{"id":44088,"date":"2019-10-14T18:31:48","date_gmt":"2019-10-14T17:31:48","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quest-ce-que-lequation-de-dittus-boelter-definition\/"},"modified":"2020-02-17T10:27:53","modified_gmt":"2020-02-17T09:27:53","slug":"quest-ce-que-lequation-de-dittus-boelter-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-dittus-boelter-definition\/","title":{"rendered":"Qu&#8217;est-ce que l&#8217;\u00e9quation de Dittus-Boelter &#8211; D\u00e9finition"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Le nombre de Nusselt local peut \u00eatre obtenu \u00e0 partir de la c\u00e9l\u00e8bre \u00e9quation de Dittus-Boelter.\u00a0L&#8217;\u00e9quation de Dittus ?? Boelter est facile \u00e0 r\u00e9soudre mais est moins pr\u00e9cise en cas de diff\u00e9rence de temp\u00e9rature importante<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>\u00c9quation de Dittus-Boelter<\/h2>\n<p>Pour\u00a0<a title=\"\u00c9coulement turbulent\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-ecoulement-turbulent-definition\/\">un \u00e9coulement turbulent<\/a>\u00a0compl\u00e8tement d\u00e9velopp\u00e9 (hydrodynamiquement et thermiquement)\u00a0dans un tube circulaire lisse, le\u00a0<a title=\"Quel est le nombre de Nusselt\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/heat-transfer\/introduction-to-heat-transfer\/characteristic-numbers\/what-is-nusselt-number\/\">nombre de Nusselt<\/a>\u00a0local\u00a0peut \u00eatre obtenu \u00e0 partir de la c\u00e9l\u00e8bre\u00a0<strong>\u00e9quation de Dittus-Boelter<\/strong>\u00a0.\u00a0L&#8217;\u00a0<strong>\u00e9quation de Dittus ?? Boelter<\/strong>\u00a0est facile \u00e0 r\u00e9soudre, mais est moins pr\u00e9cise en cas de diff\u00e9rence de temp\u00e9rature importante dans le\u00a0<a title=\"Dynamique des fluides\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/\">fluide<\/a>\u00a0et moins pr\u00e9cise pour les tubes bruts (nombreuses applications commerciales), car elle est con\u00e7ue pour les tubes lisses.<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Dittus-Boelter-Equation-Formula.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20409 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Dittus-Boelter-Equation-Formula.png\" alt=\"\u00c9quation de Dittus-Boelter - Formule\" width=\"556\" height=\"278\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Dittus-Boelter-Equation-Formula.png\" \/><\/a><\/p>\n<p>La\u00a0<strong>corr\u00e9lation de Dittus-Boelter<\/strong>\u00a0peut \u00eatre utilis\u00e9e pour des diff\u00e9rences de temp\u00e9rature faibles \u00e0 mod\u00e9r\u00e9es, T\u00a0<sub>mur<\/sub>\u00a0&#8211; T\u00a0<sub>moy<\/sub>\u00a0, avec toutes les propri\u00e9t\u00e9s \u00e9valu\u00e9es \u00e0 une temp\u00e9rature moyenne T\u00a0<sub>moy<\/sub>\u00a0.<\/p>\n<p>Pour les \u00e9coulements caract\u00e9ris\u00e9s par de grandes variations de propri\u00e9t\u00e9s, les corrections (par exemple, un facteur de correction de la viscosit\u00e9\u00a0<strong>\u00b5 \/ \u00b5\u00a0<\/strong><strong><sub>mur<\/sub><\/strong>\u00a0) doivent \u00eatre prises en compte, par exemple, comme le recommandent Sieder et Tate.<\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>\u00c9quation de Sieder-Tate<\/h2>\n<p>Lorsque la diff\u00e9rence de temp\u00e9rature entre la surface et le fluide est importante, il peut \u00eatre n\u00e9cessaire de prendre en compte la variation de la viscosit\u00e9 avec la temp\u00e9rature.\u00a0Par cons\u00e9quent,\u00a0<strong>Sieder<\/strong>\u00a0et\u00a0<strong>Tate<\/strong>\u00a0(1936) ont\u00a0propos\u00e9\u00a0une forme modifi\u00e9e de l&#8217;\u00a0<strong>\u00e9quation<\/strong>\u00a0de\u00a0<strong>Dittus-Boelter<\/strong>\u00a0.<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Sieder-Tate-Equation-correlation.