{"id":44893,"date":"2019-10-16T22:51:06","date_gmt":"2019-10-16T21:51:06","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quest-ce-que-le-cycle-de-brayton-processus-equations-definition\/"},"modified":"2020-02-19T14:27:40","modified_gmt":"2020-02-19T13:27:40","slug":"quest-ce-que-le-cycle-de-brayton-processus-equations-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-de-brayton-processus-equations-definition\/","title":{"rendered":"Qu&#8217;est-ce que le cycle de Brayton &#8211; Processus &#8211; Equations &#8211; D\u00e9finition"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Dans un cycle de Brayton id\u00e9al ferm\u00e9, le syst\u00e8me qui ex\u00e9cute le cycle subit une s\u00e9rie de quatre processus: deux processus isentropiques altern\u00e9s avec deux processus isobares.\u00a0G\u00e9nie thermique<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights lgc-first\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Brayton Cycle &#8211; Moteur \u00e0 turbine<\/h2>\n<p>En 1872, un ing\u00e9nieur am\u00e9ricain,\u00a0<strong>George Bailey Brayton, a fait<\/strong>\u00a0progresser l\u2019\u00e9tude des\u00a0<a title=\"Moteurs de chaleur\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-moteur-thermique-definition\/\">moteurs thermiques<\/a>\u00a0en brevetant un moteur \u00e0 combustion interne \u00e0 pression constante, utilisant initialement du gaz vaporis\u00e9, puis des combustibles liquides tels que le k\u00e9ros\u00e8ne.\u00a0Ce moteur thermique est connu sous le nom de \u00ab\u00a0<em><strong>moteur pr\u00eat de Brayton<\/strong>\u00a0\u00bb<\/em>\u00a0.\u00a0Cela signifie que le\u00a0<strong>moteur Brayton d&#8217;origine<\/strong>\u00a0utilisait un\u00a0<strong>compresseur \u00e0\u00a0<\/strong><strong>piston<\/strong>\u00a0et\u00a0<strong>un d\u00e9tendeur \u00e0 piston<\/strong>\u00a0au lieu d&#8217;une turbine \u00e0 gaz et d&#8217;un compresseur \u00e0 gaz.<\/p>\n<p>Aujourd&#8217;hui,\u00a0<strong>les moteurs \u00e0 turbine \u00e0 gaz<\/strong>\u00a0et les\u00a0<strong>turbor\u00e9acteurs modernes \u00e0 air comprim\u00e9<\/strong>\u00a0sont \u00e9galement des moteurs thermiques \u00e0 pression constante. C&#8217;est pourquoi nous d\u00e9crivons leur thermodynamique selon le\u00a0<strong>cycle de Brayton<\/strong>\u00a0.\u00a0En g\u00e9n\u00e9ral, le\u00a0<strong>cycle de Brayton<\/strong>\u00a0d\u00e9crit le fonctionnement d\u2019un\u00a0<strong>moteur thermique \u00e0 pression constante<\/strong>\u00a0.<\/p>\n<p>C&#8217;est l&#8217;un des\u00a0<a title=\"Cycles thermodynamiques\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-cycles\/\"><strong>cycles thermodynamiques<\/strong><\/a>\u00a0les plus courants\u00a0que l&#8217;on puisse trouver dans les centrales \u00e0 turbine \u00e0 gaz ou dans les avions.\u00a0Contrairement au\u00a0<a title=\"Cycle Carnot - Moteur thermique Carnot\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-carnot-cycle-moteur-thermique-carnot-definition\/\">cycle de Carnot<\/a>\u00a0, le\u00a0<strong>cycle de Brayton<\/strong>\u00a0n&#8217;ex\u00e9cute pas de\u00a0<a title=\"Processus isothermique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quel-est-le-processus-isothermique-definition\/\">processus isothermiques<\/a>\u00a0, car ceux-ci doivent \u00eatre effectu\u00e9s tr\u00e8s lentement.\u00a0Dans un\u00a0<strong>cycle de Brayton id\u00e9al<\/strong>\u00a0, le syst\u00e8me qui ex\u00e9cute le cycle subit une s\u00e9rie de quatre processus: deux processus isentropiques (adiabatiques r\u00e9versibles) altern\u00e9s avec deux processus isobares.