{"id":43948,"date":"2019-10-14T05:21:42","date_gmt":"2019-10-14T04:21:42","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quest-ce-que-la-force-de-trainee-exemple-coefficient-de-trainee-definition\/"},"modified":"2020-02-17T10:55:15","modified_gmt":"2020-02-17T09:55:15","slug":"quest-ce-que-la-force-de-trainee-exemple-coefficient-de-trainee-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-force-de-trainee-exemple-coefficient-de-trainee-definition\/","title":{"rendered":"Qu&#8217;est-ce que la force de tra\u00een\u00e9e Exemple &#8211; Coefficient de tra\u00een\u00e9e &#8211; D\u00e9finition"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Exemple: force de tra\u00een\u00e9e &#8211; coefficient de tra\u00een\u00e9e.\u00a0Calculez la r\u00e9sistance au frottement d&#8217;un seul crayon de combustible dans le c\u0153ur d&#8217;un r\u00e9acteur en fonctionnement normal (d\u00e9bit nominal).\u00a0Probl\u00e8me de solution.\u00a0G\u00e9nie thermique<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Drag Force en g\u00e9nie nucl\u00e9aire<\/h2>\n<p>L&#8217;analyse de la\u00a0<strong>force de levage hydraulique<\/strong>\u00a0est l&#8217;une des analyses les plus importantes dans la conception d&#8217;un assemblage de combustible et dans l&#8217;analyse de la compatibilit\u00e9 hydraulique des noyaux m\u00e9lang\u00e9s.\u00a0Les forces verticales sont induites par un \u00e9coulement ascendant \u00e0 grande vitesse \u00e0 travers le\u00a0<a title=\"C\u0153ur du r\u00e9acteur\" href=\"https:\/\/www.reactor-physics.com\/what-is-reactor-core-definition\/\">c\u0153ur<\/a>\u00a0du\u00a0<a title=\"Reactor Core\" href=\"https:\/\/www.reactor-physics.com\/what-is-reactor-core-definition\/\">r\u00e9acteur<\/a>\u00a0.\u00a0La voie d\u2019\u00e9coulement du fluide de refroidissement du\u00a0<a title=\"Cuve de r\u00e9acteur\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/nuclear-reactor\/reactor-pressure-vessel\/\">r\u00e9acteur \u00e0<\/a>\u00a0travers la\u00a0<a title=\"Reactor Pressure Vessel\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/nuclear-reactor\/reactor-pressure-vessel\/\">cuve<\/a>\u00a0du\u00a0<a title=\"Reactor Pressure Vessel\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/nuclear-reactor\/reactor-pressure-vessel\/\">r\u00e9acteur<\/a>\u00a0serait:<\/p>\n<ul>\n<li>\n<figure id=\"attachment_14206\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-14206\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Continuity-Equation-Flow-Rate-min.png\"><img loading=\"lazy\" class=\"size-medium wp-image-14206 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Continuity-Equation-Flow-Rate-min-300x300.png\" alt=\"\u00c9quation de continuit\u00e9 - D\u00e9bits dans le r\u00e9acteur\" width=\"300\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Continuity-Equation-Flow-Rate-min-300x300.png\" \/><\/a><figcaption id=\"caption-attachment-14206\" class=\"wp-caption-text\">Exemple de d\u00e9bits dans un r\u00e9acteur.\u00a0C&#8217;est un exemple illustratif, les donn\u00e9es ne repr\u00e9sentent aucune conception de r\u00e9acteur.<\/figcaption><\/figure>\n<p>Le liquide de refroidissement p\u00e9n\u00e8tre dans la\u00a0<strong>cuve<\/strong>\u00a0du\u00a0<strong>r\u00e9acteur<\/strong>\u00a0au niveau de la buse d\u2019admission et entre en contact avec le\u00a0<a title=\"Noyau baril\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/nuclear-reactor\/core-barrel\/\">cylindre<\/a>\u00a0.<\/li>\n<li>Le carottier contraint l&#8217;eau \u00e0 s&#8217;\u00e9couler dans l&#8217;espace situ\u00e9 entre la paroi de la cuve du r\u00e9acteur et le\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/nuclear-reactor\/core-barrel\/\">carottier<\/a>\u00a0. Cet espace est g\u00e9n\u00e9ralement appel\u00e9\u00a0<strong>descendant<\/strong>\u00a0.