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20466 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Sieder-Tate-Equation-correlation.png\" alt=\"\u00c9quation de Sieder-Tate - corr\u00e9lation\" width=\"558\" height=\"271\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Sieder-Tate-Equation-correlation.png\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<h2><span>\u00c9quation de Gnielinski<\/span><\/h2>\n<p><span>Bien que les\u00a0<\/span><strong><span>\u00e9quations Dittus-Boelter<\/span><\/strong><span>\u00a0et\u00a0<\/span><strong><span>Sieder-Tate<\/span><\/strong><span>\u00a0soient faciles \u00e0 appliquer et soient certainement satisfaisantes aux fins du pr\u00e9sent article, des erreurs aussi importantes que 25% peuvent r\u00e9sulter de leur utilisation.\u00a0Ces erreurs peuvent \u00eatre r\u00e9duites gr\u00e2ce \u00e0 l&#8217;utilisation de corr\u00e9lations plus r\u00e9centes, mais g\u00e9n\u00e9ralement plus complexes, telles que la\u00a0<\/span><strong><span>corr\u00e9lation de Gnielinski<\/span><\/strong><span>\u00a0.\u00a0Cette \u00e9quation est valable pour les tubes sur une large gamme de nombres de Reynolds, y compris la r\u00e9gion de transition.<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Gnielinski-equation-correlation.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20470 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Gnielinski-equation-correlation.png\" alt=\"\u00c9quation de Gnielinski - corr\u00e9lation\" width=\"600\" height=\"288\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Gnielinski-equation-correlation.png\" \/><\/a><\/p>\n<p><strong><a title=\"Facteur de friction Darcy\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-facteur-de-friction-de-darcy-definition\/\"><span>Le facteur de frottement de Darcy<\/span><\/a><span>\u00a0, f,<\/span><\/strong><span>\u00a0\u00a0est une quantit\u00e9 sans dimension utilis\u00e9e dans l&#8217;<\/span><a title=\"\u00c9quation de Darcy-Weisbach\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/darcy-weisbach-equation\/\"><span>\u00a0\u00e9quation de Darcy \u2013 Weisbach<\/span><\/a><span>\u00a0, pour la description des<\/span><a title=\"Perte de t\u00eate majeure - Perte par friction\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/\"><span>\u00a0pertes par frottement<\/span><\/a><span>\u00a0dans les tuyaux ou les conduits ainsi que pour l&#8217;\u00e9coulement \u00e0 canal ouvert.\u00a0C&#8217;est ce qu&#8217;on appelle \u00e9galement le\u00a0<\/span><strong><span>\u00a0facteur de friction Darcy \u2013 Weisbach<\/span><\/strong><span>\u00a0, le\u00a0<\/span><strong><span>\u00a0coefficient de r\u00e9sistance<\/span><\/strong><span>\u00a0ou simplement le<\/span><strong><span>\u00a0\u00a0facteur de friction<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><strong><span>Tubes \u00e0 paroi grossi\u00e8re<\/span><\/strong><\/p>\n<p><span>On note \u00e9galement que toutes ces \u00e9quations concernent des tubes lisses.\u00a0Pour un \u00e9coulement turbulent dans des tubes rugueux, le coefficient de transfert de chaleur augmente avec la\u00a0<\/span><a title=\"Rugosit\u00e9 relative du tuyau\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/relative-roughness-of-pipe\/\"><span>rugosit\u00e9 de la paroi<\/span><\/a><span>\u00a0.\u00a0\u00c0 mesure que le\u00a0<\/span><a title=\"Le num\u00e9ro de Reynold\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\"><span>nombre de Reynolds<\/span><\/a><span>\u00a0augmente, la sous-couche visqueuse devient plus mince et plus petite.\u00a0\u00c0 un nombre de Reynolds tr\u00e8s \u00e9lev\u00e9, la sous-couche visqueuse devient si mince que la rugosit\u00e9 de surface fait saillie dans l&#8217;\u00e9coulement.\u00a0Les pertes par frottement dans ce cas sont produites dans le flux principal principalement par les \u00e9l\u00e9ments de rugosit\u00e9 saillants, et la contribution de la sous-couche laminaire est n\u00e9gligeable.<\/span><\/p>\n<p><span>R\u00e9f\u00e9rence sp\u00e9ciale: A Heat Transfer Textbook, John H. Lienhard IV et John H. Lienhard V. Phlogiston Press, 2012.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Exemple &#8211; \u00c9quation Dittus-Boelter &#8211; Temp\u00e9rature de surface du rev\u00eatement<\/span><\/h2>\n<p><strong><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Convection-Convective-Heat-Transfer-example.