{"id":46189,"date":"2019-10-21T03:54:13","date_gmt":"2019-10-21T02:54:13","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quest-ce-que-la-loi-des-gaz-parfaits-definition\/"},"modified":"2020-02-26T15:00:28","modified_gmt":"2020-02-26T14:00:28","slug":"quest-ce-que-la-loi-des-gaz-parfaits-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-loi-des-gaz-parfaits-definition\/","title":{"rendered":"Qu&#8217;est-ce que la loi des gaz parfaits &#8211; D\u00e9finition"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Loi des gaz parfaits (pV = nRT &#8211; Equation des gaz parfaits).\u00a0Selon la loi des gaz parfaits, la pression varie lin\u00e9airement avec la temp\u00e9rature et la quantit\u00e9, et inversement avec le volume.\u00a0G\u00e9nie thermique<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Mod\u00e8le de gaz parfait<\/h2>\n<p>Le\u00a0<strong>mod\u00e8le de gaz parfait<\/strong>\u00a0est utilis\u00e9 pour pr\u00e9dire le comportement des gaz et constitue l&#8217;un des mod\u00e8les de substances les plus utiles et les plus couramment utilis\u00e9s jamais d\u00e9velopp\u00e9s.\u00a0On m&#8217;a d\u00e9couvert que, si nous confinons des\u00a0<strong>\u00e9chantillons d&#8217;une mole<\/strong>\u00a0de\u00a0<strong>divers gaz<\/strong>\u00a0dans\u00a0<strong>un volume identique<\/strong>\u00a0et les maintenons \u00e0 la\u00a0<strong>m\u00eame temp\u00e9rature<\/strong>\u00a0, leurs\u00a0<strong>pressions<\/strong>\u00a0mesur\u00e9es\u00a0<strong>sont presque identiques<\/strong>\u00a0.\u00a0De plus, lorsque nous confinons des gaz \u00e0 des densit\u00e9s inf\u00e9rieures, les diff\u00e9rences ont tendance \u00e0 dispara\u00eetre.\u00a0Il a \u00e9t\u00e9 constat\u00e9 que ces gaz ont tendance \u00e0 ob\u00e9ir \u00e0 la relation suivante, appel\u00e9e\u00a0<strong>loi des gaz parfaits<\/strong>\u00a0:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Enthalpy-example-min.png\"><img loading=\"lazy\" class=\"size-medium wp-image-16678 alignright lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Enthalpy-example-min-224x300.png\" alt=\"Enthalpie - Exemple - Un piston sans friction\" width=\"224\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Enthalpy-example-min-224x300.png\" \/><\/a><\/p>\n<p><strong><em>pV = nRT<\/em><\/strong><\/p>\n<p>o\u00f9:<\/p>\n<p><strong><em>p<\/em><\/strong>\u00a0est la<a title=\"Pression absolue\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/absolute-pressure\/\"><strong>\u00a0pression absolue<\/strong><\/a>\u00a0du gaz<\/p>\n<p><strong><em>n<\/em><\/strong>\u00a0est la<strong>\u00a0quantit\u00e9<\/strong>\u00a0de substance<\/p>\n<p><strong><em>T<\/em><\/strong>\u00a0est la<a title=\"\u00c9chelle Kelvin - Temp\u00e9rature absolue\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-temperature-physics\/kelvin-scale-absolute-temperature\/\"><strong>\u00a0temp\u00e9rature absolue<\/strong><\/a><\/p>\n<p><strong><em>V<\/em><\/strong>est le<strong><a title=\"Qu'est-ce que le volume - Physique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-volume-physics\/\">\u00a0volume<\/a><\/strong><\/p>\n<p><strong><em>R<\/em><\/strong>\u00a0est la<strong>\u00a0constante de gaz<\/strong>\u00a0id\u00e9ale ou universelle,\u00e9gale au produit de la<strong>\u00a0constante de Boltzmann<\/strong>\u00a0et de la<strong>\u00a0constante d&#8217;Avogadro.\u00a0<\/strong>La puissance de la<strong>\u00a0loi des gaz parfaits<\/strong>\u00a0r\u00e9side dans sa simplicit\u00e9.\u00a0Lorsque deux des<a title=\"Propri\u00e9t\u00e9s thermodynamiques\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/\">\u00a0variables thermodynamiques<\/a>\u00a0, p, v et T, sont donn\u00e9es, la troisi\u00e8me peut facilement \u00eatre trouv\u00e9e.<\/p>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<p><span>Le\u00a0<\/span><strong><span>mod\u00e8le de gaz parfait<\/span><\/strong><span>\u00a0est bas\u00e9 sur les hypoth\u00e8ses suivantes:<\/span><\/p>\n<ol>\n<li><span>La pression, le volume et la temp\u00e9rature d&#8217;un gaz parfait ob\u00e9issent \u00e0 la\u00a0<\/span><strong><span>loi du gaz parfait<\/span><\/strong><span>\u00a0.<\/span><\/li>\n<li><span>L&#8217;\u00a0<\/span><strong><span>\u00e9nergie interne sp\u00e9cifique<\/span><\/strong><span>\u00a0est uniquement fonction de la temp\u00e9rature:\u00a0<\/span><strong><em><span>u = u (T)<\/span><\/em><\/strong><\/li>\n<li><span>La masse molaire d&#8217;un gaz parfait est identique \u00e0 la masse molaire de la substance r\u00e9elle<\/span><\/li>\n<li><span>Les\u00a0<\/span><strong><span>chaleurs sp\u00e9cifiques<\/span><\/strong><span>\u00a0&#8211;\u00a0<\/span><strong><em><span>c\u00a0<\/span><sub><span>p<\/span><\/sub><\/em><\/strong><span>\u00a0et\u00a0<\/span><strong><em><span>c\u00a0<\/span><sub><span>v<\/span><\/sub><\/em><\/strong><span>\u00a0&#8211; sont ind\u00e9pendantes de la temp\u00e9rature ce qui signifie qu&#8217;elles sont constantes.