<\/p>\n<p>Puisque le\u00a0<strong>principe de Carnot<\/strong>\u00a0stipule qu&#8217;aucun moteur ne\u00a0peut \u00eatre plus efficace qu&#8217;un moteur r\u00e9versible (\u00a0<strong>un moteur thermique Carnot<\/strong>\u00a0) fonctionnant entre la m\u00eame temp\u00e9rature \u00e9lev\u00e9e et des\u00a0r\u00e9servoirs \u00e0\u00a0basse temp\u00e9rature, une turbine \u00e0 gaz en\u00a0fonction du cycle Brayton doit avoir une\u00a0efficacit\u00e9 inf\u00e9rieure \u00e0 l&#8217;efficacit\u00e9 Carnot.<\/p>\n<p>Une grande turbine \u00e0 gaz \u00e0 cycle unique produit par exemple, par exemple, 300 m\u00e9gawatts d&#8217;\u00e9nergie \u00e9lectrique et un rendement thermique compris entre 35 et 40%.\u00a0Les installations modernes \u00e0 turbine \u00e0 gaz \u00e0 cycle combin\u00e9 (CCGT), dans lesquelles le cycle thermodynamique est constitu\u00e9 de deux cycles de centrale (par exemple, le cycle de Brayton et le cycle de Rankine), peuvent atteindre un rendement thermique d\u2019environ 55%.<\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights lgc-last\">\n<div class=\"inside-grid-column\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/open-Brayton-cycle-Gas-Turbine-min.png\"><img loading=\"lazy\" class=\"aligncenter size-medium wp-image-17685 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/open-Brayton-cycle-Gas-Turbine-min-249x300.png\" alt=\"cycle de Brayton ouvert - Turbine \u00e0 gaz\" width=\"249\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/open-Brayton-cycle-Gas-Turbine-min-249x300.png\" \/><\/a><\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<h2><span>Cycle de Brayton &#8211; Processus<\/span><\/h2>\n<p><strong><span>Cycle de Brayton &#8211; Processus<\/span><\/strong><\/p>\n<p><span>Dans un\u00a0<\/span><strong><span>cycle de Brayton id\u00e9al ferm\u00e9<\/span><\/strong><span>\u00a0, le syst\u00e8me ex\u00e9cutant le cycle subit une s\u00e9rie de quatre processus: deux processus isentropiques (adiabatiques r\u00e9versibles) altern\u00e9s avec deux processus isobares:<\/span><\/p>\n<ul>\n<li>\n<figure id=\"attachment_17684\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-17684\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/closed-Brayton-cycle-pV-Diagram-min.png\"><img loading=\"lazy\" class=\"wp-image-17684 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/closed-Brayton-cycle-pV-Diagram-min.png\" alt=\"cycle de Brayton ferm\u00e9 - Diagramme pV\" width=\"370\" height=\"450\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/closed-Brayton-cycle-pV-Diagram-min.png\" \/><\/a><figcaption id=\"caption-attachment-17684\" class=\"wp-caption-text\"><span>cycle de Brayton ferm\u00e9<\/span><\/figcaption><\/figure>\n<p><strong><span>Compression isentropique<\/span><\/strong><span>\u00a0(compression dans un compresseur) &#8211; Le gaz de travail (par exemple l&#8217;h\u00e9lium) est comprim\u00e9 de mani\u00e8re adiabatique de l&#8217;\u00e9tat 1 \u00e0 l&#8217;\u00e9tat 2 par le compresseur (g\u00e9n\u00e9ralement un compresseur \u00e0 flux axial).\u00a0L&#8217;environnement travaille sur le gaz, augmentant son \u00e9nergie interne (temp\u00e9rature) et le compressant (augmentant sa pression).\u00a0En revanche, l&#8217;entropie reste inchang\u00e9e.\u00a0Le travail requis pour le compresseur est donn\u00e9 par\u00a0<\/span><strong><span>W\u00a0<\/span><\/strong><strong><sub><span>C<\/span><\/sub><\/strong><strong><span>\u00a0= H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><strong><span>\u00a0.<\/span><\/strong><\/li>\n<li><strong><span>Apport de chaleur isobare<\/span><\/strong><span>\u00a0(dans un \u00e9changeur de chaleur) &#8211; Dans cette phase (entre l&#8217;\u00e9tat 2 et l&#8217;\u00e9tat 3), il y a un transfert de chaleur \u00e0 pression constante vers le gaz depuis une source externe, car la chambre est ouverte pour entrer et sortir.