<\/li>\n<li>\u00c0 partir du bas de l&#8217;enceinte sous pression, le flux est invers\u00e9 \u00e0 travers le noyau afin de traverser les\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/nuclear-fuel\/\">assemblages de combustible<\/a>\u00a0, o\u00f9 la temp\u00e9rature du liquide de refroidissement augmente \u00e0 mesure qu&#8217;il passe \u00e0 travers les barres de combustible.<\/li>\n<li>Enfin, le fluide caloporteur du r\u00e9acteur le plus chaud entre dans la r\u00e9gion interne sup\u00e9rieure, o\u00f9 il est achemin\u00e9 par la buse de sortie dans les branches chaudes du circuit primaire et se dirige ensuite vers les\u00a0<strong><a title=\"G\u00e9n\u00e9rateur de vapeur\" href=\"https:\/\/www.nuclear-power.com\/steam-generator\/\">g\u00e9n\u00e9rateurs de vapeur<\/a>\u00a0.<\/strong><\/li>\n<\/ul>\n<p>Les assemblages combustibles sont maintenus par la\u00a0<strong>structure de guidage sup\u00e9rieure<\/strong>\u00a0, qui d\u00e9finit le sommet du noyau.\u00a0Cet assemblage est en acier inoxydable et sert \u00e0 plusieurs usages.\u00a0La structure de guidage sup\u00e9rieure exerce une\u00a0<strong>force axiale<\/strong>\u00a0sur les assemblages combustibles (gr\u00e2ce \u00e0 des ressorts dans la buse sup\u00e9rieure), d\u00e9finissant ainsi la position exacte de l\u2019assemblage combustible dans le noyau.\u00a0La\u00a0bride de\u00a0<strong>montage de la structure de guidage sup\u00e9rieure<\/strong>\u00a0est maintenue en place et pr\u00e9charg\u00e9e par la bride de t\u00eate de fermeture RPV.\u00a0La structure de guidage sup\u00e9rieure guide et prot\u00e8ge \u00e9galement\u00a0<a title=\"Barres de commande\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/control-rods\/\">les<\/a>\u00a0ensembles de\u00a0<a title=\"Control Rods\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/control-rods\/\">barres de commande<\/a>\u00a0et les instruments int\u00e9gr\u00e9s.<\/p>\n<p>La force d&#8217;appui requise de la\u00a0<strong>structure de guidage sup\u00e9rieure<\/strong>\u00a0sur les assemblages combustibles doit \u00eatre calcul\u00e9e avec soin.\u00a0Une force d&#8217;appui insuffisante peut entra\u00eener la\u00a0<strong>lev\u00e9e de l&#8217;assemblage combustible<\/strong>\u00a0, par contre, une force d&#8217;appui excessive peut entra\u00eener une flexion\u00a0<strong>de l&#8217;assemblage combustible<\/strong> , ce qui est \u00e9galement inacceptable.<\/p>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<h2><span>Exemple: force de tra\u00een\u00e9e &#8211; coefficient de tra\u00een\u00e9e &#8211; faisceau de carburant<\/span><\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-20407 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel-254x300.png\" alt=\"Diam\u00e8tre hydraulique - Canal de carburant\" width=\"254\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel-254x300.png\" \/><\/a><span>Calculer la\u00a0<\/span><strong><span>tra\u00een\u00e9e<\/span><\/strong><span>\u00a0de\u00a0<strong>frottement<\/strong>\u00a0d&#8217;une\u00a0<\/span><strong><span>barre de combustible unique \u00e0 l&#8217;<\/span><\/strong><span>\u00a0\u00a0int\u00e9rieur d&#8217;un c\u0153ur de r\u00e9acteur en fonctionnement normal (d\u00e9bit de conception).\u00a0Supposons que ce crayon de combustible fait partie d&#8217;un faisceau de combustible avec le r\u00e9seau de combustible rectangulaire et que ce faisceau de combustible ne contient pas de grilles d&#8217;espacement.\u00a0Sa hauteur est\u00a0<\/span><strong><span>h = 4 m<\/span><\/strong><span>\u00a0et la vitesse d&#8217;\u00e9coulement du c\u0153ur est constante et \u00e9gale \u00e0\u00a0<\/span><strong><span>V\u00a0<\/span><\/strong><strong><sub><span>c\u0153ur<\/span><\/sub><\/strong><strong><span>\u00a0= 5 m \/ s.