{"id":46808,"date":"2019-11-01T19:57:29","date_gmt":"2019-11-01T18:57:29","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quelle-est-la-methode-du-coefficient-de-resistance-methode-k-tete-en-exces-definition\/"},"modified":"2020-03-02T17:09:00","modified_gmt":"2020-03-02T16:09:00","slug":"quelle-est-la-methode-du-coefficient-de-resistance-methode-k-tete-en-exces-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-methode-du-coefficient-de-resistance-methode-k-tete-en-exces-definition\/","title":{"rendered":"Quelle est la m\u00e9thode du coefficient de r\u00e9sistance &#8211; M\u00e9thode K &#8211; T\u00eate en exc\u00e8s &#8211; D\u00e9finition"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">La m\u00e9thode du coefficient de r\u00e9sistance (ou m\u00e9thode K ou m\u00e9thode de la t\u00eate exc\u00e9dentaire) permet \u00e0 l&#8217;utilisateur de d\u00e9crire la perte de charge \u00e0 travers un coude ou un raccord par un nombre sans dimension &#8211; K. Ing\u00e9nierie thermique<\/div>\n<\/div>\n<div><\/div>\n<div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-60 lgc-tablet-grid-60 lgc-mobile-grid-100 lgc-equal-heights  lgc-first\">\n<div class=\"inside-grid-column\">\n<h2>M\u00e9thode du coefficient de r\u00e9sistance \u2013 M\u00e9thode K<\/h2>\n<p><strong><br \/>\nLa m\u00e9thode de coefficient de r\u00e9sistance (ou K-proc\u00e9d\u00e9, ou proc\u00e9d\u00e9 de t\u00eate en\u00a0exc\u00e8s)<\/strong>\u00a0permet \u00e0\u00a0l\u2019utilisateur de d\u00e9crire la\u00a0<strong>chute de pression<\/strong>\u00a0\u00e0 travers un coude ou un raccord par un\u00a0<strong>num\u00e9ro de dimension \u2013 K<\/strong>\u00a0.\u00a0Ce nombre sans dimension (K) peut \u00eatre incorpor\u00e9 dans l\u2019\u00a0<a title=\"\u00c9quation de Darcy-Weisbach\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/darcy-weisbach-equation\/\"><strong>\u00e9quation de Darcy-Weisbach<\/strong><\/a>\u00a0d\u2019une mani\u00e8re tr\u00e8s similaire \u00e0 la m\u00e9thode de la longueur \u00e9quivalente.\u00a0Au lieu de donn\u00e9es de longueur \u00e9quivalente dans ce cas, le nombre sans dimension (K) est utilis\u00e9 pour caract\u00e9riser le raccord sans le lier aux propri\u00e9t\u00e9s du tuyau.<\/p>\n<p>La valeur K repr\u00e9sente le\u00a0<strong>multiple des\u00a0<a title=\"T\u00eate de vitesse\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/velocity-head\/\">t\u00eates<\/a><\/strong><strong>\u00a0de\u00a0<\/strong><strong><a title=\"Velocity Head\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/velocity-head\/\">vitesse<\/a><\/strong>\u00a0qui seront perdues par le fluide traversant le raccord.\u00a0L\u2019\u00e9quation de calcul de la perte de charge de l\u2019\u00e9l\u00e9ment hydraulique est donc:<br \/>\n<a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-method.png\"><img loading=\"lazy\" class=\"size-full wp-image-14691 aligncenter lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-method.png\" alt=\"M\u00e9thode de la valeur K\" width=\"133\" height=\"63\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-method.png\" \/><\/a>Par cons\u00e9quent, l\u2019\u00e9quation pour le calcul de la perte de pression de l\u2019ensemble du syst\u00e8me hydraulique est:<br \/>\n<a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-head-loss.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14690 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-head-loss.png\" alt=\"Valeur K - perte de charge\" width=\"240\" height=\"61\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-head-loss.png\" \/><\/a><br \/>\nLa\u00a0<strong>valeur K<\/strong>\u00a0peut \u00eatre caract\u00e9ris\u00e9e pour diff\u00e9rents\u00a0<a title=\"R\u00e9gime de flux\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/flow-regime\/\">r\u00e9gimes d\u2019\u00e9coulement<\/a>\u00a0(c\u2019est-\u00e0-dire selon le\u00a0<a title=\"Le num\u00e9ro de Reynold\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\">nombre de Reynolds<\/a>\u00a0), ce qui la rend plus pr\u00e9cise que la m\u00e9thode de la longueur \u00e9quivalente.