\u00a0Dans un cycle de Brayton id\u00e9al ouvert, l&#8217;air comprim\u00e9 traverse ensuite une chambre de combustion, o\u00f9 le carburant est br\u00fbl\u00e9 et l&#8217;air ou un autre milieu est chauff\u00e9 (2 \u2192 3).\u00a0Il s&#8217;agit d&#8217;un processus \u00e0 pression constante, car la chambre est ouverte pour entrer et sortir.\u00a0La chaleur nette ajout\u00e9e est donn\u00e9e par\u00a0<\/span><strong><span>Q\u00a0<\/span><\/strong><strong><sub><span>add<\/span><\/sub><\/strong><strong><span>\u00a0= H\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><\/li>\n<li><strong><span>Expansion isentropique<\/span><\/strong><span>\u00a0(expansion dans une turbine) &#8211; Le gaz comprim\u00e9 et chauff\u00e9 se d\u00e9tend adiabatiquement de l&#8217;\u00e9tat 3 \u00e0 l&#8217;\u00e9tat 4 dans une turbine.\u00a0Le gaz travaille sur l&#8217;environnement (pales de la turbine) et perd une quantit\u00e9 d&#8217;\u00e9nergie interne \u00e9gale au travail qui quitte le syst\u00e8me.\u00a0Le travail effectu\u00e9 par turbine est donn\u00e9 par\u00a0<\/span><strong><span>W\u00a0<\/span><\/strong><strong><sub><span>T<\/span><\/sub><\/strong><strong><span>\u00a0= H\u00a0<\/span><\/strong><strong><sub><span>4<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><strong><span>\u00a0.\u00a0<\/span><\/strong><span>Encore une fois, l&#8217;entropie reste inchang\u00e9e.<\/span><\/li>\n<li><strong><span>Rejet de chaleur isobare (dans un \u00e9changeur de chaleur)<\/span><\/strong><span>\u00a0&#8211; Dans cette phase, le cycle se termine par un processus \u00e0 pression constante dans lequel la chaleur est rejet\u00e9e du gaz.\u00a0La temp\u00e9rature du gaz de travail chute du point 4 au point 1. La chaleur nette rejet\u00e9e est donn\u00e9e par\u00a0<\/span><strong><span>Q\u00a0<\/span><\/strong><strong><sub><span>re<\/span><\/sub><\/strong><strong><span>\u00a0= H\u00a0<\/span><\/strong><strong><sub><span>4<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><\/li>\n<\/ul>\n<p><span>Lors d&#8217;un cycle de Brayton, des travaux sont effectu\u00e9s sur le gaz par le compresseur entre les \u00e9tats 1 et 2 (\u00a0<\/span><strong><span>i\u00a0<\/span><\/strong><strong><span>compression sentropique<\/span><\/strong><span>\u00a0).\u00a0Le travail est effectu\u00e9 par le gaz dans la turbine entre les \u00e9tapes 3 et 4 (\u00a0<\/span><strong><span>i\u00a0<\/span><\/strong><strong><span>expansion sentropique<\/span><\/strong><span>\u00a0).\u00a0La diff\u00e9rence entre le travail effectu\u00e9 par le gaz et le travail effectu\u00e9 sur le gaz est le travail net produit par le cycle et il correspond \u00e0 l&#8217;aire d\u00e9limit\u00e9e par la courbe du cycle (en diagramme pV).<\/span><\/p>\n<p><span>Comme on peut le voir, il est commode d&#8217;utiliser l&#8217;\u00a0<\/span><a title=\"Qu'est-ce que l'enthalpie\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-enthalpy\/\"><strong><span>enthalpie<\/span><\/strong><\/a><span>\u00a0\u00a0ou l&#8217;\u00a0<a title=\"Qu'est-ce que l'enthalpie\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-enthalpy\/\"><strong>enthalpie\u00a0<\/strong><\/a><\/span><strong><a title=\"Enthalpie sp\u00e9cifique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-enthalpy\/specific-enthalpy\/\"><span>sp\u00e9cifique<\/span><\/a><\/strong><span>\u00a0et d&#8217;exprimer la\u00a0<\/span><a title=\"Premi\u00e8re loi en termes d'enthalpie dH = dQ + Vdp\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/first-law-in-terms-of-enthalpy-dh-dq-vdp\/\"><span>premi\u00e8re loi en termes d&#8217;enthalpie<\/span><\/a><span>\u00a0dans l&#8217;analyse de ce cycle thermodynamique.\u00a0Cette forme de loi\u00a0<\/span><strong><span>simplifie la description du transfert d&#8217;\u00e9nergie<\/span><\/strong><span>\u00a0.