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-20406 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Convection-Convective-Heat-Transfer-example-275x300.png\" alt=\"Convection - Transfert de chaleur par convection\" width=\"275\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Convection-Convective-Heat-Transfer-example-275x300.png\" \/><\/a><span>Le rev\u00eatement<\/span><\/strong><span>\u00a0est la couche externe des crayons de combustible, se trouvant entre le\u00a0<\/span><strong><span>liquide de refroidissement<\/span><\/strong><span>\u00a0du\u00a0<strong>r\u00e9acteur<\/strong>\u00a0et le\u00a0<\/span><a title=\"Combustible nucl\u00e9aire\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/nuclear-fuel\/\"><strong><span>combustible nucl\u00e9aire<\/span><\/strong>\u00a0<\/a><span>(c&#8217;est-\u00e0-dire\u00a0<\/span><strong><span>les pastilles de combustible<\/span><\/strong><span>\u00a0).\u00a0Il est fait d&#8217;un mat\u00e9riau r\u00e9sistant \u00e0 la corrosion avec une faible section d&#8217;absorption pour\u00a0<\/span><a title=\"Neutron thermique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power\/reactor-physics\/atomic-nuclear-physics\/fundamental-particles\/neutron\/thermal-neutron\/\"><span>les neutrons thermiques<\/span><\/a><span>\u00a0, g\u00e9n\u00e9ralement en\u00a0<\/span><strong><span>alliage de zirconium<\/span><\/strong><span>\u00a0.\u00a0<\/span><strong><span>Le rev\u00eatement<\/span><\/strong><span>\u00a0emp\u00eache les produits de fission radioactifs de s&#8217;\u00e9chapper de la matrice de combustible dans le liquide de refroidissement du r\u00e9acteur et de le contaminer.\u00a0Le rev\u00eatement constitue l&#8217;un des obstacles \u00e0 l&#8217;\u00a0approche de\u00a0\u00ab\u00a0<\/span><strong><span>d\u00e9fense en profondeur<\/span><\/strong><span>\u00a0\u00bb, donc sa\u00a0<\/span><strong><span>refroidissabilit\u00e9<\/span><\/strong><span>\u00a0est l&#8217;un des aspects cl\u00e9s de la s\u00e9curit\u00e9.<\/span><\/p>\n<p><span>Consid\u00e9rons la gaine de combustible du rayon int\u00e9rieur\u00a0<\/span><strong><span>r\u00a0<\/span><\/strong><strong><sub><span>Zr, 2<\/span><\/sub><\/strong><strong><span>\u00a0= 0,408 cm<\/span><\/strong><span>\u00a0et du rayon ext\u00e9rieur\u00a0<\/span><strong><span>r\u00a0<\/span><\/strong><strong><sub><span>Zr, 1<\/span><\/sub><\/strong><strong><span>\u00a0= 0,465 cm<\/span><\/strong><span>\u00a0.\u00a0Par rapport \u00e0 la pastille de combustible, il n&#8217;y a presque pas de g\u00e9n\u00e9ration de chaleur dans la gaine de combustible (la gaine est\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-power\/fission\/energy-release-from-fission\/\"><span>l\u00e9g\u00e8rement chauff\u00e9e par rayonnement<\/span><\/a><span>\u00a0).\u00a0Toute la chaleur g\u00e9n\u00e9r\u00e9e dans le carburant doit \u00eatre transf\u00e9r\u00e9e par\u00a0<\/span><a title=\"Conduction thermique - Conduction thermique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-conduction-thermique-conduction-thermique-definition\/\"><strong><span>conduction \u00e0<\/span><\/strong><\/a><span>\u00a0travers le rev\u00eatement et, par cons\u00e9quent, la surface int\u00e9rieure est plus chaude que la surface ext\u00e9rieure.<\/span><\/p>\n<p><span>Suppose que:<\/span><\/p>\n<ul>\n<li><span>le diam\u00e8tre ext\u00e9rieur du rev\u00eatement est:\u00a0<\/span><strong><span>d = 2 xr\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><span>\u00a0= 9,3 mm<\/span><\/strong><\/li>\n<li><span>le pas des goupilles de combustible est:\u00a0<\/span><strong><span>p = 13 mm<\/span><\/strong><\/li>\n<li><span>la\u00a0<\/span><a title=\"Conductivit\u00e9 thermique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-conductivite-thermique-definition\/\"><span>conductivit\u00e9 thermique<\/span><\/a><span>\u00a0de l&#8217;\u00a0<\/span><a title=\"Liquide satur\u00e9 et sous-refroidi\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/materials-nuclear-engineering\/properties-steam-what-is-steam\/saturated-and-subcooled-liquid\/\"><span>eau satur\u00e9e<\/span><\/a><span>\u00a0\u00e0 300 \u00b0 C est:\u00a0<\/span><strong><span>k\u00a0<\/span><\/strong><strong><sub><span>H2O<\/span><\/sub><\/strong><strong><span>\u00a0= 0,545 W \/ mK<\/span><\/strong><\/li>\n<li><span>la viscosit\u00e9 dynamique de l&#8217;eau satur\u00e9e \u00e0 