<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-K-values-valves-elbows-bends.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14692 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-K-values-valves-elbows-bends.png\" alt=\"tableau des valeurs K - soupapes, coudes, coudes\" width=\"598\" height=\"582\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-K-values-valves-elbows-bends.png\" \/><\/a><\/p>\n<p>Il existe plusieurs autres m\u00e9thodes pour calculer la perte de pression des raccords, ces m\u00e9thodes sont\u00a0<strong>plus sophistiqu\u00e9es<\/strong>\u00a0et \u00e9galement\u00a0<strong>plus pr\u00e9cises<\/strong>\u00a0:<\/p>\n<ul>\n<li><strong>M\u00e9thode 2K<\/strong>\u00a0.\u00a0La m\u00e9thode 2K est une technique d\u00e9velopp\u00e9e par Hooper BW pour pr\u00e9dire la perte de charge dans un coude, une valve ou un t\u00e9.\u00a0La m\u00e9thode 2K am\u00e9liore la m\u00e9thode de la t\u00eate exc\u00e9dentaire en caract\u00e9risant la variation de la perte de pression due \u00e0 la\u00a0<strong>variation du nombre de Reynolds<\/strong>\u00a0.\u00a0La m\u00e9thode 2-K est avantageuse par rapport \u00e0 une autre m\u00e9thode, en particulier dans la\u00a0<a title=\"\u00c9coulement laminaire - \u00c9coulement visqueux\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lecoulement-laminaire-ecoulement-visqueux-definition\/\"><strong>r\u00e9gion d\u2019\u00e9coulement laminaire<\/strong><\/a>\u00a0.<a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/2K-method.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14689 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/2K-method.png\" alt=\"M\u00e9thode 2K\" width=\"199\" height=\"49\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/2K-method.png\" \/><\/a><\/li>\n<\/ul>\n<ul>\n<li><strong>M\u00e9thode 3K<\/strong>\u00a0.\u00a0La m\u00e9thode 3K (par Ron Darby en 1999) am\u00e9liore encore la pr\u00e9cision du calcul de la perte de pression en caract\u00e9risant \u00e9galement le\u00a0<strong>changement des proportions g\u00e9om\u00e9triques<\/strong>\u00a0d\u2019un raccord \u00e0 mesure que sa taille change.\u00a0Cela rend la m\u00e9thode 3K particuli\u00e8rement\u00a0<strong>pr\u00e9cise pour un syst\u00e8me avec de grands raccords<\/strong>\u00a0.<a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/3K-method.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14688 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/3K-method.png\" alt=\"M\u00e9thode 3K\" width=\"215\" height=\"58\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/3K-method.png\" \/><\/a><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-40 lgc-tablet-grid-40 lgc-mobile-grid-100 lgc-equal-heights  lgc-last\">\n<div class=\"inside-grid-column\">\n<h2>Sommaire:<\/h2>\n<ul>\n<li>La perte de charge du syst\u00e8me hydraulique est divis\u00e9e en\u00a0<strong>deux cat\u00e9gories principales<\/strong>\u00a0:\n<ul>\n<li><strong>Perte de charge importante<\/strong>\u00a0\u2013 due au frottement dans des tuyaux droits<\/li>\n<li><strong>Perte de charge mineure<\/strong>\u00a0\u2013 due \u00e0 des composants comme des valves, des coudes\u2026<\/li>\n<\/ul>\n<\/li>\n<li>Une\u00a0<strong>forme sp\u00e9ciale de l\u2019\u00e9quation de Darcy<\/strong>\u00a0peut \u00eatre utilis\u00e9e pour calculer\u00a0<strong>les pertes mineures<\/strong>\u00a0.