\u00a0<\/span><strong><span>\u00c0 pression constante<\/span><\/strong><span>\u00a0, le\u00a0<\/span><strong><span>changement d&#8217;enthalpie<\/span><\/strong><span>\u00a0est \u00e9gal \u00e0 l&#8217;\u00a0<\/span><strong><span>\u00e9nergie<\/span><\/strong><span>\u00a0transf\u00e9r\u00e9e de l&#8217;environnement par le chauffage:<\/span><\/p>\n<p><strong><span>Processus isobare (Vdp = 0):<\/span><\/strong><\/p>\n<p><strong><span>dH = dQ \u2192 Q = H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><\/p>\n<p><strong><span>\u00c0 entropie constante<\/span><\/strong><span>\u00a0, c&#8217;est-\u00e0-dire dans un processus isentropique, le\u00a0<\/span><strong><span>changement d&#8217;enthalpie<\/span><\/strong><span>\u00a0est \u00e9gal au\u00a0<\/span><strong><span>travail de processus d&#8217;\u00e9coulement<\/span><\/strong><span>\u00a0effectu\u00e9 sur ou par le syst\u00e8me:<\/span><\/p>\n<p><strong><span>Processus isentropique (dQ = 0):<\/span><\/strong><\/p>\n<p><strong><span>dH = Vdp \u2192 W = H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><\/p>\n<p><span>Voir aussi:\u00a0<\/span><a title=\"Premi\u00e8re loi en termes d'enthalpie dH = dQ + Vdp\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/first-law-in-terms-of-enthalpy-dh-dq-vdp\/\"><strong><span>Pourquoi les ing\u00e9nieurs motoristes utilisent l&#8217;enthalpie?\u00a0R\u00e9ponse: dH = dQ + Vdp<\/span><\/strong><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights  lgc-first\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Processus isentropique<\/span><\/h2>\n<p><span>Un\u00a0<\/span><a title=\"Processus isentropique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quel-est-le-processus-isentropique-definition\/\"><strong><span>processus isentropique<\/span><\/strong><\/a><span>\u00a0est un\u00a0<\/span><a title=\"Processus thermodynamiques\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-processus-thermodynamique-definition\/\"><strong><span>processus thermodynamique<\/span><\/strong><\/a><span>\u00a0, dans lequel l&#8217;\u00a0<\/span><a title=\"Qu'est-ce que l'entropie\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-entropy\/\"><strong><span>entropie<\/span><\/strong>\u00a0<\/a><span>du fluide ou du gaz reste constante.\u00a0Cela signifie que le\u00a0<\/span><strong><span>processus isentropique<\/span><\/strong><span>\u00a0est un cas particulier d&#8217;un\u00a0<\/span><strong><span>processus adiabatique<\/span><\/strong><span>\u00a0dans lequel il n&#8217;y a pas de transfert de chaleur ou de mati\u00e8re.\u00a0Il s&#8217;agit d&#8217;un\u00a0<\/span><strong><span>processus adiabatique r\u00e9versible<\/span><\/strong><span>\u00a0.\u00a0L&#8217;hypoth\u00e8se d&#8217;absence de transfert de chaleur est tr\u00e8s importante, car nous ne pouvons utiliser l&#8217;approximation adiabatique que dans\u00a0<\/span><strong><span>des processus tr\u00e8s rapides<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><strong><span>Processus isentropique et premi\u00e8re loi<\/span><\/strong><\/p>\n<p><span>Pour un syst\u00e8me ferm\u00e9, on peut \u00e9crire la\u00a0<\/span><strong><a title=\"Premi\u00e8re loi en termes d'enthalpie dH = dQ + Vdp\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/first-law-in-terms-of-enthalpy-dh-dq-vdp\/\"><span>premi\u00e8re loi de la thermodynamique en termes d&#8217;enthalpie<\/span><\/a><\/strong><span>\u00a0:<\/span><\/p>\n<p><strong><span>dH = dQ + Vdp<\/span><\/strong><\/p>\n<p><strong><span>ou<\/span><\/strong><\/p>\n<p><strong><span>dH = TdS + Vdp<\/span><\/strong><\/p>\n<p><strong><span>Processus isentropique (dQ = 0):<\/span><\/strong><\/p>\n<p><strong><span>dH = Vdp \u2192 W = H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><strong><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u2192 