{"id":46157,"date":"2019-10-21T01:16:06","date_gmt":"2019-10-21T00:16:06","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quest-ce-que-pascal-unite-de-pression-definition\/"},"modified":"2020-02-26T14:52:38","modified_gmt":"2020-02-26T13:52:38","slug":"quest-ce-que-pascal-unite-de-pression-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-pascal-unite-de-pression-definition\/","title":{"rendered":"Qu&#8217;est-ce que Pascal &#8211; Unit\u00e9 de pression &#8211; D\u00e9finition"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Pascal &#8211; Unit\u00e9 de pression. Pascal est d\u00e9fini comme un newton par m\u00e8tre carr\u00e9. Cependant, il est pratique de travailler avec des multiples du pascal: le kPa, le bar et le MPa. G\u00e9nie thermique<\/div>\n<\/div>\n<div><\/div>\n<div><\/div>\n<div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<h2><span>Quelle est la pression<\/span><\/h2>\n<p><strong><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Manometer-Pressure-Measurement.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-16368 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Manometer-Pressure-Measurement-235x300.png\" alt=\"manom\u00e8tre-pression-mesure\" width=\"235\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Manometer-Pressure-Measurement-235x300.png\" \/><\/a><a title=\"Qu'est-ce que la pression - Physique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/\"><span>La pression<\/span><\/a><\/strong><span>\u00a0est une mesure de la<\/span><strong><span>\u00a0force exerc\u00e9e<\/span><\/strong><span>\u00a0par unit\u00e9 de surface sur les limites d&#8217;une substance.\u00a0L&#8217;unit\u00e9 standard de<\/span><strong><span>\u00a0pression<\/span><\/strong><span>\u00a0dans le syst\u00e8me SI est le<\/span><strong><span>\u00a0Newton par m\u00e8tre carr\u00e9 ou pascal (Pa)<\/span><\/strong><span>\u00a0.\u00a0Math\u00e9matiquement:<\/span><\/p>\n<p><strong><span>p = F \/ A<\/span><\/strong><\/p>\n<p><span>o\u00f9<\/span><\/p>\n<ul>\n<li><strong><span>p est la pression<\/span><\/strong><\/li>\n<li><strong><span>F est la force normale<\/span><\/strong><\/li>\n<li><strong><span>A est l&#8217;aire de la fronti\u00e8re<\/span><\/strong><\/li>\n<\/ul>\n<p><span>Pascal est d\u00e9fini comme la force de 1N qui s&#8217;exerce sur la surface unitaire.<\/span><\/p>\n<ul>\n<li><strong><span>1 Pascal = 1 N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-60 lgc-tablet-grid-60 lgc-mobile-grid-100 lgc-equal-heights  lgc-first\">\n<div class=\"inside-grid-column\"><span>Cependant, pour la plupart des probl\u00e8mes d&#8217;ing\u00e9nierie, il s&#8217;agit d&#8217;une unit\u00e9 assez petite, il est donc pratique de travailler avec des multiples du pascal: le\u00a0<\/span><strong><span>kPa<\/span><\/strong><span>\u00a0, la\u00a0<\/span><strong><span>barre<\/span><\/strong><span>\u00a0et le\u00a0<\/span><strong><span>MPa<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<ul>\n<li><strong><span>1 MPa 10\u00a0<\/span><sup><span>6<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><strong><span>1 bar 10\u00a0<\/span><sup><span>5<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><strong><span>1 kPa 10\u00a0<\/span><sup><span>3<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<\/ul>\n<p><span>En g\u00e9n\u00e9ral, la pression ou la force exerc\u00e9e par unit\u00e9 de surface sur les limites d&#8217;une substance est caus\u00e9e par les\u00a0<\/span><strong><span>collisions<\/span><\/strong><span>\u00a0des\u00a0<\/span><strong><span>mol\u00e9cules<\/span><\/strong><span>\u00a0de la substance avec les limites du syst\u00e8me.