<\/span><\/strong><\/p>\n<p><span>Suppose que:<\/span><\/p>\n<ul>\n<li><span>le diam\u00e8tre ext\u00e9rieur du rev\u00eatement est:\u00a0<\/span><strong><span>d = 2 xr\u00a0<\/span><\/strong><strong><sub><span>Zr, 1<\/span><\/sub><\/strong><strong><span>\u00a0= 9,3 mm<\/span><\/strong><\/li>\n<li><span>le pas des goupilles de combustible est:\u00a0<\/span><strong><span>p = 13 mm<\/span><\/strong><\/li>\n<li><span>la\u00a0<\/span><a title=\"Rugosit\u00e9 relative du tuyau\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/relative-roughness-of-pipe\/\"><span>rugosit\u00e9 relative<\/span><\/a><span>\u00a0est\u00a0<\/span><strong><span>\u03b5 \/ D = 5 \u00d7 10\u00a0<\/span><\/strong><strong><sup><span>-4<\/span><\/sup><\/strong><\/li>\n<li><span>la\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-density-physics\/\"><span>densit\u00e9<\/span><\/a><span>\u00a0du fluide\u00a0est:\u00a0<\/span><strong><span>\u03c1 = 714 kg \/ m\u00a0<\/span><\/strong><strong><sup><span>3<\/span><\/sup><\/strong><\/li>\n<li><span>la vitesse d&#8217;\u00e9coulement du c\u0153ur est constante et \u00e9gale \u00e0\u00a0<\/span><strong><span>V\u00a0<\/span><\/strong><strong><sub><span>c\u0153ur<\/span><\/sub><\/strong><strong><span>\u00a0= 5 m \/ s<\/span><\/strong><\/li>\n<li><span>la\u00a0<\/span><a title=\"Qu'est-ce que la temp\u00e9rature - Physique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-temperature-physique-definition\/\"><span>temp\u00e9rature<\/span><\/a><span>\u00a0moyenne\u00a0du liquide de refroidissement du r\u00e9acteur est:\u00a0<\/span><strong><span>T en\u00a0<\/span><\/strong><strong><sub><span>vrac<\/span><\/sub><\/strong><strong><span>\u00a0= 296 \u00b0 C<\/span><\/strong><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Calcul du nombre de Reynolds<\/span><\/h2>\n<p><span>Pour calculer le\u00a0<\/span><a title=\"Le num\u00e9ro de Reynold\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\"><span>nombre de Reynolds<\/span><\/a><span>\u00a0, nous devons savoir:<\/span><\/p>\n<ul>\n<li><span>le diam\u00e8tre ext\u00e9rieur du rev\u00eatement est:\u00a0<\/span><strong><span>d = 2 xr\u00a0<\/span><\/strong><strong><sub><span>Zr, 1<\/span><\/sub><\/strong><strong><span>\u00a0= 9,3 mm<\/span><\/strong><span>\u00a0(pour calculer le diam\u00e8tre hydraulique)<\/span><\/li>\n<li><span>le pas des goupilles de combustible est:\u00a0<\/span><strong><span>p = 13 mm<\/span><\/strong><span>\u00a0\u00a0(pour calculer le diam\u00e8tre hydraulique)<\/span><\/li>\n<li><span>la viscosit\u00e9 dynamique de l&#8217;eau satur\u00e9e \u00e0 300 \u00b0 C est:\u00a0<\/span><strong><span>\u03bc = 0,0000859 Ns \/ m\u00a0<\/span><\/strong><strong><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><span>la densit\u00e9 du fluide est:\u00a0<\/span><strong><span>\u03c1 = 714 kg \/ m\u00a0<\/span><\/strong><strong><sup><span>3<\/span><\/sup><\/strong><\/li>\n<\/ul>\n<p><strong><span>Le diam\u00e8tre hydraulique, D\u00a0<\/span><\/strong><strong><sub><span>h<\/span><\/sub><\/strong><span>\u00a0, est un terme couramment utilis\u00e9 pour g\u00e9rer le d\u00e9bit dans\u00a0<\/span><strong><span>des tubes et canaux non circulaires<\/span><\/strong><span>\u00a0.