H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><strong><span>\u00a0=\u00a0<\/span><em><span>C\u00a0<\/span><\/em><\/strong><strong><em><sub><span>p<\/span><\/sub><\/em><\/strong><strong><em><span>\u00a0(T\u00a0<\/span><\/em><\/strong><strong><em><sub><span>2<\/span><\/sub><\/em><\/strong><strong><em><span>\u00a0&#8211; T\u00a0<\/span><\/em><\/strong><strong><em><sub><span>1<\/span><\/sub><\/em><\/strong><strong><em><span>\u00a0) \u00a0\u00a0\u00a0<\/span><\/em><\/strong><em><span>\u00a0(pour\u00a0<\/span><a title=\"Qu'est-ce que le gaz parfait\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/ideal-gas-law\/what-is-ideal-gas\/\"><span>le gaz parfait<\/span><\/a><span>\u00a0)<\/span><\/em><\/p>\n<p><strong><span>Processus isentropique du gaz parfait<\/span><\/strong><\/p>\n<p><span>Le\u00a0<\/span><strong><span>processus isentropique<\/span><\/strong><span>\u00a0(un cas particulier du processus adiabatique) peut \u00eatre exprim\u00e9 avec la\u00a0<\/span><a title=\"Loi du gaz parfait\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/ideal-gas-law\/\"><strong><span>loi du gaz parfait<\/span><\/strong><\/a><span>\u00a0comme:<\/span><\/p>\n<p><strong><em><span>pV\u00a0<\/span><sup><span>\u03ba<\/span><\/sup><span>\u00a0= constant<\/span><\/em><\/strong><\/p>\n<p><span>ou<\/span><\/p>\n<p><em><strong><span>p\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>1\u00a0<\/span><\/sub><sup><span>\u03ba<\/span><\/sup><span>\u00a0= p\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>2\u00a0<\/span><\/sub><sup><span>\u03ba<\/span><\/sup><\/strong><\/em><\/p>\n<p><span>dans laquelle\u00a0<\/span><strong><span>\u03ba = c\u00a0<\/span><sub><span>p<\/span><\/sub><span>\u00a0\/ c\u00a0<\/span><sub><span>v<\/span><\/sub><\/strong><span>\u00a0est le rapport des\u00a0<a title=\"Capacit\u00e9 calorifique - Capacit\u00e9 calorifique sp\u00e9cifique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/heat-capacity\/\"><strong>chaleurs sp\u00e9cifiques<\/strong><\/a>\u00a0(ou\u00a0<strong>capacit\u00e9s calorifiques<\/strong>\u00a0) pour le gaz.\u00a0Un pour\u00a0<strong>une pression constante (c\u00a0<\/strong><strong><sub>p<\/sub><\/strong><strong>\u00a0)<\/strong>\u00a0et un pour\u00a0<strong>un volume constant (c\u00a0<\/strong><strong><sub>v<\/sub><\/strong><strong>\u00a0)<\/strong>\u00a0.\u00a0Notez que ce rapport\u00a0<strong>\u03ba\u00a0\u00a0<\/strong><strong>= c\u00a0<\/strong><strong><sub>p<\/sub><\/strong><strong>\u00a0\/ c\u00a0<\/strong><strong><sub>v<\/sub><\/strong>\u00a0est un facteur d\u00e9terminant la vitesse du son dans un gaz et d&#8217;autres processus adiabatiques.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights  lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Processus isobare<\/span><\/h2>\n<p><span>Un\u00a0<\/span><a title=\"Processus isobare\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quel-est-le-processus-isobare-definition\/\"><strong><span>processus isobare<\/span><\/strong><\/a><span>\u00a0est un\u00a0<\/span><a title=\"Processus thermodynamiques\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-processus-thermodynamique-definition\/\"><span>processus thermodynamique<\/span><\/a><span>\u00a0, dans lequel la\u00a0<\/span><a title=\"Qu'est-ce que la pression - Physique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/\"><strong><span>pression<\/span><\/strong><\/a><span>\u00a0du syst\u00e8me\u00a0<\/span><strong><span>reste constante<\/span><\/strong><span>\u00a0(p = const).\u00a0Le transfert de chaleur dans ou hors du syst\u00e8me fonctionne, mais modifie \u00e9galement l&#8217;\u00e9nergie interne du syst\u00e8me.