300 \u00b0 C est:\u00a0<\/span><strong><span>\u03bc = 0,0000859 Ns \/ m\u00a0<\/span><\/strong><strong><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><span>la\u00a0<\/span><a title=\"Qu'est-ce que la densit\u00e9 - Physique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-density-physics\/\"><span>densit\u00e9<\/span><\/a><span>\u00a0du fluide\u00a0est:\u00a0<\/span><strong><span>\u03c1 = 714 kg \/ m\u00a0<\/span><\/strong><strong><sup><span>3<\/span><\/sup><\/strong><\/li>\n<li><span>la\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/heat-capacity\/\"><strong><span>chaleur sp\u00e9cifique<\/span><\/strong><\/a><span>\u00a0est:\u00a0<\/span><strong><span>c\u00a0<\/span><\/strong><strong><sub><span>p<\/span><\/sub><\/strong><strong><span>\u00a0= 5,65 kJ \/ kg.K<\/span><\/strong><\/li>\n<li><span>la vitesse d&#8217;\u00e9coulement du c\u0153ur est constante et \u00e9gale \u00e0\u00a0<\/span><strong><span>V\u00a0<\/span><\/strong><strong><sub><span>c\u0153ur<\/span><\/sub><\/strong><strong><span>\u00a0= 5 m \/ s<\/span><\/strong><\/li>\n<li><span>la temp\u00e9rature du liquide de refroidissement du r\u00e9acteur \u00e0 cette coordonn\u00e9e axiale est:\u00a0<\/span><strong><span>T en\u00a0<\/span><\/strong><strong><sub><span>vrac<\/span><\/sub><\/strong><strong><span>\u00a0= 296 \u00b0 C<\/span><\/strong><\/li>\n<li><span>le taux de chaleur lin\u00e9aire du combustible est\u00a0<\/span><strong><span>q\u00a0<\/span><\/strong><strong><sub><span>L<\/span><\/sub><\/strong><strong><span>\u00a0= 300 W \/ cm<\/span><\/strong><span>\u00a0(F\u00a0<\/span><sub><span>Q<\/span><\/sub><span>\u00a0\u2248 2.0) et donc le taux de chaleur volum\u00e9trique est q\u00a0<\/span><sub><span>V<\/span><\/sub><span>\u00a0= 597 x 10\u00a0<\/span><sup><span>6<\/span><\/sup><span>\u00a0W \/ m\u00a0<\/span><sup><span>3<\/span><\/sup><\/li>\n<\/ul>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-20407 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel-254x300.png\" alt=\"Diam\u00e8tre hydraulique - Canal de carburant\" width=\"254\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel-254x300.png\" \/><\/a><span>Calculez le nombre de\u00a0<\/span><a title=\"Qu'est-ce que le num\u00e9ro Prandtl\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/heat-transfer\/introduction-to-heat-transfer\/characteristic-numbers\/what-is-prandtl-number\/\"><span>Prandtl<\/span><\/a><span>\u00a0,\u00a0<\/span><a title=\"Le num\u00e9ro de Reynold\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\"><span>Reynolds<\/span><\/a><span>\u00a0et Nusselt pour ce r\u00e9gime d&#8217;\u00e9coulement (\u00e9coulement turbulent forc\u00e9 interne) \u00e0 l&#8217;int\u00e9rieur du r\u00e9seau rectangulaire de combustible (canal de combustible), puis calculez le\u00a0<\/span><strong><span>coefficient de transfert de chaleur<\/span><\/strong><span>\u00a0et enfin la\u00a0<\/span><strong><span>temp\u00e9rature de surface de<\/span><\/strong><span>\u00a0la\u00a0<strong>gaine<\/strong>\u00a0,\u00a0<\/span><strong><span>T\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><\/strong><span>\u00a0.<\/span><\/p>\n<p><span>Pour calculer la\u00a0<\/span><strong><span>temp\u00e9rature de surface de<\/span><\/strong><span>\u00a0la\u00a0<strong>gaine<\/strong>\u00a0, nous devons calculer le nombre de\u00a0<\/span><strong><span>Prandtl<\/span><\/strong><span>\u00a0,\u00a0<\/span><strong><span>Reynolds<\/span><\/strong><span>\u00a0et\u00a0<\/span><strong><span>Nusselt<\/span><\/strong><span>\u00a0, car le transfert de chaleur pour ce r\u00e9gime d&#8217;\u00e9coulement peut \u00eatre d\u00e9crit par l&#8217;\u00a0<\/span><strong><span>\u00e9quation de Dittus-Boelter<\/span><\/strong><span>\u00a0, qui est:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Dittus-Boelter-Equation-Formula.