<\/li>\n<li>Les pertes mineures sont \u00e0\u00a0peu pr\u00e8s proportionnelle \u00e0 la\u00a0<strong>place du d\u00e9bit<\/strong>\u00a0et par\u00a0cons\u00e9quent ,\u00a0ils peuvent \u00eatre int\u00e9gr\u00e9s facilement dans l\u2019\u00e9quation de\u00a0Darcy-Weisbach par\u00a0<strong>coefficient de r\u00e9sistance K<\/strong>\u00a0.<\/li>\n<li>En tant que perte de pression locale,\u00a0<strong>l\u2019acc\u00e9l\u00e9ration du fluide dans un canal chauff\u00e9<\/strong>\u00a0peut \u00e9galement \u00eatre envisag\u00e9e.<\/li>\n<\/ul>\n<p>Il existe les m\u00e9thodes suivantes:<\/p>\n<ul>\n<li><strong>M\u00e9thode de longueur \u00e9quivalente<\/strong><\/li>\n<li><strong>M\u00e9thode K (m\u00e9thode du coefficient de r\u00e9sistance)<\/strong><\/li>\n<li><strong>M\u00e9thode 2K<\/strong><\/li>\n<li><strong>M\u00e9thode 3K<\/strong><\/li>\n<\/ul>\n<h2>Pourquoi la perte de t\u00eate est tr\u00e8s importante?<\/h2>\n<p>Comme on peut le voir sur la photo, la perte de charge est\u00a0<strong>une caract\u00e9ristique cl\u00e9<\/strong>\u00a0de tout syst\u00e8me hydraulique.\u00a0Dans les syst\u00e8mes dans lesquels un certain d\u00e9bit doit \u00eatre maintenu (par exemple pour assurer un refroidissement ou un transfert de chaleur suffisant \u00e0 partir d\u2019un\u00a0<a title=\"Noyau du r\u00e9acteur\" href=\"https:\/\/www.reactor-physics.com\/what-is-reactor-core-definition\/\">c\u0153ur de r\u00e9acteur<\/a>\u00a0),\u00a0<strong>l\u2019\u00e9quilibre<\/strong>\u00a0de la\u00a0<strong>perte de charge<\/strong>\u00a0et de la\u00a0\u00a0<strong>t\u00eate ajout\u00e9e<\/strong>\u00a0par une pompe d\u00e9termine le d\u00e9bit \u00e0 travers le syst\u00e8me.<\/p>\n<figure id=\"attachment_14299\" class=\"wp-caption aligncenter\" aria-describedby=\"caption-attachment-14299\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Head-Q-H.png\"><img loading=\"lazy\" class=\"size-medium wp-image-14299 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Head-Q-H-300x207.png\" alt=\"Diagramme caract\u00e9ristique QH de la pompe centrifuge et de la canalisation\" width=\"300\" height=\"207\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Head-Q-H-300x207.png\" \/><\/a><figcaption id=\"caption-attachment-14299\" class=\"wp-caption-text\">Diagramme caract\u00e9ristique QH de la pompe centrifuge et de la canalisation<\/figcaption><\/figure>\n<\/div>\n<\/div>\n<\/div>\n<div><\/div>\n<div><\/div>\n<div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>La m\u00e9thode du coefficient de r\u00e9sistance (ou m\u00e9thode K ou m\u00e9thode de la t\u00eate exc\u00e9dentaire) permet \u00e0 l&#8217;utilisateur de d\u00e9crire la perte de charge \u00e0 travers un coude ou un raccord par un nombre sans dimension &#8211; K. Ing\u00e9nierie thermique M\u00e9thode du coefficient de r\u00e9sistance \u2013 M\u00e9thode K La m\u00e9thode de coefficient de r\u00e9sistance (ou &#8230; <a title=\"Quelle est la m\u00e9thode du coefficient de r\u00e9sistance &#8211; M\u00e9thode K &#8211; T\u00eate en exc\u00e8s &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-methode-du-coefficient-de-resistance-methode-k-tete-en-exces-definition\/\" aria-label=\"En savoir plus sur Quelle est la m\u00e9thode du coefficient de r\u00e9sistance &#8211; M\u00e9thode K &#8211; T\u00eate en exc\u00e8s &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Quelle est la m\u00e9thode du coefficient de r\u00e9sistance - M\u00e9thode K - T\u00eate en exc\u00e8s - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"La m\u00e9thode du coefficient de r\u00e9sistance (ou m\u00e9thode K ou m\u00e9thode de la t\u00eate exc\u00e9dentaire) permet \u00e0 l&#039;utilisateur de d\u00e9crire la perte de charge \u00e0 travers un coude ou un raccord par un nombre sans dimension - K. 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