<\/span><\/p>\n<p><span>Puisqu&#8217;il y a des changements d&#8217;\u00a0<\/span><a href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lenergie-interne-energie-thermique-definition\/\"><span>\u00e9nergie interne<\/span><\/a><span>\u00a0(dU) et des changements de volume du syst\u00e8me (\u2206V), les ing\u00e9nieurs utilisent souvent l&#8217;\u00a0<\/span><a title=\"Qu'est-ce que l'enthalpie\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-enthalpy\/\"><strong><span>enthalpie<\/span><\/strong><\/a><span>\u00a0du syst\u00e8me, qui est d\u00e9finie comme:<\/span><\/p>\n<p><em><strong><span>H = U + pV<\/span><\/strong><\/em><\/p>\n<p><strong><span>Processus isobare et premi\u00e8re loi<\/span><\/strong><\/p>\n<p><span>La forme classique de la\u00a0<\/span><a title=\"Premi\u00e8re loi de la thermodynamique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-premiere-loi-de-la-thermodynamique-definition\/\"><span>premi\u00e8re loi de la thermodynamique<\/span><\/a><span>\u00a0est l&#8217;\u00e9quation suivante:<\/span><\/p>\n<p><strong><span>dU = dQ &#8211; dW<\/span><\/strong><\/p>\n<p><span>Dans cette \u00e9quation, dW est \u00e9gal \u00e0\u00a0<\/span><strong><span>dW = pdV<\/span><\/strong><span>\u00a0et est connu comme le\u00a0<\/span><a title=\"Travaux p\u0394V - Travaux aux limites et travaux V\u0394p\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/p%ce%b4v-work-boundary-work-and-v%ce%b4p-work\/\"><span>travail<\/span><\/a><span>\u00a0aux\u00a0<a title=\"Travaux p\u0394V - Travaux aux limites et travaux V\u0394p\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/p%ce%b4v-work-boundary-work-and-v%ce%b4p-work\/\">limites<\/a>\u00a0.\u00a0Dans un proc\u00e9d\u00e9 isobare et le gaz parfait, une\u00a0<\/span><strong><span>partie de la chaleur ajout\u00e9e<\/span><\/strong><span>\u00a0au syst\u00e8me sera utilis\u00e9e pour\u00a0<\/span><strong><span>faire le travail<\/span><\/strong><span>\u00a0et une\u00a0<\/span><strong><span>partie de la chaleur<\/span><\/strong><span>\u00a0ajout\u00e9e augmentera l&#8217;\u00a0<\/span><a href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lenergie-interne-energie-thermique-definition\/\"><strong><span>\u00e9nergie interne<\/span><\/strong><\/a><span>\u00a0(augmentera la temp\u00e9rature).\u00a0Par cons\u00e9quent, il est commode d&#8217;utiliser l&#8217;\u00a0<\/span><strong><span>enthalpie<\/span><\/strong><span>\u00a0au lieu de l&#8217;\u00e9nergie interne.<\/span><\/p>\n<p><strong><span>Processus isobare (Vdp = 0):<\/span><\/strong><\/p>\n<p><strong><span>dH = dQ \u2192 Q = H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><\/p>\n<p><strong><span>\u00c0 entropie constante<\/span><\/strong><span>\u00a0, c&#8217;est-\u00e0-dire dans un processus isentropique, le\u00a0<\/span><strong><span>changement d&#8217;enthalpie<\/span><\/strong><span>\u00a0est \u00e9gal au\u00a0<\/span><strong><span>travail de processus d&#8217;\u00e9coulement<\/span><\/strong><span>\u00a0effectu\u00e9 sur ou par le syst\u00e8me.<\/span><\/p>\n<p><strong><span>Processus isobare du gaz parfait<\/span><\/strong><\/p>\n<p><span>Le\u00a0<\/span><strong><span>processus isobare<\/span><\/strong><span>\u00a0peut s&#8217;exprimer avec la\u00a0<\/span><a title=\"Loi du gaz parfait\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/ideal-gas-law\/\"><strong><span>loi du gaz parfait<\/span><\/strong><\/a><span>\u00a0comme:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isobaric-process-equation-2.png?a34b7f\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17430 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isobaric-process-equation-2.png?a34b7f\" alt=\"processus isobare - \u00e9quation - 2\" width=\"134\" height=\"63\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isobaric-process-equation-2.png?a34b7f\" \/><\/a><\/p>\n<p><span>ou<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isobaric-process-equation-3.png?a34b7f\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17431 