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20409 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Dittus-Boelter-Equation-Formula.png\" alt=\"\u00c9quation Dittus-Boelter - Formule\" width=\"556\" height=\"278\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Dittus-Boelter-Equation-Formula.png\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Calcul du nombre de Prandtl<\/span><\/h2>\n<p><span>Pour calculer le\u00a0<\/span><a title=\"Qu'est-ce que le num\u00e9ro Prandtl\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/heat-transfer\/introduction-to-heat-transfer\/characteristic-numbers\/what-is-prandtl-number\/\"><span>nombre de Prandtl<\/span><\/a><span>\u00a0, nous devons savoir:<\/span><\/p>\n<ul>\n<li><span>la conductivit\u00e9 thermique de l&#8217;eau satur\u00e9e \u00e0 300 \u00b0 C est:\u00a0<\/span><strong><span>k\u00a0<\/span><\/strong><strong><sub><span>H2O<\/span><\/sub><\/strong><strong><span>\u00a0= 0,545 W \/ mK<\/span><\/strong><\/li>\n<li><span>la viscosit\u00e9 dynamique de l&#8217;eau satur\u00e9e \u00e0 300 \u00b0 C est:\u00a0<\/span><strong><span>\u03bc = 0,0000859 Ns \/ m\u00a0<\/span><\/strong><strong><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><span>la\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/heat-capacity\/\"><strong><span>chaleur sp\u00e9cifique<\/span><\/strong><\/a><span>\u00a0est:\u00a0<\/span><strong><span>c\u00a0<\/span><\/strong><strong><sub><span>p<\/span><\/sub><\/strong><strong><span>\u00a0= 5,65 kJ \/ kg.K<\/span><\/strong><\/li>\n<\/ul>\n<p><span>Notez que tous ces param\u00e8tres diff\u00e8rent de mani\u00e8re significative pour l&#8217;eau \u00e0 300 \u00b0 C de ceux \u00e0 20 \u00b0 C.\u00a0Le nombre de Prandtl pour l&#8217;\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/materials-nuclear-engineering\/properties-of-water\/\"><span>eau<\/span><\/a><span>\u00a0\u00e0 20 \u00b0 C est d&#8217;environ\u00a0<\/span><strong><span>6,91.\u00a0<\/span><\/strong><span>Le nombre de Prandtl pour le liquide de refroidissement du r\u00e9acteur \u00e0 300 \u00b0 C est alors:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/prandtl-number-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20411 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/prandtl-number-example.png\" alt=\"num\u00e9ro prandtl - exemple\" width=\"469\" height=\"80\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/prandtl-number-example.png\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Calcul du nombre de Reynolds<\/span><\/h2>\n<p><span>Pour calculer le nombre de Reynolds, nous devons savoir:<\/span><\/p>\n<ul>\n<li><span>le diam\u00e8tre ext\u00e9rieur du rev\u00eatement est:\u00a0<\/span><strong><span>d = 2 xr\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><span>\u00a0= 9,3 mm<\/span><\/strong><span>\u00a0(pour calculer le diam\u00e8tre hydraulique)<\/span><\/li>\n<li><span>le pas des goupilles de combustible est:\u00a0<\/span><strong><span>p = 13 mm<\/span><\/strong><span>\u00a0\u00a0(pour calculer le diam\u00e8tre hydraulique)<\/span><\/li>\n<li><span>la viscosit\u00e9 dynamique de l&#8217;eau satur\u00e9e \u00e0 300 \u00b0 C est:\u00a0<\/span><strong><span>\u03bc = 0,0000859 Ns \/ m\u00a0<\/span><\/strong><strong><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><span>la densit\u00e9 du fluide est:\u00a0<\/span><strong><span>\u03c1 = 714 kg \/ m\u00a0<\/span><\/strong><strong><sup><span>3<\/span><\/sup><\/strong><\/li>\n<\/ul>\n<p><strong><span>Le diam\u00e8tre hydraulique, D\u00a0<\/span><\/strong><strong><sub><span>h<\/span><\/sub><\/strong><span>\u00a0, est un terme couramment utilis\u00e9 pour g\u00e9rer le d\u00e9bit dans\u00a0<\/span><strong><span>des tubes et canaux non circulaires<\/span><\/strong><span>\u00a0.\u00a0Le\u00a0<\/span><strong><span>diam\u00e8tre hydraulique du canal de carburant<\/span><\/strong><span>\u00a0,\u00a0<\/span><em><span>D\u00a0<\/span><\/em><em><sub><span>h<\/span><\/sub><\/em><span>\u00a0, est \u00e9gal \u00e0 13,85 mm.<\/span><\/p>\n<p><span>Voir aussi:\u00a0<\/span><a title=\"Diam\u00e8tre hydraulique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/internal-flow\/hydraulic-diameter-2\/\"><span>Diam\u00e8tre hydraulique<\/span><\/a><\/p>\n<p><span>Le\u00a0<\/span><strong><span>nombre de Reynolds<\/span><\/strong><span>\u00a0\u00e0 l&#8217;int\u00e9rieur du canal de carburant est alors \u00e9gal \u00e0:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20412 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\" alt=\"nombre de reynolds - exemple\" width=\"593\" height=\"78\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\" \/><\/a><\/p>\n<p><span>Cela satisfait pleinement les\u00a0<\/span><a title=\"\u00c9coulement turbulent\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-ecoulement-turbulent-definition\/\"><strong><span>conditions turbulentes<\/span><\/strong><\/a><span>\u00a0.