<\/span><\/li>\n<\/ol>\n<p><span>Du point de vue microscopique, il est bas\u00e9 sur ces hypoth\u00e8ses:<\/span><\/p>\n<ol>\n<li><span>Les mol\u00e9cules du gaz sont de\u00a0<\/span><strong><span>petites sph\u00e8res dures<\/span><\/strong><span>\u00a0.<\/span><\/li>\n<li><span>Les seules forces entre les mol\u00e9cules de gaz sont celles qui d\u00e9terminent les\u00a0<\/span><strong><span>collisions ponctuelles<\/span><\/strong><span>\u00a0.<\/span><\/li>\n<li><span>Toutes les collisions sont\u00a0<\/span><a title=\"Collisions \u00e9lastiques\" href=\"https:\/\/www.nuclear-power.com\/laws-of-conservation\/law-of-conservation-of-energy\/elastic-collisions\/\"><strong><span>\u00e9lastiques<\/span><\/strong><\/a><span>\u00a0et tout mouvement est sans\u00a0<\/span><strong><span>friction<\/span><\/strong><span>\u00a0.<\/span><\/li>\n<li><span>La distance moyenne entre les mol\u00e9cules est beaucoup plus grande que la taille des mol\u00e9cules.<\/span><\/li>\n<li><span>Les mol\u00e9cules se d\u00e9placent dans des directions al\u00e9atoires.<\/span><\/li>\n<li><span>Il n&#8217;y a pas d&#8217;autre force d&#8217;attraction ou de r\u00e9pulsion entre ces mol\u00e9cules.<\/span><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-60 lgc-tablet-grid-60 lgc-mobile-grid-100 lgc-equal-heights  lgc-first\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Qu&#8217;est-ce qu&#8217;un gaz parfait<\/span><\/h2>\n<p><span>Un\u00a0<\/span><strong><span>gaz parfait<\/span><\/strong><span>\u00a0est d\u00e9fini comme celui dans lequel toutes les collisions entre atomes ou mol\u00e9cules sont\u00a0<\/span><strong><span>parfaitement \u00e9lastiques<\/span><\/strong><span>\u00a0et o\u00f9 il n&#8217;y a\u00a0<\/span><strong><span>pas de forces d&#8217;attraction intermol\u00e9culaires<\/span><\/strong><span>\u00a0.\u00a0Un gaz parfait peut \u00eatre visualis\u00e9 comme une collection de sph\u00e8res parfaitement dures qui entrent en collision mais qui, autrement, n&#8217;interagissent pas entre elles.\u00a0En r\u00e9alit\u00e9, aucun gaz r\u00e9el n&#8217;est comme un gaz parfait et donc aucun gaz r\u00e9el ne suit\u00a0compl\u00e8tement la\u00a0<\/span><strong><span>loi<\/span><\/strong><span>\u00a0ou l&#8217;\u00e9quation du\u00a0<strong>gaz parfait<\/strong>\u00a0.\u00a0\u00c0 des\u00a0<\/span><a title=\"Qu'est-ce que la temp\u00e9rature - Physique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-temperature-physique-definition\/\"><span>temp\u00e9ratures<\/span><\/a><span>\u00a0proches d&#8217;un\u00a0<\/span><a title=\"Saturation - point d'\u00e9bullition\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-saturation-point-debullition-definition\/\"><span>point d&#8217;\u00e9bullition des<\/span><\/a><span>\u00a0gaz\u00a0, augmentation de la\u00a0<\/span><a title=\"Qu'est-ce que la pression - Physique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/\"><span>pression<\/span><\/a><span>provoquera la condensation et des baisses drastiques de volume.\u00a0A des pressions tr\u00e8s \u00e9lev\u00e9es, les forces intermol\u00e9culaires d&#8217;un gaz sont importantes.\u00a0Cependant, la plupart des gaz sont en accord approximatif \u00e0 des pressions et des temp\u00e9ratures sup\u00e9rieures \u00e0 leur point d&#8217;\u00e9bullition.\u00a0La\u00a0<\/span><strong><span>loi du gaz parfait<\/span><\/strong><span>\u00a0est utilis\u00e9e par les ing\u00e9nieurs travaillant avec les gaz car elle est\u00a0<\/span><strong><span>simple \u00e0 utiliser<\/span><\/strong><span>\u00a0et se rapproche du comportement r\u00e9el du gaz.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-40 lgc-tablet-grid-40 lgc-mobile-grid-100 lgc-equal-heights  lgc-last\">\n<div class=\"inside-grid-column\"><span>[extrait xyz-ihs = &#8220;pression&#8221;]<\/span><span>Voir aussi:\u00a0<\/span><a title=\"Collisions \u00e9lastiques\" href=\"https:\/\/www.nuclear-power.com\/laws-of-conservation\/law-of-conservation-of-energy\/elastic-collisions\/\"><span>Collision \u00e9lastique<\/span><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>La deuxi\u00e8me loi de Joule<\/span><\/h2>\n<p><span>Pour tout gaz dont l&#8217;\u00e9quation d&#8217;\u00e9tat est donn\u00e9e exactement par\u00a0<\/span><em><strong><span>pV = nRT<\/span><\/strong>\u00a0<\/em><span>(ou\u00a0<\/span><em><strong><span>pv = RT<\/span><\/strong><\/em><span>\u00a0), l&#8217;\u00a0<\/span><a title=\"\u00c9nergie interne sp\u00e9cifique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/internal-energy-thermal-energy\/specific-internal-energy\/\"><strong><span>\u00e9nergie interne sp\u00e9cifique<\/span><\/strong>\u00a0<\/a><span>d\u00e9pend uniquement de la temp\u00e9rature.