\u00a0Le\u00a0<\/span><strong><span>diam\u00e8tre hydraulique du canal de carburant<\/span><\/strong><span>\u00a0,\u00a0<\/span><em><span>D\u00a0<\/span><\/em><em><sub><span>h<\/span><\/sub><\/em><span>\u00a0, est \u00e9gal \u00e0\u00a0<\/span><strong><span>13,85 mm<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><span>Voir aussi:\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/internal-flow\/hydraulic-diameter-2\/\"><span>Diam\u00e8tre hydraulique<\/span><\/a><\/p>\n<p><span>Le\u00a0<\/span><strong><span>nombre de Reynolds<\/span><\/strong><span>\u00a0\u00e0 l&#8217;int\u00e9rieur du canal de carburant est alors \u00e9gal \u00e0:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20412 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\" alt=\"nombre de reynolds - exemple\" width=\"593\" height=\"78\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\" \/><\/a><\/p>\n<p><span>Cela satisfait pleinement les\u00a0<\/span><a href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-ecoulement-turbulent-definition\/\"><strong><span>conditions turbulentes<\/span><\/strong><\/a><span>\u00a0.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Calcul du coefficient de friction cutan\u00e9e<\/span><\/h2>\n<p><strong><span>Le facteur de frottement<\/span><\/strong><span>\u00a0pour un \u00e9coulement turbulent d\u00e9pend fortement de la\u00a0<\/span><strong><span>rugosit\u00e9 relative.\u00a0<\/span><\/strong><span>Il est d\u00e9termin\u00e9 par l&#8217;\u00e9quation de Colebrook ou peut \u00eatre d\u00e9termin\u00e9 \u00e0 l&#8217;aide du\u00a0<\/span><a title=\"Diagramme Moody\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/moody-diagram\/\"><strong><span>diagramme de Moody<\/span><\/strong><\/a><span>\u00a0.\u00a0Le\u00a0<\/span><strong><span>graphique de Moody<\/span><\/strong><span>\u00a0pour\u00a0<\/span><strong><span>Re = 575 600<\/span><\/strong><span>\u00a0et\u00a0<\/span><strong><span>\u03b5 \/ D = 5 x 10\u00a0<\/span><\/strong><strong><sup><span>-4<\/span><\/sup><\/strong><span>\u00a0renvoie les valeurs suivantes:<\/span><\/p>\n<ul>\n<li><span>le\u00a0<\/span><a title=\"Facteur de friction Darcy\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-facteur-de-friction-de-darcy-definition\/\"><strong><span>facteur de friction de Darcy<\/span><\/strong><\/a><span>\u00a0est \u00e9gal \u00e0\u00a0<\/span><strong><span>f\u00a0<\/span><\/strong><strong><sub><span>D<\/span><\/sub><\/strong><strong><span>\u00a0= 0,017<\/span><\/strong><\/li>\n<li><span>le\u00a0<\/span><a title=\"Facteur de friction de ventilation\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/fanning-friction-factor\/\"><strong><span>facteur de friction Fanning<\/span><\/strong><\/a><span>\u00a0est \u00e9gal \u00e0\u00a0<\/span><strong><span>f\u00a0<\/span><\/strong><strong><sub><span>F<\/span><\/sub><\/strong><strong><span>\u00a0= f\u00a0<\/span><\/strong><strong><sub><span>D<\/span><\/sub><\/strong><strong><span>\u00a0\/ 4 = 0,00425<\/span><\/strong><\/li>\n<\/ul>\n<p><span>Le coefficient de frottement cutan\u00e9 est donc \u00e9gal \u00e0:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/skin-friction-coefficient-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20533 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/skin-friction-coefficient-example.png\" alt=\"coefficient de frottement cutan\u00e9 - exemple\" width=\"377\" height=\"186\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/skin-friction-coefficient-example.png\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Calcul de la force de tra\u00een\u00e9e<\/span><\/h2>\n<p><span>Pour calculer la\u00a0<\/span><strong><span>force de tra\u00een\u00e9e<\/span><\/strong><span>\u00a0, nous devons savoir:<\/span><\/p>\n<ul>\n<li><span>le coefficient de frottement cutan\u00e9, qui est:\u00a0<\/span><strong><span>C\u00a0<\/span><\/strong><strong><sub><span>D, frottement<\/span><\/sub><\/strong><strong><span>\u00a0= 0,00425<\/span><\/strong><\/li>\n<li><span>l&#8217;aire de la surface de la broche, qui est:\u00a0<\/span><strong><span>A = \u03c0.dh = 0,1169 