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Calcul du nombre de Nusselt \u00e0 l&#8217;aide de l&#8217;\u00e9quation de Dittus-Boelter<\/span><\/h2>\n<p><span>Pour un \u00e9coulement turbulent pleinement d\u00e9velopp\u00e9 (hydrodynamiquement et thermiquement) dans un tube circulaire lisse, le\u00a0<\/span><strong><span>nombre de Nusselt<\/span><\/strong><span>\u00a0local\u00a0peut \u00eatre obtenu \u00e0 partir de l&#8217;\u00a0<\/span><strong><span>\u00e9quation<\/span><\/strong><span>\u00a0bien connue de\u00a0<strong>Dittus ?? Boelter<\/strong>\u00a0.<\/span><\/p>\n<p><span>Pour calculer le\u00a0<\/span><strong><span>nombre de Nusselt<\/span><\/strong><span>\u00a0, nous devons savoir:<\/span><\/p>\n<ul>\n<li><span>le\u00a0<\/span><a title=\"Le num\u00e9ro de Reynold\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\"><span>nombre de Reynolds<\/span><\/a><span>\u00a0, qui est\u00a0<\/span><strong><span>Re\u00a0<\/span><sub><span>Dh<\/span><\/sub><span>\u00a0= 575600<\/span><\/strong><\/li>\n<li><span>le\u00a0<\/span><a title=\"Qu'est-ce que le num\u00e9ro Prandtl\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/heat-transfer\/introduction-to-heat-transfer\/characteristic-numbers\/what-is-prandtl-number\/\"><span>nombre de Prandtl<\/span><\/a><span>\u00a0, qui est\u00a0<\/span><strong><span>Pr = 0,89<\/span><\/strong><\/li>\n<\/ul>\n<p><span>Le\u00a0<\/span><strong><span>nombre de Nusselt<\/span><\/strong><span>\u00a0pour la convection forc\u00e9e \u00e0 l&#8217;int\u00e9rieur du canal de carburant est alors \u00e9gal \u00e0:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/nusselt-number-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20413 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/nusselt-number-example.png\" alt=\"num\u00e9ro nusselt - exemple\" width=\"387\" height=\"58\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/nusselt-number-example.png\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Calcul du coefficient de transfert de chaleur et de la temp\u00e9rature de surface du rev\u00eatement, T\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><\/h2>\n<p><span>Une connaissance d\u00e9taill\u00e9e de la g\u00e9om\u00e9trie, des param\u00e8tres des fluides, du rayon ext\u00e9rieur du rev\u00eatement, du taux de chaleur lin\u00e9aire, du coefficient de transfert de chaleur par convection nous permet de calculer la diff\u00e9rence de temp\u00e9rature\u00a0<\/span><strong><span>\u2206T<\/span><\/strong><span>\u00a0entre le liquide de refroidissement (T en\u00a0<\/span><sub><span>vrac<\/span><\/sub><span>\u00a0) et la surface du rev\u00eatement (T\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><span>\u00a0).<\/span><\/p>\n<p><span>Pour calculer la temp\u00e9rature de surface de la gaine, il faut savoir:<\/span><\/p>\n<ul>\n<li><span>le diam\u00e8tre ext\u00e9rieur du rev\u00eatement est: d = 2 x\u00a0<\/span><strong><span>r\u00a0<\/span><\/strong><strong><sub><span>Zr, 1<\/span><\/sub><\/strong><strong><span>\u00a0= 9,3 mm<\/span><\/strong><\/li>\n<li><span>le nombre de Nusselt, qui est\u00a0<\/span><strong><span>Nu\u00a0<\/span><\/strong><strong><sub><span>Dh<\/span><\/sub><\/strong><strong><span>\u00a0= 890<\/span><\/strong><\/li>\n<li><span>le diam\u00e8tre hydraulique du canal de carburant est:\u00a0<\/span><strong><em><span>D\u00a0<\/span><\/em><\/strong><strong><em><sub><span>h<\/span><\/sub><\/em><\/strong><strong><span>\u00a0= 13,85 mm<\/span><\/strong><\/li>\n<li><span>la conductivit\u00e9 thermique du liquide de refroidissement du r\u00e9acteur (300 \u00b0 C) est:\u00a0<\/span><strong><span>k\u00a0<\/span><\/strong><strong><sub><span>H2O<\/span><\/sub><\/strong><strong><span>\u00a0= 0,545 W \/ mK<\/span><\/strong><\/li>\n<li><span>la temp\u00e9rature en vrac du liquide de refroidissement du r\u00e9acteur \u00e0 