\u00a0Lorsque les mol\u00e9cules frappent les murs, elles exercent des forces qui tentent de pousser les murs vers l&#8217;ext\u00e9rieur.\u00a0Les forces r\u00e9sultant de toutes ces collisions provoquent la\u00a0<\/span><strong><span>pression<\/span><\/strong><span>\u00a0exerc\u00e9e par un syst\u00e8me sur son environnement.\u00a0La pression en tant que\u00a0<\/span><a title=\"Propri\u00e9t\u00e9s \u00e9tendues et intensives\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/extensive-and-intensive-properties\/\"><strong><span>variable intensive<\/span><\/strong>\u00a0<\/a><span>est constante dans un syst\u00e8me ferm\u00e9.\u00a0Il n&#8217;est vraiment pertinent que dans les syst\u00e8mes liquides ou gazeux.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-40 lgc-tablet-grid-40 lgc-mobile-grid-100 lgc-equal-heights  lgc-last\">\n<div class=\"inside-grid-column\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/What-is-Pressure.png\"><img loading=\"lazy\" class=\"aligncenter size-medium wp-image-16371 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/What-is-Pressure-300x129.png\" alt=\"Quelle est la pression\" width=\"300\" height=\"129\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/What-is-Pressure-300x129.png\" \/><\/a><\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>\u00c9chelles de pression &#8211; Unit\u00e9s de pression<\/span><\/h2>\n<h2><span>Pascal &#8211; Unit\u00e9 de pression<\/span><\/h2>\n<p><span>Comme nous l&#8217;avons vu, l&#8217;\u00a0<\/span><strong><span>unit\u00e9 SI<\/span><\/strong><span>\u00a0de\u00a0<\/span><strong><span>pression<\/span><\/strong><span>\u00a0et de contrainte est le\u00a0<\/span><strong><span>pascal<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<ul>\n<li><strong><span>1 pascal 1 N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><span>\u00a0= 1 kg \/ (ms\u00a0<\/span><sup><span>2<\/span><\/sup><span>\u00a0)<\/span><\/strong><\/li>\n<\/ul>\n<p><span>Pascal est d\u00e9fini comme un newton par m\u00e8tre carr\u00e9.\u00a0Cependant, pour la plupart des probl\u00e8mes d&#8217;ing\u00e9nierie, il s&#8217;agit d&#8217;une unit\u00e9 assez petite, il est donc pratique de travailler avec des multiples du pascal: le\u00a0<\/span><strong><span>kPa<\/span><\/strong><span>\u00a0, la\u00a0<\/span><strong><span>barre<\/span><\/strong><span>\u00a0et le\u00a0<\/span><strong><span>MPa<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<ul>\n<li><strong><span>1 MPa 10\u00a0<\/span><sup><span>6<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><strong><span>1 bar 10\u00a0<\/span><sup><span>5<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><strong><span>1 kPa 10\u00a0<\/span><sup><span>3<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<\/ul>\n<p><span>L&#8217;unit\u00e9 de mesure appel\u00e9e\u00a0<\/span><strong><span>atmosph\u00e8re standard<\/span><\/strong><span>\u00a0(\u00a0<\/span><strong><span>atm<\/span><\/strong><span>\u00a0) est d\u00e9finie comme:<\/span><\/p>\n<ul>\n<li><strong><span>1 atm = 101,33 kPa<\/span><\/strong><\/li>\n<\/ul>\n<p><span>L&#8217;atmosph\u00e8re standard se rapproche de la pression moyenne au niveau de la mer \u00e0 45 \u00b0 de latitude N. Notez qu&#8217;il y a une diff\u00e9rence entre l&#8217;\u00a0<\/span><strong><span>atmosph\u00e8re standard<\/span><\/strong><span>\u00a0(atm) et l&#8217;\u00a0<\/span><strong><span>atmosph\u00e8re technique<\/span><\/strong><span>\u00a0(at).