\u00a0Cette r\u00e8gle a \u00e9t\u00e9 d\u00e9couverte \u00e0 l&#8217;origine en 1843 par un physicien anglais\u00a0<\/span><strong><span>James Prescott Joule<\/span><\/strong><span>\u00a0exp\u00e9rimentalement pour les gaz r\u00e9els et est connue comme\u00a0<\/span><strong><span>le deuxi\u00e8me principe de Joule<\/span><\/strong><span>\u00a0:<\/span><\/p>\n<p><em><span>L&#8217;\u00e9nergie interne d&#8217;une masse fixe d&#8217;un gaz parfait ne d\u00e9pend que de sa temp\u00e9rature (et non de la pression ou du volume).<\/span><\/em><\/p>\n<p><span>L&#8217;\u00a0<\/span><a title=\"Enthalpie sp\u00e9cifique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-enthalpy\/specific-enthalpy\/\"><span>enthalpie sp\u00e9cifique<\/span><\/a><span>\u00a0d&#8217;un gaz d\u00e9crite par\u00a0<\/span><em><strong><span>pV = nRT<\/span><\/strong><\/em><span>\u00a0d\u00e9pend \u00e9galement uniquement de la temp\u00e9rature.\u00a0Notez que l&#8217;\u00a0<\/span><strong><span>enthalpie<\/span><\/strong><span>\u00a0est la quantit\u00e9 thermodynamique \u00e9quivalente \u00e0 la\u00a0<\/span><strong><span>chaleur totale<\/span><\/strong><span>\u00a0d&#8217;un syst\u00e8me.\u00a0Elle est \u00e9gale \u00e0 l&#8217;\u00e9nergie interne du syst\u00e8me plus le produit de la pression et du volume.\u00a0Dans les variables intensives, la\u00a0<\/span><strong><span>deuxi\u00e8me loi de Joule<\/span><\/strong><span>\u00a0est donc donn\u00e9e par\u00a0<\/span><em><span>h = h (T) = u (T) + pv = u (T) + RT.<\/span><\/em><\/p>\n<p><span>Ces trois \u00e9quations constituent le mod\u00e8le de gaz parfait, r\u00e9sum\u00e9 comme suit:<\/span><\/p>\n<p><em><strong><span>pv = RT<\/span><\/strong><\/em><\/p>\n<p><em><strong><span>u = u (T)<\/span><\/strong><\/em><\/p>\n<p><em><strong><span>h = h (T) = u (T) + RT<\/span><\/strong><\/em><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Loi du gaz parfait<\/span><\/h2>\n<p><span>Toute \u00e9quation qui relie la pression, la temp\u00e9rature et le volume sp\u00e9cifique d&#8217;une substance est appel\u00e9e une\u00a0<\/span><a title=\"\u00c9quation d'\u00e9tat\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-detat-definition\/\"><strong><span>\u00e9quation d&#8217;\u00e9tat<\/span><\/strong><\/a><span>\u00a0.\u00a0L&#8217;\u00a0\u00e9quation d&#8217;\u00e9tat la\u00a0plus simple et la\u00a0<\/span><strong><span>plus connue<\/span><\/strong><span>\u00a0pour les substances en phase gazeuse est l&#8217;\u00a0<\/span><strong><span>\u00e9quation<\/span><\/strong><span>\u00a0d&#8217;\u00e9tat du\u00a0<strong>gaz parfait<\/strong>\u00a0.\u00a0\u00c9mile Clapeyron l&#8217;a d\u00e9clar\u00e9 pour la premi\u00e8re fois en 1834 comme une combinaison de la loi empirique de Boyle, de la loi de Charles et de la loi d&#8217;Avogadro.\u00a0Cette \u00e9quation pr\u00e9dit le\u00a0<\/span><strong><span>comportement pvT<\/span><\/strong><span>\u00a0d&#8217;un gaz de fa\u00e7on assez pr\u00e9cise pour les gaz dilu\u00e9s ou \u00e0 basse pression.\u00a0Dans un gaz parfait, les mol\u00e9cules n&#8217;ont pas de volume et n&#8217;interagissent pas.\u00a0Selon la loi du gaz parfait, la pression varie lin\u00e9airement avec la\u00a0<\/span><strong><span>temp\u00e9rature<\/span><\/strong><span>\u00a0et la\u00a0<\/span><strong><span>quantit\u00e9<\/span><\/strong><span>\u00a0, et inversement avec le\u00a0<\/span><strong><span>volume<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><strong><i><span>pV = nRT<\/span><\/i><\/strong><\/p>\n<p><span>o\u00f9:<\/span><\/p>\n<ul>\n<li><strong><em><span>p<\/span><\/em><\/strong><span>\u00a0est la<\/span><strong><span>\u00a0pression absolue<\/span><\/strong><span>\u00a0du gaz<\/span><\/li>\n<li><strong><em><span>n<\/span><\/em><\/strong><span>\u00a0est la<\/span><strong><span>\u00a0quantit\u00e9<\/span><\/strong><span>\u00a0de substance<\/span><\/li>\n<li><strong><em><span>T<\/span><\/em><\/strong><span>\u00a0est la<\/span><strong><span>\u00a0temp\u00e9rature absolue<\/span><\/strong><\/li>\n<li><strong><em><span>V<\/span><\/em><\/strong><span>\u00a0est le<\/span><strong><span>\u00a0volume<\/span><\/strong><\/li>\n<li><strong><em><span>R<\/span><\/em>\u00a0<\/strong><span>\u00a0est la<\/span><strong><span>\u00a0constante de gaz<\/span><\/strong><span>\u00a0id\u00e9ale ou universelle,\u00e9gale au produit de la constante de Boltzmann et de la constante d&#8217;Avogadro,<\/span><\/li>\n<\/ul>\n<p><span>Dans cette \u00e9quation, le symbole R est une constante appel\u00e9e constante de\u00a0<\/span><strong><span>gaz universelle<\/span><\/strong><span>\u00a0qui a la m\u00eame valeur pour tous les gaz, \u00e0 savoir\u00a0<\/span><strong><span>R = 8,31 J \/ mol K.<\/span><\/strong><\/p>\n<p><span>La puissance de la loi du gaz parfait r\u00e9side dans sa\u00a0<\/span><strong><span>simplicit\u00e9<\/span><\/strong><span>\u00a0.