00e9rminos de\u00a0<strong>entalp\u00eda<\/strong>\u00a0nos muestra por qu\u00e9 los ingenieros usan la entalp\u00eda en ciclos termodin\u00e1micos (por ejemplo, el\u00a0<strong>ciclo de Brayton<\/strong>\u00a0o el\u00a0<strong>ciclo de Rankine<\/strong>\u00a0).<\/p>\n<p>La forma cl\u00e1sica de la ley es la siguiente ecuaci\u00f3n:<\/p>\n<p><em><strong>dU = dQ &#8211; dW<\/strong><\/em><\/p>\n<p>En esta ecuaci\u00f3n,\u00a0<strong>dW<\/strong>\u00a0es igual a\u00a0<strong>dW = pdV<\/strong>\u00a0y se conoce como el\u00a0<strong>trabajo l\u00edmite<\/strong>\u00a0.<\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\"><span>Como\u00a0<\/span><strong><em><span>H = U + pV<\/span><\/em><\/strong><span>\u00a0, entonces\u00a0<\/span><em><strong><span>dH = dU + pdV + Vdp<\/span><\/strong><\/em><span>\u00a0y sustituimos\u00a0<\/span><em><strong><span>dU = dH &#8211; pdV &#8211; Vdp<\/span><\/strong><\/em><span>\u00a0en la forma cl\u00e1sica de la ley:<\/span><em><strong><span>dH &#8211; pdV &#8211; Vdp = dQ &#8211; pdV<\/span><\/strong><\/em><\/p>\n<p><span>Obtenemos la ley en t\u00e9rminos de entalp\u00eda:<\/span><\/p>\n<p><strong><em><span>dH = dQ + Vdp<\/span><\/em><\/strong><\/p>\n<p><span>o<\/span><\/p>\n<p><strong><em><span>dH = TdS + Vdp<\/span><\/em><\/strong><\/p>\n<p><span>En esta ecuaci\u00f3n, el t\u00e9rmino\u00a0<\/span><em><strong><span>Vdp<\/span><\/strong><\/em><span>\u00a0es un\u00a0<\/span><strong><span>proceso de flujo de trabajo.\u00a0<\/span><\/strong><span>Este trabajo, \u00a0\u00a0<\/span><em><strong><span>Vdp<\/span><\/strong><\/em><span>\u00a0, se utiliza para\u00a0<\/span><strong><span>sistemas de flujo abierto<\/span><\/strong><span>\u00a0como una\u00a0<\/span><strong><span>turbina<\/span><\/strong><span>\u00a0o una\u00a0<\/span><strong><span>bomba<\/span><\/strong><span>\u00a0en la que hay un\u00a0<\/span><strong><span>&#8220;dp&#8221;<\/span><\/strong><span>\u00a0, es decir, un cambio de presi\u00f3n.\u00a0No hay cambios en el\u00a0<\/span><a title=\"Control Volume - Control Volume Analysis\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/control-volume-control-volume-analysis\/\"><span>volumen de control<\/span><\/a><span>\u00a0.\u00a0Como puede verse, esta forma de ley\u00a0<\/span><strong><span>simplifica la descripci\u00f3n de la transferencia de energ\u00eda<\/span><\/strong><span>\u00a0.\u00a0<\/span><strong><span>A presi\u00f3n constante<\/span><\/strong><span>\u00a0, el\u00a0<\/span><strong><span>cambio de entalp\u00eda<\/span><\/strong><span>\u00a0es igual a la\u00a0<\/span><strong><span>energ\u00eda<\/span><\/strong><span>\u00a0transferida del ambiente a trav\u00e9s del calentamiento:<\/span><\/p>\n<p><strong><span>Proceso isob\u00e1rico (Vdp = 0):<\/span><\/strong><\/p>\n<p><strong><span>dH = dQ \u00a0 \u00a0\u00a0\u00a0<\/span><span>\u2192<\/span><span>\u00a0\u00a0 \u00a0 \u00a0Q = H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><\/p>\n<p><strong><span>En una entrop\u00eda constante<\/span><\/strong><span>\u00a0, es decir, en un proceso isentr\u00f3pico, el\u00a0<\/span><strong><span>cambio de entalp\u00eda<\/span><\/strong><span>\u00a0es igual al\u00a0<\/span><strong><span>trabajo del proceso de flujo<\/span><\/strong><span>\u00a0realizado en o por el sistema:<\/span><\/p>\n<p><strong><span>Proceso isentr\u00f3pico (dQ = 0):<\/span><\/strong><\/p>\n<p><strong><span>dH = Vdp\u00a0 \u00a0 \u00a0\u00a0<\/span><span>\u2192<\/span><span>\u00a0\u00a0 \u00a0 \u00a0W = H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><\/p>\n<p><span>Es obvio, ser\u00e1 muy \u00fatil en el an\u00e1lisis de los dos ciclos termodin\u00e1micos utilizados en la ingenier\u00eda de energ\u00eda, es decir, en el ciclo de Brayton y el ciclo de Rankine.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Ejemplo: primera ley de termodin\u00e1mica y ciclo de Brayton<\/span><\/h2>\n<p><span>Supongamos el\u00a0<\/span><strong><span>ciclo Brayton ideal<\/span><\/strong><span>\u00a0que describe el funcionamiento de un\u00a0<strong>motor de calor a\u00a0<\/strong><\/span><strong><span>presi\u00f3n constante<\/span><\/strong>\u00a0<span>.\u00a0<strong>Los modernos<\/strong>\u00a0motores de\u00a0<strong>turbina de gas<\/strong>\u00a0y los motores de\u00a0<strong>inyecci\u00f3n de aire<\/strong>\u00a0tambi\u00e9n siguen el ciclo de Brayton.