m\u00a0<\/span><\/strong><strong><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><span>la\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-density-physics\/\"><span>densit\u00e9<\/span><\/a><span>\u00a0du fluide\u00a0, qui est:\u00a0<\/span><strong><span>\u03c1 = 714 kg \/ m\u00a0<\/span><\/strong><strong><sup><span>3<\/span><\/sup><\/strong><\/li>\n<li><span>la vitesse d&#8217;\u00e9coulement du c\u0153ur, constante et \u00e9gale \u00e0\u00a0<\/span><strong><span>V\u00a0<\/span><\/strong><strong><sub><span>c\u0153ur<\/span><\/sub><\/strong><strong><span>\u00a0= 5 m \/ s<\/span><\/strong><\/li>\n<\/ul>\n<p><span>\u00c0 partir du\u00a0<\/span><strong><span>coefficient de friction de<\/span><\/strong><span>\u00a0la\u00a0<strong>peau,<\/strong>\u00a0qui est \u00e9gal au\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/fanning-friction-factor\/\"><strong><span>facteur de friction de Fanning,<\/span><\/strong><\/a><span>\u00a0nous pouvons calculer la composante de friction de la\u00a0<\/span><strong><span>force de tra\u00een\u00e9e.\u00a0<\/span><\/strong><span>La force de tra\u00een\u00e9e est donn\u00e9e par:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/drag-force-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20534 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/drag-force-example.png\" alt=\"force de tra\u00een\u00e9e - exemple\" width=\"452\" height=\"72\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/drag-force-example.png\" \/><\/a><\/p>\n<p><span>En supposant qu&#8217;un assemblage combustible puisse avoir, par exemple, 289 goupilles combustibles (assemblage combustible 17&#215;17), la\u00a0<\/span><strong><span>composante frictionnelle<\/span><\/strong><span>\u00a0de la\u00a0<\/span><strong><span>force de tra\u00een\u00e9e<\/span><\/strong><span>\u00a0est alors de l&#8217;ordre de\u00a0<\/span><strong><span>kilonewtons<\/span><\/strong><span>\u00a0.\u00a0De plus, cette force de tra\u00een\u00e9e provient uniquement du frottement de la peau sur le faisceau de combustible.\u00a0Mais l&#8217;assemblage combustible PWR typique contient d&#8217;autres composants, qui influencent l&#8217;hydraulique de l&#8217;assemblage combustible:<\/span><\/p>\n<ul>\n<li><strong><span>Barres de combustible<\/span><\/strong><span>\u00a0.\u00a0Les crayons combustibles contiennent le carburant et les poisons combustibles.<\/span><\/li>\n<li><strong><span>Buse sup\u00e9rieure<\/span><\/strong><span>\u00a0.\u00a0Fournit le support m\u00e9canique de la structure d&#8217;assemblage combustible.<\/span><\/li>\n<li><strong><span>Buse inf\u00e9rieure<\/span><\/strong><span>\u00a0.\u00a0Fournit le support m\u00e9canique de la structure d&#8217;assemblage combustible.<\/span><\/li>\n<li><strong><span>Grille d&#8217;espacement<\/span><\/strong><span>\u00a0.\u00a0Assure un guidage pr\u00e9cis des crayons combustibles.<\/span><\/li>\n<li><strong><span>Guide tube de d\u00e9 \u00e0 coudre<\/span><\/strong><span>\u00a0.\u00a0Tube vide pour barres de contr\u00f4le ou instrumentation in-core.<\/span><\/li>\n<\/ul>\n<p><span>Comme il a \u00e9t\u00e9 \u00e9crit, le deuxi\u00e8me composant de la force de tra\u00een\u00e9e est la tra\u00een\u00e9e de forme.\u00a0<\/span><strong><span>La tra\u00een\u00e9e de forme,<\/span><\/strong><span>\u00a0\u00e9galement appel\u00e9e\u00a0<strong>tra\u00een\u00e9e<\/strong>\u00a0de\u00a0<\/span><strong><span>pression,<\/span><\/strong><span>\u00a0r\u00e9sulte de la\u00a0<\/span><strong><span>forme<\/span><\/strong><span>\u00a0et de la\u00a0<\/span><strong><span>taille<\/span><\/strong><span>\u00a0de l&#8217;objet.\u00a0La\u00a0<\/span><strong><span>tra\u00een\u00e9e de pression<\/span><\/strong><span>\u00a0est proportionnelle \u00e0 la diff\u00e9rence entre les pressions agissant \u00e0 l&#8217;avant et \u00e0 l&#8217;arri\u00e8re du corps immerg\u00e9 et la zone frontale.