\u00a0Lorsque\u00a0<\/span><strong><span>deux<\/span><\/strong><span>\u00a0variables thermodynamiques, p, v et T\u00a0<\/span><strong><span>sont\u00a0<\/span><\/strong><strong><span>donn\u00e9es<\/span><\/strong><span>\u00a0, la\u00a0<\/span><strong><span>troisi\u00e8me<\/span><\/strong><span>\u00a0peut\u00a0<\/span><strong><span>\u00eatre facilement trouv\u00e9e<\/span><\/strong><span>\u00a0.\u00a0De nombreuses conditions physiques des gaz calcul\u00e9es par les ing\u00e9nieurs correspondent \u00e0 la description ci-dessus.\u00a0Peut-\u00eatre l&#8217;utilisation la plus courante du comportement des gaz \u00e9tudi\u00e9e par les ing\u00e9nieurs est celle du processus de compression et du processus d&#8217;expansion utilisant des approximations de gaz parfaites.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Lois sur le gaz<\/span><\/h2>\n<p><span>En g\u00e9n\u00e9ral, les\u00a0<\/span><strong><span>lois des gaz<\/span><\/strong><span>\u00a0sont des\u00a0<\/span><strong><span>premi\u00e8res\u00a0<\/span><a title=\"\u00c9quation d'\u00e9tat\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-detat-definition\/\"><span>\u00e9quations d&#8217;\u00e9tat<\/span><\/a><\/strong><span>\u00a0, qui corr\u00e8lent les densit\u00e9s de gaz et de liquides aux temp\u00e9ratures et aux pressions.\u00a0Les\u00a0<\/span><strong><span>lois sur le gaz ont<\/span><\/strong><span>\u00a0\u00e9t\u00e9 compl\u00e8tement d\u00e9velopp\u00e9es \u00e0 la fin du XVIIIe si\u00e8cle.\u00a0Ces lois ou d\u00e9clarations ont\u00a0<\/span><strong><span>pr\u00e9c\u00e9d\u00e9<\/span><\/strong><span>\u00a0la\u00a0<\/span><strong><span>loi du gaz parfait<\/span><\/strong><span>\u00a0, car individuellement ces lois sont consid\u00e9r\u00e9es comme des cas particuliers de l&#8217;\u00e9quation du gaz parfait, avec une ou plusieurs des variables maintenues constantes.\u00a0Puisqu&#8217;ils ont \u00e9t\u00e9 presque compl\u00e8tement remplac\u00e9s par l&#8217;\u00e9quation du gaz parfait, il n&#8217;est pas habituel que les \u00e9l\u00e8ves apprennent ces lois en d\u00e9tail.\u00a0L&#8217;\u00a0<\/span><strong><span>\u00e9quation du gaz parfait a<\/span><\/strong><span>\u00a0\u00e9t\u00e9 \u00e9nonc\u00e9e pour la premi\u00e8re fois par \u00c9mile Clapeyron en 1834 comme une combinaison de ces lois:<\/span><\/p>\n<ul>\n<li><a title=\"Loi de Boyle-Mariotte\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-loi-boyle-mariotte-definition\/\"><span>Loi de Boyle-Mariotte<\/span><\/a><\/li>\n<li><a title=\"La loi de Charles\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-loi-de-charles-definition\/\"><span>La loi de Charles<\/span><\/a><\/li>\n<li><a title=\"Loi de Guy-Lussac\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-loi-gay-lussac-definition\/\"><span>Loi de Guy-Lussac<\/span><\/a><\/li>\n<li><a title=\"Loi d'Avogadro\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-loi-davogadro-definition\/\"><span>Loi d&#8217;Avogadro<\/span><\/a><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Exemple: Loi des gaz parfaits &#8211; Compression de gaz \u00e0 l&#8217;int\u00e9rieur d&#8217;un pressuriseur<\/span><\/h2>\n<figure id=\"attachment_430\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-430\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/pressurizer_nuclear.png\"><img loading=\"lazy\" class=\"size-medium wp-image-430 lazy-loaded\" src=\"https:\/\/www.thermal-engineering.org\/wp-content\/uploads\/2019\/05\/neutron_spectrum_reactor-300x201.jpg\" alt=\"pressuriseur\" width=\"238\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/www.thermal-engineering.org\/wp-content\/uploads\/2019\/05\/neutron_spectrum_reactor-300x201.jpg\" \/><\/a><figcaption id=\"caption-attachment-430\" class=\"wp-caption-text\"><span>Un pressuriseur est un \u00e9l\u00e9ment cl\u00e9 des REP.<\/span><\/figcaption><\/figure>\n<p><strong><span>La pression dans le circuit primaire<\/span><\/strong><span>\u00a0des\u00a0<\/span><a title=\"PWR - R\u00e9acteur \u00e0 eau sous pression\" href=\"https:\/\/www.nuclear-power.com\/pwr-pressurized-water-reactor\/\"><span>REP<\/span><\/a><span>\u00a0est maintenue par un\u00a0<\/span><a title=\"Pressuriseur\" href=\"https:\/\/www.nuclear-power.com\/pressurizer\/\"><strong><span>pressuriseur<\/span><\/strong><\/a><span>\u00a0, un r\u00e9cipient s\u00e9par\u00e9 qui est connect\u00e9 au circuit primaire (jambe chaude) et partiellement rempli d&#8217;eau qui est chauff\u00e9e \u00e0 la\u00a0<\/span><a title=\"Saturation - point d'\u00e9bullition\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-saturation-point-debullition-definition\/\"><strong><span>temp\u00e9rature de saturation<\/span><\/strong><\/a><span>\u00a0(point d&#8217;\u00e9bullition) pour la pression souhait\u00e9e par une\u00a0<\/span><strong><span>alimentation \u00e9lectrique<\/span><\/strong><span>\u00a0immerg\u00e9e\u00a0<strong>radiateurs<\/strong>\u00a0.