<\/span><\/p>\n<p><span>Une atmosph\u00e8re technique est une unit\u00e9 de pression non SI \u00e9gale \u00e0 un kilogramme de force par centim\u00e8tre carr\u00e9.<\/span><\/p>\n<ul>\n<li><strong><span>1 \u00e0 = 98,67 kPa<\/span><\/strong><\/li>\n<\/ul>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Pressure-Units-pascal-bar-psi-atmosphere.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-16280 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Pressure-Units-pascal-bar-psi-atmosphere.png\" alt=\"Tableau - Conversion entre unit\u00e9s de pression - pascal, bar, psi, atmosph\u00e8re\" width=\"659\" height=\"289\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Pressure-Units-pascal-bar-psi-atmosphere.png\" \/><\/a><\/p>\n<p><span>Voir aussi:\u00a0<\/span><a title=\"Livres par pouce carr\u00e9 - psi\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/pounds-per-square-inch-psi\/\"><span>Livre par pouce carr\u00e9 &#8211; psi<\/span><\/a><\/p>\n<p><span>Voir aussi:\u00a0<\/span><a title=\"Bar - Unit\u00e9 de pression\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/bar-unit-of-pressure\/\"><span>Bar &#8211; Unit\u00e9 de pression<\/span><\/a><\/p>\n<p><span>Voir aussi:\u00a0<\/span><a title=\"Pressions typiques en ing\u00e9nierie - Exemples\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/typical-pressures-in-engineering-examples\/\"><span>Pressions typiques en ing\u00e9nierie<\/span><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Pression absolue vs pression manom\u00e9trique<\/span><\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/absolute-vs.-gauge-pressure.png\"><img loading=\"lazy\" class=\"alignright size-full wp-image-16281 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/absolute-vs.-gauge-pressure.png\" alt=\"pression absolue vs manom\u00e9trique\" width=\"388\" height=\"247\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/absolute-vs.-gauge-pressure.png\" \/><\/a><span>La pression d\u00e9crite ci-dessus est appel\u00e9e\u00a0<\/span><strong><span>pression absolue<\/span><\/strong><span>\u00a0.\u00a0Souvent ,\u00a0il est important de\u00a0faire la\u00a0distinction entre\u00a0<\/span><strong><span>pression absolue<\/span><\/strong><span>\u00a0et la\u00a0<\/span><strong><span>pression de la\u00a0jauge<\/span><\/strong><span>\u00a0.\u00a0Dans cet article, le terme pression fait r\u00e9f\u00e9rence \u00e0 la pression absolue, sauf indication contraire explicite.\u00a0Mais en ing\u00e9nierie, nous avons souvent affaire \u00e0 des pressions, qui sont\u00a0<\/span><strong><span>mesur\u00e9es<\/span><\/strong><span>\u00a0par certains appareils.\u00a0Bien que les pressions absolues doivent \u00eatre utilis\u00e9es dans les relations thermodynamiques,\u00a0<\/span><strong><span>les<\/span><\/strong><span>\u00a0appareils de\u00a0<strong>mesure de pression<\/strong>\u00a0indiquent souvent la\u00a0<\/span><strong><span>diff\u00e9rence<\/span><\/strong><span>\u00a0entre la pression absolue dans un syst\u00e8me et la pression absolue de l&#8217;atmosph\u00e8re existant \u00e0 l&#8217;ext\u00e9rieur de l&#8217;appareil de mesure.\u00a0Ils mesurent la\u00a0<\/span><strong><span>pression manom\u00e9trique<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<ul>\n<li><strong><span>Pression absolue.