cette coordonn\u00e9e axiale est:\u00a0<\/span><strong><span>T en\u00a0<\/span><\/strong><strong><sub><span>vrac<\/span><\/sub><\/strong><strong><span>\u00a0= 296 \u00b0 C<\/span><\/strong><\/li>\n<li><span>le taux de chaleur lin\u00e9aire du combustible est:\u00a0<\/span><strong><span>q\u00a0<\/span><\/strong><strong><sub><span>L<\/span><\/sub><\/strong><strong><span>\u00a0= 300 W \/ cm<\/span><\/strong><span>\u00a0(F\u00a0<\/span><sub><span>Q<\/span><\/sub><span>\u00a0\u2248 2.0)<\/span><\/li>\n<\/ul>\n<p><span>Le coefficient de transfert de chaleur par convection,\u00a0<\/span><strong><span>h<\/span><\/strong><span>\u00a0, est donn\u00e9 directement par la d\u00e9finition du nombre de Nusselt:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/convective-heat-transfer-coefficient-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20410 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/convective-heat-transfer-coefficient-example.png\" alt=\"coefficient de transfert de chaleur par convection - exemple\" width=\"619\" height=\"92\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/convective-heat-transfer-coefficient-example.png\" \/><\/a><\/p>\n<p><span>Enfin, nous pouvons calculer la temp\u00e9rature de surface de la gaine (T\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><span>\u00a0) simplement en utilisant la\u00a0<\/span><strong><span>loi de Newton du refroidissement<\/span><\/strong><span>\u00a0:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Newton-law-of-cooling-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20408 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Newton-law-of-cooling-example.png\" alt=\"Loi de Newton du refroidissement - exemple\" width=\"377\" height=\"369\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Newton-law-of-cooling-example.png\" \/><\/a><\/p>\n<p><span>Pour les REP en fonctionnement normal, il y a une\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/materials-nuclear-engineering\/properties-steam-what-is-steam\/saturated-and-subcooled-liquid\/\"><span>eau liquide comprim\u00e9e \u00e0 l&#8217;<\/span><\/a><span>\u00a0int\u00e9rieur du c\u0153ur du r\u00e9acteur, des boucles et des g\u00e9n\u00e9rateurs de vapeur.\u00a0La pression est maintenue \u00e0 environ\u00a0<\/span><strong><span>16 MPa<\/span><\/strong><span>\u00a0.\u00a0\u00c0 cette pression, l&#8217;eau bout \u00e0 environ\u00a0<\/span><strong><span>350 \u00b0 C<\/span><\/strong><span>\u00a0(662 \u00b0 F).\u00a0Comme on peut le voir, la temp\u00e9rature de surface T\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><span>\u00a0= 325 \u00b0 C garantit que m\u00eame une \u00e9bullition sous-refroidie ne se produit pas.\u00a0Notez que l&#8217;\u00e9bullition sous-refroidie n\u00e9cessite T\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><span>\u00a0= T\u00a0<\/span><sub><span>sat<\/span><\/sub><span>\u00a0.\u00a0\u00c9tant donn\u00e9 que les temp\u00e9ratures d&#8217;entr\u00e9e de l&#8217;eau sont g\u00e9n\u00e9ralement d&#8217;environ\u00a0<\/span><strong><span>290 \u00b0 C<\/span><\/strong><span>(554 \u00b0 F), il est \u00e9vident que cet exemple correspond \u00e0 la partie inf\u00e9rieure du noyau.\u00a0Aux altitudes plus \u00e9lev\u00e9es du c\u0153ur, la temp\u00e9rature globale peut atteindre jusqu&#8217;\u00e0 330 \u00b0 C.\u00a0La diff\u00e9rence de temp\u00e9rature de 29 \u00b0 C peut entra\u00eener une \u00e9bullition sous-refroidie (330 \u00b0 C + 29 \u00b0 C&gt; 350 \u00b0 C).\u00a0D&#8217;autre part, l&#8217;\u00a0<\/span><strong><span>\u00e9bullition nucl\u00e9\u00e9e<\/span><\/strong><span>\u00a0\u00e0 la surface perturbe efficacement la couche stagnante et, par cons\u00e9quent, l&#8217;\u00e9bullition nucl\u00e9\u00e9e augmente consid\u00e9rablement la capacit\u00e9 d&#8217;une surface \u00e0 transf\u00e9rer l&#8217;\u00a0<\/span><a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/internal-energy-thermal-energy\/\"><span>\u00e9nergie thermique<\/span><\/a><span>\u00a0au fluide en vrac.