\u00a0Pendant le chauffage de l&#8217;installation, le pressuriseur peut \u00eatre rempli d&#8217;azote au lieu de\u00a0<\/span><a title=\"Vapeur s\u00e8che\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/materials-nuclear-engineering\/properties-steam-what-is-steam\/dry-steam\/\"><span>vapeur satur\u00e9e<\/span><\/a><span>\u00a0.<\/span><\/p>\n<p><span>Supposons qu&#8217;un pressuriseur contienne\u00a0<\/span><strong><span>12 m\u00a0<\/span><\/strong><strong><sup><span>3<\/span><\/sup><\/strong><span>\u00a0d&#8217;azote \u00e0\u00a0<\/span><strong><span>20 \u00b0 C<\/span><\/strong><span>\u00a0et\u00a0<\/span><strong><span>15 bar<\/span><\/strong><span>\u00a0.\u00a0La temp\u00e9rature est port\u00e9e \u00e0\u00a0<\/span><strong><span>35 \u00b0 C<\/span><\/strong><span>\u00a0et le volume est r\u00e9duit \u00e0\u00a0<\/span><strong><span>8,5 m\u00a0<\/span><\/strong><strong><sup><span>3<\/span><\/sup><\/strong><span>\u00a0.\u00a0Quelle est la pression finale du gaz \u00e0 l&#8217;int\u00e9rieur du pressuriseur?\u00a0Supposons que le gaz soit id\u00e9al.<\/span><\/p>\n<p><strong><span>Solution:<\/span><\/strong><\/p>\n<p><span>Puisque le gaz est id\u00e9al, nous pouvons utiliser la loi du gaz parfait pour relier ses param\u00e8tres, \u00e0 la fois dans l&#8217;\u00a0<\/span><strong><span>\u00e9tat initial i<\/span><\/strong><span>\u00a0et dans l&#8217;\u00a0<\/span><strong><span>\u00e9tat final f<\/span><\/strong><span>\u00a0.\u00a0Donc:<\/span><\/p>\n<p><strong><em><span>p\u00a0<\/span><sub><span>init<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>init<\/span><\/sub><span>\u00a0= nRT\u00a0<\/span><sub><span>init<\/span><\/sub><\/em><\/strong><\/p>\n<p><span>et<\/span><\/p>\n<p><strong><em><span>p\u00a0<\/span><sub><span>final<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>final<\/span><\/sub><span>\u00a0= nRT\u00a0<\/span><sub><span>final<\/span><\/sub><\/em><\/strong><\/p>\n<p><span>En divisant la deuxi\u00e8me \u00e9quation par la premi\u00e8re \u00e9quation et en r\u00e9solvant pour\u00a0<\/span><strong><em><span>p\u00a0<\/span><sub><span>f<\/span><\/sub><\/em><\/strong><span>\u00a0on obtient:<\/span><\/p>\n<p><strong><em><span>p\u00a0<\/span><sub><span>final<\/span><\/sub><span>\u00a0= p\u00a0<\/span><sub><span>init<\/span><\/sub><span>\u00a0T\u00a0<\/span><sub><span>final<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>init<\/span><\/sub><span>\u00a0\/ T\u00a0<\/span><sub><span>init<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>final<\/span><\/sub><\/em><\/strong><\/p>\n<p><span>Notez que nous ne pouvons pas convertir les unit\u00e9s de volume et de pression en unit\u00e9s SI de base, car elles s&#8217;annulent mutuellement.\u00a0D&#8217;un autre c\u00f4t\u00e9, nous devons utiliser Kelvins au lieu de degr\u00e9s Celsius.\u00a0Donc T\u00a0<\/span><sub><span>init<\/span><\/sub><span>\u00a0= 293 K et T\u00a0<\/span><sub><span>final<\/span><\/sub><span>\u00a0= 308 K.<\/span><\/p>\n<p><span>Il s&#8217;ensuit que la pression r\u00e9sultante dans l&#8217;\u00e9tat final sera:<\/span><\/p>\n<p><strong><em><span>p\u00a0<\/span><sub><span>final<\/span><\/sub>\u00a0<\/em><\/strong><em><span>= (15 bar) x (308 K) x (12 m\u00a0<\/span><\/em><em><sup><span>3<\/span><\/sup><span>\u00a0) \/ (293 K) x (8,5 m\u00a0<\/span><sup><span>3<\/span><\/sup><\/em><em><span>\u00a0) =\u00a0<\/span><\/em><strong><em><span>22 bar<\/span><\/em><\/strong><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Validit\u00e9 de la loi des gaz parfaits<\/span><\/h2>\n<p><span>Puisque\u00a0<\/span><strong><span>le gaz parfait<\/span><\/strong><span>\u00a0est d\u00e9fini comme celui dans lequel toutes les collisions entre atomes ou mol\u00e9cules sont parfaitement \u00e9lastiques et o\u00f9 il n&#8217;y a pas de forces d&#8217;attraction intermol\u00e9culaires, il n&#8217;existe pas dans la nature de gaz vraiment id\u00e9al.\u00a0En revanche, tous les gaz r\u00e9els approchent de l\u2019\u00e9tat id\u00e9al\u00a0<\/span><strong><span>\u00e0 basse pression (densit\u00e9)<\/span><\/strong><span>\u00a0.\u00a0A basse pression, les mol\u00e9cules sont suffisamment \u00e9loign\u00e9es pour ne pas interagir les unes avec les autres.<\/span><\/p>\n<p><span>En d&#8217;autres termes, la\u00a0<\/span><strong><span>loi des gaz parfaits<\/span><\/strong><span>\u00a0n&#8217;est pr\u00e9cise qu&#8217;\u00e0\u00a0<\/span><strong><span>des pressions relativement basses<\/span><\/strong><span>\u00a0(par rapport \u00e0 la\u00a0<\/span><a title=\"Pression critique de l'eau\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/critical-pressure-of-water\/\"><span>pression critique p\u00a0<\/span><sub><span>cr<\/span><\/sub><\/a><span>\u00a0) et \u00e0\u00a0<\/span><strong><span>des temp\u00e9ratures \u00e9lev\u00e9es<\/span><\/strong><span>\u00a0(par rapport \u00e0 la\u00a0<\/span><a title=\"Point critique de l'eau\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/materials-nuclear-engineering\/properties-of-water\/critical-point-of-water\/\"><span>temp\u00e9rature critique T\u00a0<\/span><sub><span>cr<\/span><\/sub><\/a><span>\u00a0).