\u00a0<\/span><\/strong><span>Lorsque la pression est mesur\u00e9e par rapport \u00e0 un vide parfait, elle est appel\u00e9e pression absolue (psia).\u00a0Les livres par pouce carr\u00e9 absolu (psia) sont utilis\u00e9es pour indiquer clairement que la pression est relative \u00e0 un vide plut\u00f4t qu&#8217;\u00e0 la pression atmosph\u00e9rique ambiante.\u00a0\u00c9tant donn\u00e9 que la pression atmosph\u00e9rique au niveau de la mer est d&#8217;environ 101,3 kPa (14,7 psi), cela s&#8217;ajoutera \u00e0 toute lecture de pression effectu\u00e9e dans l&#8217;air au niveau de la mer.<\/span><\/li>\n<li><strong><span>Pression manom\u00e9trique.\u00a0<\/span><\/strong><span>Lorsque la pression est mesur\u00e9e par rapport \u00e0 la pression atmosph\u00e9rique (14,7 psi), elle est appel\u00e9e pression manom\u00e9trique (psig).\u00a0Le terme pression relative est appliqu\u00e9 lorsque la pression dans le syst\u00e8me est sup\u00e9rieure \u00e0 la pression atmosph\u00e9rique locale, p\u00a0<\/span><sub><span>atm<\/span><\/sub><span>\u00a0.\u00a0Cette derni\u00e8re \u00e9chelle de pression a \u00e9t\u00e9 d\u00e9velopp\u00e9e car presque tous les manom\u00e8tres enregistrent z\u00e9ro lorsqu&#8217;ils sont ouverts sur l&#8217;atmosph\u00e8re.\u00a0Les pressions manom\u00e9triques sont positives si elles sont sup\u00e9rieures \u00e0 la pression atmosph\u00e9rique et n\u00e9gatives si elles sont inf\u00e9rieures \u00e0 la pression atmosph\u00e9rique.<\/span><\/li>\n<\/ul>\n<p><em><sub><span>jauge<\/span><\/sub><\/em><span><em>\u00a0p\u00a0<\/em><\/span><em><span>= p\u00a0<\/span><\/em><em><sub><span>absolu<\/span><\/sub><\/em><em><span>\u00a0&#8211; p\u00a0<\/span><\/em><em><sub><span>absolu;\u00a0au m<\/span><\/sub><\/em><\/p>\n<ul>\n<li><strong><span>Pression atmosph\u00e9rique.\u00a0<\/span><\/strong><span>La pression atmosph\u00e9rique est la pression dans l&#8217;air ambiant \u00e0 la surface de la Terre &#8211; ou \u00abpr\u00e8s\u00bb de celle-ci.\u00a0La pression atmosph\u00e9rique varie avec la temp\u00e9rature et l&#8217;altitude au-dessus du niveau de la mer.\u00a0La\u00a0<\/span><strong><span>pression atmosph\u00e9rique standard se<\/span><\/strong><span>\u00a0rapproche de la pression moyenne au niveau de la mer \u00e0 45 \u00b0 de latitude nord. La\u00a0<\/span><strong><span>pression atmosph\u00e9rique standard<\/span><\/strong><span>\u00a0est d\u00e9finie au niveau de la mer \u00e0\u00a0<\/span><em><span>273\u00a0<\/span><\/em><em><sup><span>o<\/span><\/sup><\/em><em><span>\u00a0K (0\u00a0<\/span><\/em><em><sup><span>o<\/span><\/sup><\/em><em><span>\u00a0C)<\/span><\/em><span>\u00a0et est:<\/span>\n<ul>\n<li><strong><em><span>101325 Pa<\/span><\/em><\/strong><\/li>\n<li><strong><em><span>1.01325 bar<\/span><\/em><\/strong><\/li>\n<li><strong><em><span>14,696 psi<\/span><\/em><\/strong><\/li>\n<li><strong><em><span>760 mmHg<\/span><\/em><\/strong><\/li>\n<li><strong><em><span>760 torr<\/span><\/em><\/strong><\/li>\n<\/ul>\n<\/li>\n<li><strong><span>Pression manom\u00e9trique n\u00e9gative &#8211; Pression de vide.\u00a0<\/span><\/strong><span>Lorsque la pression atmosph\u00e9rique locale est sup\u00e9rieure \u00e0 la pression dans le syst\u00e8me, le terme\u00a0<\/span><strong><span>pression de vide<\/span><\/strong><span>\u00a0est utilis\u00e9.\u00a0Un vide parfait correspondrait \u00e0 une pression nulle absolue.\u00a0Il est certes possible d&#8217;avoir une pression manom\u00e9trique n\u00e9gative, mais pas possible d&#8217;avoir une pression absolue n\u00e9gative.