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Chute de pression &#8211; assemblage de carburant<\/span><\/h2>\n<p><span>En g\u00e9n\u00e9ral, la\u00a0<strong>chute de pression<\/strong>\u00a0totale de\u00a0<\/span><strong><span>l&#8217;assemblage combustible<\/span><\/strong><span>\u00a0est form\u00e9e par la chute de friction du faisceau de combustible (en fonction de\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/relative-roughness-of-pipe\/\">la rugosit\u00e9 relative<\/a>\u00a0des crayons combustibles, du\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\">nombre de reynolds<\/a>\u00a0, du\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/internal-flow\/hydraulic-diameter-2\/\">diam\u00e8tre hydraulique<\/a>\u00a0,\u00a0etc.) et d&#8217;autres chutes de pression des \u00e9l\u00e9ments structurels (buse sup\u00e9rieure et inf\u00e9rieure, grilles d&#8217;espacement ou grilles de m\u00e9lange ).<\/span><\/p>\n<p><span>En g\u00e9n\u00e9ral, il n&#8217;est pas si simple de calculer les chutes de pression dans les assemblages combustibles (en particulier les grilles d&#8217;espacement) et il appartient au\u00a0<\/span><strong><span>savoir-faire<\/span><\/strong><span>\u00a0cl\u00e9\u00a0de certains fabricants de carburants.\u00a0La plupart du temps, les chutes de pression sont mesur\u00e9es dans\u00a0<\/span><strong><span>des boucles hydrauliques exp\u00e9rimentales<\/span><\/strong><span>\u00a0, plut\u00f4t que calcul\u00e9es.<\/span><\/p>\n<p><span>Les ing\u00e9nieurs utilisent le\u00a0<\/span><a title=\"Coefficient de perte de pression - PLC\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/head-loss\/pressure-loss-coefficient-plc\/\"><strong><span>coefficient de perte de pression<\/span><\/strong><\/a><span>\u00a0,\u00a0<\/span><strong><span>PLC<\/span><\/strong><span>\u00a0.\u00a0Il est not\u00e9 K ou\u00a0<\/span><strong><span>\u03be<\/span><\/strong><span>\u00a0\u00a0(prononc\u00e9 \u00abxi\u00bb).\u00a0Ce coefficient caract\u00e9rise\u00a0<\/span><a title=\"Perte de t\u00eate - Perte de pression\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/head-loss\/\"><span>la perte<\/span><\/a><span>\u00a0de charge d&#8217;un certain syst\u00e8me hydraulique ou d&#8217;une partie d&#8217;un syst\u00e8me hydraulique.\u00a0Il peut \u00eatre facilement mesur\u00e9 dans les boucles hydrauliques.\u00a0Le coefficient de perte de charge peut \u00eatre d\u00e9fini ou mesur\u00e9 pour les deux tuyaux droits et en particulier pour\u00a0<\/span><a title=\"Perte de t\u00eate mineure - Pertes locales\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/minor-head-loss-local-losses\/\"><strong><span>les pertes locales (mineures)<\/span><\/strong><\/a><span>\u00a0.<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/PLC-Pressure-loss-coefficient-equations.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20526 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/PLC-Pressure-loss-coefficient-equations.png\" alt=\"PLC - Coefficient de perte de pression - \u00e9quations\" width=\"339\" height=\"375\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/PLC-Pressure-loss-coefficient-equations.png\" \/><\/a><\/p>\n<p><span>En utilisant les donn\u00e9es de l&#8217;exemple mentionn\u00e9 ci-dessus, le\u00a0<\/span><strong><span>coefficient de perte de pression<\/span><\/strong><span>\u00a0(seulement le frottement du tuyau droit) est \u00e9gal \u00e0\u00a0<\/span><strong><span>\u03be = f\u00a0<\/span><sub><span>D<\/span><\/sub><span>\u00a0L \/ D\u00a0<\/span><sub><span>H<\/span><\/sub><span>\u00a0= 4,9<\/span><\/strong><span>\u00a0.