\u00a0\u00c0 ces param\u00e8tres, le\u00a0<\/span><strong><span>facteur de compressibilit\u00e9,\u00a0<\/span><em><span>Z = pv \/ RT<\/span><\/em><\/strong><span>\u00a0, est d&#8217;\u00a0<\/span><strong><span>environ 1<\/span><\/strong><span>\u00a0.\u00a0Le facteur de compressibilit\u00e9 est utilis\u00e9 pour tenir compte de l&#8217;\u00e9cart par rapport \u00e0 la situation id\u00e9ale.\u00a0Ce facteur de correction d\u00e9pend de la pression et de la temp\u00e9rature pour chaque gaz consid\u00e9r\u00e9.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>\u00c9nergie interne d&#8217;un gaz parfait<\/span><\/h2>\n<p><span>L&#8217;\u00a0<\/span><a href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lenergie-interne-energie-thermique-definition\/\"><strong><span>\u00e9nergie interne<\/span><\/strong><\/a><span>\u00a0est le total de toute l&#8217;\u00e9nergie associ\u00e9e au mouvement des atomes ou des mol\u00e9cules dans le syst\u00e8me.\u00a0<\/span><strong><span>Les formes microscopiques<\/span><\/strong><span>\u00a0d&#8217;\u00e9nergie comprennent celles dues \u00e0 la\u00a0<\/span><strong><span>rotation<\/span><\/strong><span>\u00a0, aux\u00a0<\/span><strong><span>vibrations<\/span><\/strong><span>\u00a0, \u00e0 la\u00a0<\/span><strong><span>traduction<\/span><\/strong><span>\u00a0et aux\u00a0<\/span><strong><span>interactions<\/span><\/strong><span>\u00a0entre les mol\u00e9cules d&#8217;une substance.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Gaz monoatomique &#8211; \u00c9nergie interne<\/span><\/h2>\n<p><span>Pour un\u00a0<\/span><strong><span>gaz parfait monatomique<\/span><\/strong><span>\u00a0(tel que l&#8217;h\u00e9lium, le n\u00e9on ou l&#8217;argon), la seule contribution \u00e0 l&#8217;\u00e9nergie provient de\u00a0<\/span><strong><span>l&#8217;\u00e9nergie cin\u00e9tique<\/span><\/strong><span>\u00a0de\u00a0<strong>translation<\/strong>\u00a0.\u00a0L&#8217;\u00e9nergie cin\u00e9tique de translation moyenne d&#8217;un seul atome\u00a0<\/span><strong><span>ne<\/span><\/strong><span>\u00a0d\u00e9pend\u00a0<strong>que<\/strong>\u00a0de la\u00a0<\/span><strong><span>temp\u00e9rature<\/span><\/strong><span>\u00a0du\u00a0<strong>gaz<\/strong>\u00a0et est donn\u00e9e par l&#8217;\u00e9quation:<\/span><\/p>\n<p><strong><em><span>K\u00a0<\/span><sub><span>moy<\/span><\/sub><span>\u00a0= 3\/2 kT.<\/span><\/em><\/strong><\/p>\n<p><span>L&#8217;\u00e9nergie interne de n moles d&#8217;un gaz monatomique id\u00e9al (un atome par mol\u00e9cule) est \u00e9gale \u00e0 l&#8217;\u00e9nergie cin\u00e9tique moyenne par mol\u00e9cule multipli\u00e9e par le nombre total de mol\u00e9cules, N:<\/span><\/p>\n<p><em><span>E\u00a0<\/span><sub><span>int<\/span><\/sub><span>\u00a0= 3\/2 NkT = 3\/2 nRT<\/span><\/em><\/p>\n<p><span>o\u00f9 n est le nombre de moles.\u00a0<\/span><strong><span>Chaque direction<\/span><\/strong><span>\u00a0(x, y et z) contribue\u00a0<\/span><strong><em><span>(1\/2) nRT<\/span><\/em>\u00a0<\/strong><span>\u00e0 l&#8217;\u00a0<\/span><strong><span>\u00e9nergie interne<\/span><\/strong><span>\u00a0.\u00a0C&#8217;est l\u00e0\u00a0<\/span><strong><span>qu&#8217;intervient l&#8217;id\u00e9e d&#8217;\u00e9quipartition d&#8217;\u00e9nergie<\/span><\/strong><span>\u00a0&#8211; toute autre contribution \u00e0 l&#8217;\u00e9nergie doit \u00e9galement contribuer\u00a0<\/span><strong><em><span>(1\/2) nRT<\/span><\/em><\/strong><span>\u00a0.\u00a0Comme on peut le voir, l&#8217;\u00e9nergie interne d&#8217;un gaz parfait ne\u00a0<\/span><strong><span>d\u00e9pend que de la temp\u00e9rature<\/span><\/strong><span>\u00a0et du nombre de moles de gaz.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Mol\u00e9cule diatomique &#8211; \u00c9nergie interne<\/span><\/h2>\n<p><span>Si les mol\u00e9cules de gaz contiennent plus d&#8217;un atome, il existe\u00a0<\/span><strong><span>trois directions de translation<\/span><\/strong><span>\u00a0et\u00a0<\/span><strong><span>l&#8217;\u00e9nergie cin\u00e9tique de rotation<\/span><\/strong><span>\u00a0contribue \u00e9galement, mais uniquement pour les rotations autour de deux des trois axes perpendiculaires.\u00a0Les cinq contributions \u00e0 l&#8217;\u00e9nergie (cinq degr\u00e9s de libert\u00e9) donnent:<\/span><\/p>\n<p><strong><span>Gaz id\u00e9al diatomique:<\/span><\/strong><\/p>\n<p><em><span>E\u00a0<\/span><sub><span>int<\/span><\/sub><span>\u00a0= 5\/2 NkT = 5\/2 nRT<\/span><\/em><\/p>\n<p><span>Ceci n&#8217;est qu&#8217;une approximation et s&#8217;applique aux temp\u00e9ratures interm\u00e9diaires.