\u00a0Par exemple, une pression absolue de 80 kPa peut \u00eatre d\u00e9crite comme une pression manom\u00e9trique de -21 kPa (c&#8217;est-\u00e0-dire 21 kPa en dessous d&#8217;une pression atmosph\u00e9rique de 101 kPa).<\/span><\/li>\n<\/ul>\n<p><em><span>p\u00a0<\/span><\/em><em><sub><span>vide<\/span><\/sub><\/em><em><span>\u00a0= p\u00a0<\/span><\/em><em><sub><span>absolu;\u00a0atm<\/span><\/sub><\/em><em><span>\u00a0&#8211; p\u00a0<\/span><\/em><em><sub><span>absolu<\/span><\/sub><\/em><\/p>\n<p><span>Par exemple, un pneu de voiture pomp\u00e9 jusqu&#8217;\u00e0 2,5 atm (36,75 psig) au-dessus de la pression atmosph\u00e9rique locale (disons 1 atm ou 14,7 psia localement), aura une pression absolue de 2,5 + 1 = 3,5 atm (36,75 + 14,7 = 51,45 psia ou 36,75 psig).<\/span><\/p>\n<p><span>En revanche, les\u00a0<\/span><span>turbines<\/span><span>\u00a0\u00e0\u00a0vapeur\u00a0\u00e0 condensation\u00a0\u00a0(dans\u00a0<a title=\"Centrale nucl\u00e9aire\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/\">les centrales nucl\u00e9aires<\/a>\u00a0) \u00e9vacuent la\u00a0<a title=\"Propri\u00e9t\u00e9s de Steam - Qu'est-ce que Steam\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-steam-proprietes-de-steam-definition\/\">vapeur<\/a>\u00a0\u00e0 une pression bien inf\u00e9rieure \u00e0 la pression atmosph\u00e9rique\u00a0<\/span><span>(par exemple \u00e0 0,08 bar ou 8 kPa ou 1,16 psia)\u00a0<\/span><span>et dans un \u00e9tat partiellement condens\u00e9.\u00a0En unit\u00e9s relatives, il s&#8217;agit d&#8217;une pression manom\u00e9trique n\u00e9gative d&#8217;environ &#8211; 0,92 bar, &#8211; 92 kPa ou &#8211; 13,54 psig.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<div><\/div>\n<div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Pascal &#8211; Unit\u00e9 de pression. Pascal est d\u00e9fini comme un newton par m\u00e8tre carr\u00e9. Cependant, il est pratique de travailler avec des multiples du pascal: le kPa, le bar et le MPa. G\u00e9nie thermique Quelle est la pression La pression\u00a0est une mesure de la\u00a0force exerc\u00e9e\u00a0par unit\u00e9 de surface sur les limites d&#8217;une substance.\u00a0L&#8217;unit\u00e9 standard de\u00a0pression\u00a0dans &#8230; <a title=\"Qu&#8217;est-ce que Pascal &#8211; Unit\u00e9 de pression &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-pascal-unite-de-pression-definition\/\" aria-label=\"En savoir plus sur Qu&#8217;est-ce que Pascal &#8211; Unit\u00e9 de pression &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Qu&#039;est-ce que Pascal - Unit\u00e9 de pression - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"Pascal - Unit\u00e9 de pression. Pascal est d\u00e9fini comme un newton par m\u00e8tre carr\u00e9. Cependant, il est pratique de travailler avec des multiples du pascal: le kPa, le bar et le MPa. G\u00e9nie thermique\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-pascal-unite-de-pression-definition\/\" \/>\n<meta property=\"og:locale\" content=\"fr_FR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Qu&#039;est-ce que Pascal - Unit\u00e9 de pression - D\u00e9finition\" \/>\n<meta property=\"og:description\" content=\"Pascal - Unit\u00e9 de pression. Pascal est d\u00e9fini comme un newton par m\u00e8tre carr\u00e9. Cependant, il est pratique de travailler avec des multiples du pascal: le kPa, le bar et le MPa. 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