\u00a0Este ciclo consta de cuatro procesos termodin\u00e1micos:<\/span><\/p>\n<ol>\n<li>\n<figure id=\"attachment_16843\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-16843\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/first-law-example-brayton-cycle.png\"><img loading=\"lazy\" class=\"size-medium wp-image-16843 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/first-law-example-brayton-cycle-300x244.png\" alt=\"primera ley - ejemplo - ciclo de brayton\" width=\"300\" height=\"244\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/first-law-example-brayton-cycle-300x244.png\" \/><\/a><figcaption id=\"caption-attachment-16843\" class=\"wp-caption-text\"><span>El ciclo ideal de Brayton consiste en cuatro procesos termodin\u00e1micos.\u00a0Dos procesos isentr\u00f3picos y dos procesos isob\u00e1ricos.<\/span><\/figcaption><\/figure>\n<p><strong><span>Compresi\u00f3n isentr\u00f3pica<\/span><\/strong><span>\u00a0: el aire ambiente ingresa al compresor, donde se presuriza (1 \u2192 2).\u00a0El trabajo requerido para el compresor viene dado por\u00a0<\/span><strong><span>W\u00a0<\/span><\/strong><strong><sub><span>C<\/span><\/sub><\/strong><strong><span>\u00a0= H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><strong><span>\u00a0.<\/span><\/strong><\/li>\n<li><strong><span>adici\u00f3n de calor isob\u00e1rico<\/span><\/strong><span>\u00a0: el aire comprimido pasa a trav\u00e9s de una c\u00e1mara de combusti\u00f3n, donde se quema el combustible y se calienta el aire u otro medio (2 \u2192 3).\u00a0Es un proceso de presi\u00f3n constante, ya que la c\u00e1mara est\u00e1 abierta para fluir hacia adentro y hacia afuera.\u00a0El calor neto agregado viene dado por\u00a0<\/span><strong><span>Q\u00a0<\/span><\/strong><strong><sub><span>add<\/span><\/sub><\/strong><strong><span>\u00a0= H\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><\/li>\n<li><strong><span>Expansi\u00f3n isentr\u00f3pica<\/span><\/strong><span>\u00a0: el aire calentado y presurizado se expande en la turbina y entrega su energ\u00eda.\u00a0El trabajo realizado por la turbina viene dado por\u00a0<\/span><strong><span>W\u00a0<\/span><\/strong><strong><sub><span>T<\/span><\/sub><\/strong><strong><span>\u00a0= H\u00a0<\/span><\/strong><strong><sub><span>4<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><\/li>\n<li><strong><span>rechazo de calor isob\u00e1rico<\/span><\/strong><span>\u00a0: el calor residual debe rechazarse para cerrar el ciclo.\u00a0El calor neto rechazado viene dado por\u00a0<\/span><strong><span>Q\u00a0<\/span><\/strong><strong><sub><span>re<\/span><\/sub><\/strong><strong><span>\u00a0= H\u00a0<\/span><\/strong><strong><sub><span>4<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><\/li>\n<\/ol>\n<p><span>Como se puede ver, podemos describir y calcular (por ejemplo, eficiencia termodin\u00e1mica) tales ciclos (de manera similar para el\u00a0<\/span><strong><span>ciclo de Rankine<\/span><\/strong><span>\u00a0) usando\u00a0<\/span><a title=\"\u00bfQu\u00e9 es la entalp\u00eda?\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-enthalpy\/\"><span>entalp\u00edas<\/span><\/a><span>\u00a0.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div><\/div>\n<div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Este art\u00edculo se basa en la traducci\u00f3n autom\u00e1tica del art\u00edculo original en ingl\u00e9s. Para m\u00e1s informaci\u00f3n vea el art\u00edculo en ingl\u00e9s. Puedes ayudarnos. Si desea corregir la traducci\u00f3n, env\u00edela a: translations@nuclear-power.com o complete el formulario de traducci\u00f3n en l\u00ednea. Agradecemos su ayuda, actualizaremos la traducci\u00f3n lo antes posible. Gracias.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>La primera ley de la termodin\u00e1mica en t\u00e9rminos de entalp\u00eda (dH = dQ + Vdp) nos muestra por qu\u00e9 los ingenieros usan la entalp\u00eda en ciclos termodin\u00e1micos (por ejemplo, ciclo de Brayton o ciclo de Rankine).\u00a0Ingenieria termal Primera ley en t\u00e9rminos de entalp\u00eda dH = dQ + Vdp La\u00a0entalp\u00eda\u00a0se define para ser la suma de &#8230; <a title=\"\u00bfQu\u00e9 es la primera ley en t\u00e9rminos de entalp\u00eda? DH = dQ + Vdp &#8211; Definici\u00f3n\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/es\/que-es-la-primera-ley-en-terminos-de-entalpia-dh-dq-vdp-definicion\/\" aria-label=\"M\u00e1s en \u00bfQu\u00e9 es la primera ley en t\u00e9rminos de entalp\u00eda? DH = dQ + Vdp &#8211; Definici\u00f3n\">Leer m\u00e1s<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[16],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u00bfQu\u00e9 es la primera ley en t\u00e9rminos de entalp\u00eda? 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