\u00a0<\/span><strong><span>Aux basses temp\u00e9ratures,<\/span><\/strong><span>\u00a0seule l&#8217;\u00a0<\/span><strong><span>\u00e9nergie cin\u00e9tique de translation contribue<\/span><\/strong><span>\u00a0, et \u00e0 des temp\u00e9ratures plus \u00e9lev\u00e9es, deux contributions suppl\u00e9mentaires (\u00e9nergie cin\u00e9tique et potentielle) proviennent des vibrations.\u00a0L&#8217;\u00a0<\/span><strong><span>\u00e9nergie interne sera plus grande<\/span><\/strong><span>\u00a0\u00e0 une temp\u00e9rature donn\u00e9e que pour un gaz monoatomique, mais elle ne restera fonction que de la temp\u00e9rature pour un gaz parfait.<\/span><\/p>\n<p><span>L&#8217;\u00e9nergie interne des gaz r\u00e9els d\u00e9pend \u00e9galement principalement de la temp\u00e9rature, mais de la m\u00eame mani\u00e8re que la\u00a0<\/span><strong><span>loi des gaz parfaits<\/span><\/strong><span>\u00a0, l&#8217;\u00e9nergie interne des gaz r\u00e9els d\u00e9pend \u00e9galement quelque peu de la\u00a0<\/span><strong><span>pression<\/span><\/strong><span>\u00a0et du\u00a0<\/span><strong><span>volume<\/span><\/strong><span>\u00a0.\u00a0Tous les gaz r\u00e9els approchent de l&#8217;\u00e9tat id\u00e9al \u00e0 de faibles pressions (densit\u00e9s).\u00a0A basse pression, les mol\u00e9cules sont suffisamment \u00e9loign\u00e9es pour ne pas interagir les unes avec les autres.\u00a0L&#8217;\u00e9nergie interne des liquides et des solides est assez compliqu\u00e9e, car elle comprend\u00a0<\/span><strong><span>l&#8217;\u00e9nergie potentielle \u00e9lectrique<\/span><\/strong><span>\u00a0associ\u00e9e aux forces (ou\u00a0<\/span><strong><span>liaisons chimiques<\/span><\/strong><span>\u00a0) entre les atomes et les mol\u00e9cules.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Chaleur sp\u00e9cifique \u00e0 volume et pression constants<\/span><\/h2>\n<p><strong><span>La chaleur sp\u00e9cifique<\/span><\/strong><span>\u00a0est une propri\u00e9t\u00e9 li\u00e9e \u00e0\u00a0<\/span><strong><span>l&#8217;\u00e9nergie interne<\/span><\/strong><span>\u00a0qui est tr\u00e8s importante en thermodynamique.\u00a0Les\u00a0<\/span><strong><span>propri\u00e9t\u00e9s intensives\u00a0<\/span><em><span>c\u00a0<\/span><sub><span>v<\/span><\/sub><\/em><\/strong><span>\u00a0et\u00a0<\/span><em><strong><span>c\u00a0<\/span><sub><span>p<\/span><\/sub><\/strong><\/em><span>\u00a0sont d\u00e9finies pour les substances compressibles pures et simples comme des d\u00e9riv\u00e9es partielles de l&#8217;\u00a0<\/span><strong><span>\u00e9nergie interne\u00a0<\/span><em><span>u (T, v)<\/span><\/em><\/strong><span>\u00a0et de l&#8217;\u00a0<\/span><strong><span>enthalpie\u00a0<\/span><em><span>h (T, p)<\/span><\/em><\/strong><span>\u00a0, respectivement:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Specific-Heat-at-Constant-Volume-and-Constant-Pressure.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-16806 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Specific-Heat-at-Constant-Volume-and-Constant-Pressure.png\" alt=\"Chaleur sp\u00e9cifique \u00e0 volume et pression constants\" width=\"106\" height=\"138\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Specific-Heat-at-Constant-Volume-and-Constant-Pressure.png\" \/><\/a><\/p>\n<p><span>o\u00f9 les indices\u00a0<\/span><strong><span>v<\/span><\/strong><span>\u00a0et\u00a0<\/span><strong><span>p<\/span><\/strong><span>\u00a0d\u00e9signent les variables maintenues fixes pendant la diff\u00e9renciation.\u00a0Les propri\u00e9t\u00e9s\u00a0<\/span><strong><span>c\u00a0<\/span><sub><span>v<\/span><\/sub>\u00a0<\/strong><span>et\u00a0<\/span><strong><span>c\u00a0<\/span><sub><span>p<\/span><\/sub><\/strong><span>\u00a0sont appel\u00e9es\u00a0<\/span><strong><span>chaleurs sp\u00e9cifiques<\/span><\/strong><span>\u00a0(ou\u00a0<\/span><strong><span>capacit\u00e9s calorifiques<\/span><\/strong><span>\u00a0) car dans certaines conditions sp\u00e9ciales, elles relient le changement de temp\u00e9rature d&#8217;un syst\u00e8me \u00e0 la quantit\u00e9 d&#8217;\u00e9nergie ajout\u00e9e par transfert de chaleur.\u00a0Les unit\u00e9s SI sont\u00a0<\/span><strong><span>J \/ kg K<\/span><\/strong><span>\u00a0ou\u00a0<\/span><strong><span>J \/ mole K<\/span><\/strong><span>\u00a0.