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isobaric-process-equation-3.png?a34b7f\" alt=\"processus isobare - \u00e9quation - 3\" width=\"77\" height=\"67\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isobaric-process-equation-3.png?a34b7f\" \/><\/a><\/p>\n<p><span>Sur un\u00a0<\/span><strong><span>diagramme pV<\/span><\/strong><span>\u00a0, le processus se produit le long d&#8217;une ligne horizontale (appel\u00e9e isobare) qui a l&#8217;\u00e9quation p = constante.<\/span><\/p>\n<p><span>Voir aussi:\u00a0<\/span><a title=\"La loi de Charles\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-loi-de-charles-definition\/\"><span>Charles&#8217;s Law<\/span><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights  lgc-first\">\n<div class=\"inside-grid-column\">\n<figure id=\"attachment_17280\" class=\"wp-caption aligncenter\" aria-describedby=\"caption-attachment-17280\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isentropic-Process-characteristics.png\"><img loading=\"lazy\" class=\"size-full wp-image-17280 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isentropic-Process-characteristics.png\" alt=\"Processus isentropique - caract\u00e9ristiques\" width=\"386\" height=\"609\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isentropic-Process-characteristics.png\" \/><\/a><figcaption id=\"caption-attachment-17280\" class=\"wp-caption-text\"><span>Processus isentropique &#8211; principales caract\u00e9ristiques<\/span><\/figcaption><\/figure>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights  lgc-last\">\n<div class=\"inside-grid-column\">\n<figure id=\"attachment_17426\" class=\"wp-caption aligncenter\" aria-describedby=\"caption-attachment-17426\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isobaric-process-main-characteristics.png\"><img loading=\"lazy\" class=\"size-full wp-image-17426 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isobaric-process-main-characteristics.png\" alt=\"Processus isobare - principales caract\u00e9ristiques\" width=\"381\" height=\"717\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isobaric-process-main-characteristics.png\" \/><\/a><figcaption id=\"caption-attachment-17426\" class=\"wp-caption-text\"><span>Processus isobare &#8211; principales caract\u00e9ristiques<\/span><\/figcaption><\/figure>\n<\/div>\n<\/div>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Dans un cycle de Brayton id\u00e9al ferm\u00e9, le syst\u00e8me qui ex\u00e9cute le cycle subit une s\u00e9rie de quatre processus: deux processus isentropiques altern\u00e9s avec deux processus isobares.\u00a0G\u00e9nie thermique Brayton Cycle &#8211; Moteur \u00e0 turbine En 1872, un ing\u00e9nieur am\u00e9ricain,\u00a0George Bailey Brayton, a fait\u00a0progresser l\u2019\u00e9tude des\u00a0moteurs thermiques\u00a0en brevetant un moteur \u00e0 combustion interne \u00e0 pression constante, &#8230; <a title=\"Qu&#8217;est-ce que le cycle de Brayton &#8211; Processus &#8211; Equations &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-de-brayton-processus-equations-definition\/\" aria-label=\"En savoir plus sur Qu&#8217;est-ce que le cycle de Brayton &#8211; Processus &#8211; Equations &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Qu&#039;est-ce que le cycle de Brayton - Processus - Equations - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"Dans un cycle de Brayton id\u00e9al ferm\u00e9, le syst\u00e8me qui ex\u00e9cute le cycle subit une s\u00e9rie de quatre processus: deux processus isentropiques altern\u00e9s avec deux processus isobares. 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