\u00a0Mais le coefficient global de perte de pression (y compris les grilles d&#8217;espacement, les buses sup\u00e9rieure et inf\u00e9rieure, etc.) est g\u00e9n\u00e9ralement environ trois fois plus \u00e9lev\u00e9.\u00a0Cet automate (\u00a0<\/span><strong><span>\u03be = 4,9<\/span><\/strong><span>\u00a0) provoque que la chute de pression est de l&#8217;ordre de ( en\u00a0utilisant les entr\u00e9es pr\u00e9c\u00e9dentes)\u00a0<\/span><strong><span>Dp\u00a0<\/span><sub><span>friction<\/span><\/sub><\/strong><span>\u00a0= 4,9 x 714 x 5\u00a0<\/span><sup><span>2<\/span><\/sup><span>\u00a0\/2 =\u00a0<\/span><strong><span>43,7 kPa<\/span><\/strong><span>\u00a0(sans grilles, embouts sup\u00e9rieur et inf\u00e9rieur d&#8217;\u00a0espacement).\u00a0Un PLC r\u00e9el environ trois fois plus \u00e9lev\u00e9 signifie un\u00a0<strong><sub>carburant\u00a0<\/sub><\/strong><\/span><strong><span>\u00a0\u0394p<\/span><\/strong><span>\u00a0environ trois fois plus \u00e9lev\u00e9\u00a0.<\/span><\/p>\n<p><span>La perte de charge globale du r\u00e9acteur,\u00a0<strong><sub>r\u00e9acteur<\/sub><\/strong><\/span><strong><span>\u00a0\u0394p<\/span><\/strong><span>\u00a0, doit comprendre:<\/span><\/p>\n<ul>\n<li><span>descente et fond de r\u00e9acteur<\/span><\/li>\n<li><span>plaque de support inf\u00e9rieure<\/span><\/li>\n<li><span>assemblage de combustible comprenant des grilles d&#8217;espacement, des buses sup\u00e9rieure et inf\u00e9rieure et d&#8217;autres composants structurels &#8211;\u00a0\u00a0<\/span><strong><span>\u0394p\u00a0<\/span><sub><span>fuel<\/span><\/sub><\/strong><\/li>\n<li><span>ensemble de structure de guidage sup\u00e9rieur<\/span><\/li>\n<\/ul>\n<p><span>En cons\u00e9quence, la perte de charge globale du r\u00e9acteur &#8211;\u00a0\u00a0<strong><sub>r\u00e9acteur<\/sub><\/strong><\/span><strong><span>\u00a0\u0394p<\/span><\/strong><span>\u00a0est g\u00e9n\u00e9ralement de l&#8217;ordre de centaines de kPa (disons 300 &#8211; 400 kPa) pour les param\u00e8tres de conception.<\/span><\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Exemple: force de tra\u00een\u00e9e &#8211; coefficient de tra\u00een\u00e9e.\u00a0Calculez la r\u00e9sistance au frottement d&#8217;un seul crayon de combustible dans le c\u0153ur d&#8217;un r\u00e9acteur en fonctionnement normal (d\u00e9bit nominal).\u00a0Probl\u00e8me de solution.\u00a0G\u00e9nie thermique Drag Force en g\u00e9nie nucl\u00e9aire L&#8217;analyse de la\u00a0force de levage hydraulique\u00a0est l&#8217;une des analyses les plus importantes dans la conception d&#8217;un assemblage de combustible et &#8230; <a title=\"Qu&#8217;est-ce que la force de tra\u00een\u00e9e Exemple &#8211; Coefficient de tra\u00een\u00e9e &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-force-de-trainee-exemple-coefficient-de-trainee-definition\/\" aria-label=\"En savoir plus sur Qu&#8217;est-ce que la force de tra\u00een\u00e9e Exemple &#8211; Coefficient de tra\u00een\u00e9e &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Qu&#039;est-ce que la force de tra\u00een\u00e9e Exemple - Coefficient de tra\u00een\u00e9e - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"Exemple: force de tra\u00een\u00e9e - coefficient de tra\u00een\u00e9e. 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Calculez la r\u00e9sistance au frottement d&#039;un seul crayon de combustible dans le c\u0153ur d&#039;un r\u00e9acteur en fonctionnement normal (d\u00e9bit nominal). Probl\u00e8me de solution. 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Calculez la r\\u00e9sistance au frottement d'un seul crayon de combustible dans le c\\u0153ur d'un r\\u00e9acteur en fonctionnement normal (d\\u00e9bit nominal). Probl\\u00e8me de solution. 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