\u00a0Deux chaleurs sp\u00e9cifiques sont d\u00e9finies pour les gaz, une pour\u00a0<\/span><strong><span>un volume constant (c\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0)<\/span><\/strong><span>\u00a0et une pour\u00a0<\/span><strong><span>une pression constante (c\u00a0<\/span><sub><span>p<\/span><\/sub><span>\u00a0)<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Molar-specific-heats-ideal-gas.png\"><img loading=\"lazy\" class=\"alignright size-full wp-image-16807 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Molar-specific-heats-ideal-gas.png\" alt=\"Chaleur sp\u00e9cifique aux molaires - gaz parfait\" width=\"353\" height=\"251\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Molar-specific-heats-ideal-gas.png\" \/><\/a><span>Selon la\u00a0<\/span><strong><span>premi\u00e8re loi de la thermodynamique<\/span><\/strong><span>\u00a0, pour un proc\u00e9d\u00e9 \u00e0 volume constant avec un gaz parfait monatomique, la chaleur sp\u00e9cifique molaire sera:<\/span><\/p>\n<p><strong><em><span>C\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0= 3 \/ 2R = 12,5 J \/ mol K<\/span><\/em><\/strong><\/p>\n<p><span>car<\/span><\/p>\n<p><strong><em><span>U = 3 \/ 2nRT<\/span><\/em><\/strong><\/p>\n<p><span>On peut d\u00e9duire que la\u00a0<\/span><strong><span>chaleur sp\u00e9cifique molaire<\/span><\/strong><span>\u00a0\u00e0 pression constante est:<\/span><\/p>\n<p><em><strong><span>C\u00a0<\/span><sub><span>p<\/span><\/sub><span>\u00a0= C\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0+ R = 5 \/ 2R = 20,8 J \/ mol K<\/span><\/strong><\/em><\/p>\n<p><span>Ce\u00a0<\/span><strong><em><span>C\u00a0<\/span><sub><span>p<\/span><\/sub><\/em><\/strong><span>\u00a0est sup\u00e9rieur \u00e0 la chaleur sp\u00e9cifique molaire \u00e0 volume constant\u00a0<\/span><strong><em><span>C\u00a0<\/span><sub><span>v<\/span><\/sub><\/em><\/strong><span>\u00a0, car il faut maintenant fournir de l&#8217;\u00e9nergie\u00a0<\/span><strong><span>non seulement<\/span><\/strong><span>\u00a0pour\u00a0<\/span><strong><span>\u00e9lever la temp\u00e9rature<\/span><\/strong><span>\u00a0du gaz mais aussi pour que le\u00a0<\/span><strong><span>gaz fonctionne<\/span><\/strong><span>\u00a0car dans ce cas le volume change.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>La relation de Mayer &#8211; La formule de Mayer<\/span><\/h2>\n<p><span>Julius Robert Mayer, chimiste et physicien allemand, a \u00e9tabli une relation entre la\u00a0<\/span><strong><span>chaleur sp\u00e9cifique \u00e0<\/span><\/strong><span>\u00a0pression\u00a0<strong>constante<\/strong>\u00a0et la\u00a0<\/span><strong><span>chaleur sp\u00e9cifique \u00e0 volume constant<\/span><\/strong><span>\u00a0pour un gaz parfait.\u00a0Il a \u00e9tudi\u00e9 le fait que la capacit\u00e9 thermique sp\u00e9cifique d&#8217;un gaz \u00e0 pression constante (C\u00a0<\/span><sub><span>p<\/span><\/sub><span>\u00a0) est l\u00e9g\u00e8rement sup\u00e9rieure \u00e0 celle \u00e0 volume constant (C\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0).\u00a0Il a estim\u00e9 que ce\u00a0<\/span><strong><em><span>C\u00a0<\/span><\/em><\/strong><strong><em><sub><span>p<\/span><\/sub><\/em><\/strong><span>\u00a0est sup\u00e9rieur \u00e0 la chaleur sp\u00e9cifique molaire \u00e0 volume constant\u00a0<\/span><strong><em><span>C\u00a0<\/span><\/em><\/strong><strong><em><sub><span>v<\/span><\/sub><\/em><\/strong><span>\u00a0, car l&#8217;\u00e9nergie doit maintenant \u00eatre fournie\u00a0<\/span><strong><span>non seulement<\/span><\/strong><span>\u00a0pour\u00a0<\/span><strong><span>\u00e9lever la temp\u00e9rature<\/span><\/strong><span>\u00a0du gaz mais aussi pour que le\u00a0<\/span><strong><span>gaz fonctionne,<\/span><\/strong><span>\u00a0car dans ce cas, le volume change.\u00a0Selon le<\/span><strong><span>La relation de Mayer<\/span><\/strong><span>\u00a0ou la\u00a0<\/span><strong><span>formule de Mayer<\/span><\/strong><span>\u00a0la diff\u00e9rence entre ces deux capacit\u00e9s calorifiques est \u00e9gale \u00e0 la constante de gaz universelle, donc la chaleur sp\u00e9cifique molaire \u00e0 pression constante est \u00e9gale:<\/span><\/p>\n<p><strong><span>C\u00a0<\/span><sub><span>p<\/span><\/sub><span>\u00a0= C\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0+ R<\/span><\/strong><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Loi des gaz parfaits (pV = nRT &#8211; Equation des gaz parfaits).\u00a0Selon la loi des gaz parfaits, la pression varie lin\u00e9airement avec la temp\u00e9rature et la quantit\u00e9, et inversement avec le volume.\u00a0G\u00e9nie thermique Mod\u00e8le de gaz parfait Le\u00a0mod\u00e8le de gaz parfait\u00a0est utilis\u00e9 pour pr\u00e9dire le comportement des gaz et constitue l&#8217;un des mod\u00e8les de substances &#8230; <a title=\"Qu&#8217;est-ce que la loi des gaz parfaits &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-loi-des-gaz-parfaits-definition\/\" aria-label=\"En savoir plus sur Qu&#8217;est-ce que la loi des gaz parfaits &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Qu&#039;est-ce que la loi des gaz parfaits - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"Loi des gaz parfaits (pV = nRT - Equation des gaz parfaits). 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