\u00a0En cons\u00e9quence, le coefficient de transfert de chaleur convectif augmente consid\u00e9rablement et donc \u00e0 des altitudes plus \u00e9lev\u00e9es, la diff\u00e9rence de temp\u00e9rature (T\u00a0<\/span><sub><span>Zr, 1<\/span><\/sub><span>\u00a0&#8211; T en\u00a0<\/span><sub><span>vrac<\/span><\/sub><span>\u00a0) diminue consid\u00e9rablement.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Le nombre de Nusselt local peut \u00eatre obtenu \u00e0 partir de la c\u00e9l\u00e8bre \u00e9quation de Dittus-Boelter.\u00a0L&#8217;\u00e9quation de Dittus ?? Boelter est facile \u00e0 r\u00e9soudre mais est moins pr\u00e9cise en cas de diff\u00e9rence de temp\u00e9rature importante \u00c9quation de Dittus-Boelter Pour\u00a0un \u00e9coulement turbulent\u00a0compl\u00e8tement d\u00e9velopp\u00e9 (hydrodynamiquement et thermiquement)\u00a0dans un tube circulaire lisse, le\u00a0nombre de Nusselt\u00a0local\u00a0peut \u00eatre obtenu \u00e0 &#8230; <a title=\"Qu&#8217;est-ce que l&#8217;\u00e9quation de Dittus-Boelter &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-dittus-boelter-definition\/\" aria-label=\"En savoir plus sur Qu&#8217;est-ce que l&#8217;\u00e9quation de Dittus-Boelter &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Qu&#039;est-ce que l&#039;\u00e9quation de Dittus-Boelter - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"Le nombre de Nusselt local peut \u00eatre obtenu \u00e0 partir de la c\u00e9l\u00e8bre \u00e9quation de Dittus-Boelter. L&#039;\u00e9quation de Dittus \u2013 Boelter est facile \u00e0 r\u00e9soudre, mais est moins pr\u00e9cise en cas de diff\u00e9rence de temp\u00e9rature importante\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-dittus-boelter-definition\/\" \/>\n<meta property=\"og:locale\" content=\"fr_FR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Qu&#039;est-ce que l&#039;\u00e9quation de Dittus-Boelter - D\u00e9finition\" \/>\n<meta property=\"og:description\" content=\"Le nombre de Nusselt local peut \u00eatre obtenu \u00e0 partir de la c\u00e9l\u00e8bre \u00e9quation de Dittus-Boelter. L&#039;\u00e9quation de Dittus \u2013 Boelter est facile \u00e0 r\u00e9soudre, mais est moins pr\u00e9cise en cas de diff\u00e9rence de temp\u00e9rature importante\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-dittus-boelter-definition\/\" \/>\n<meta property=\"og:site_name\" content=\"Thermal Engineering\" \/>\n<meta property=\"article:published_time\" content=\"2019-10-14T17:31:48+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2020-02-17T09:27:53+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Dittus-Boelter-Equation-Formula.png\" \/>\n<meta name=\"twitter:card\" content=\"summary\" \/>\n<meta name=\"twitter:label1\" content=\"\u00c9crit par\">\n\t<meta name=\"twitter:data1\" content=\"Nick Connor\">\n\t<meta name=\"twitter:label2\" content=\"Dur\u00e9e de lecture est.\">\n\t<meta name=\"twitter:data2\" content=\"7 minutes\">\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebSite\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#website\",\"url\":\"https:\/\/www.thermal-engineering.org\/fr\/\",\"name\":\"Thermal Engineering\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":\"https:\/\/www.thermal-engineering.org\/fr\/?s={search_term_string}\",\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"fr-FR\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-dittus-boelter-definition\/#primaryimage\",\"inLanguage\":\"fr-FR\",\"url\":\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Dittus-Boelter-Equation-Formula.png\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-dittus-boelter-definition\/#webpage\",\"url\":\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-dittus-boelter-definition\/\",\"name\":\"Qu'est-ce que l'\\u00e9quation de Dittus-Boelter - D\\u00e9finition\",\"isPartOf\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-dittus-boelter-definition\/#primaryimage\"},\"datePublished\":\"2019-10-14T17:31:48+00:00\",\"dateModified\":\"2020-02-17T09:27:53+00:00\",\"author\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#\/schema\/person\/e8c544db9afedaec8574d6464f9398bb\"},\"description\":\"Le nombre de Nusselt local peut \\u00eatre obtenu \\u00e0 partir de la c\\u00e9l\\u00e8bre \\u00e9quation de Dittus-Boelter. 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