{"id":49374,"date":"2019-11-17T20:58:38","date_gmt":"2019-11-17T19:58:38","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/"},"modified":"2020-02-19T13:56:15","modified_gmt":"2020-02-19T12:56:15","slug":"quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/","title":{"rendered":"Qu&#8217;est-ce que le cycle du diesel &#8211; Probl\u00e8me de solution &#8211; D\u00e9finition"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Exemple de cycle diesel &#8211; Probl\u00e8me de solution.\u00a0Laissons supposer un cycle diesel typique.\u00a0Calculez les caract\u00e9ristiques cl\u00e9s telles que les temp\u00e9ratures, les pressions, le MEP et l&#8217;efficacit\u00e9.\u00a0G\u00e9nie thermique<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Cycle diesel &#8211; Probl\u00e8me de solution<\/h2>\n<figure id=\"attachment_18421\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-18421\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Diesel-cycle-pV-Diagram.png\"><img loading=\"lazy\" class=\"size-medium wp-image-18421 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Diesel-cycle-pV-Diagram-300x280.png\" alt=\"Diagramme pv d'un cycle diesel id\u00e9al\" width=\"300\" height=\"280\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Diesel-cycle-pV-Diagram-300x280.png\" \/><\/a><figcaption id=\"caption-attachment-18421\" class=\"wp-caption-text\">Diagramme pv d&#8217;un cycle diesel id\u00e9al<\/figcaption><\/figure>\n<p><strong>Cycle diesel &#8211; Probl\u00e8me de solution<\/strong><\/p>\n<p>Supposons le cycle Diesel, qui est l\u2019un des\u00a0<strong>cycles thermodynamiques<\/strong>\u00a0les plus courants\u00a0que l\u2019on puisse trouver dans les\u00a0<strong>moteurs d\u2019automobiles<\/strong>\u00a0.\u00a0L&#8217;un des param\u00e8tres cl\u00e9s de ces moteurs est la variation des volumes entre le point mort haut (TDC) et le point mort bas (BDC).\u00a0Le rapport de ces volumes (\u00a0<em>V\u00a0<\/em><em><sub>1<\/sub><\/em><em>\u00a0\/ V\u00a0<\/em><em><sub>2<\/sub><\/em>\u00a0) est appel\u00e9\u00a0<strong>taux de compression<\/strong>\u00a0.\u00a0Egalement le taux de coupure V\u00a0<sub>3<\/sub>\u00a0\/ V\u00a0<sub>2<\/sub>\u00a0, qui est le rapport des volumes \u00e0 la fin et au d\u00e9but de la phase de combustion.<\/p>\n<p>Dans cet exemple, supposons que le cycle Diesel avec un taux de compression de CR = 20: 1 et un taux de coupure \u03b1 = 2. L&#8217;air est \u00e0 100 kPa = 1 bar, 20 \u00b0 C (293 K) et le volume de la chambre est 500 cm\u00b3 avant la course de compression.<\/p>\n<ul>\n<li>Capacit\u00e9 thermique sp\u00e9cifique \u00e0 pression constante de l\u2019air \u00e0 la pression atmosph\u00e9rique et \u00e0 la temp\u00e9rature ambiante:\u00a0<strong>c\u00a0<\/strong><strong><sub>p<\/sub><\/strong><strong>\u00a0= 1,01 kJ \/ kgK.<\/strong><\/li>\n<li>Capacit\u00e9 thermique sp\u00e9cifique \u00e0 volume constant d\u2019air \u00e0 la pression atmosph\u00e9rique et \u00e0 la temp\u00e9rature ambiante:\u00a0<strong>c\u00a0<\/strong><strong><sub>v<\/sub><\/strong><strong>\u00a0= 0,718 kJ \/ kgK.<\/strong><\/li>\n<li><strong>\u03ba = c\u00a0<\/strong><strong><sub>p<\/sub><\/strong><strong>\u00a0\/ c\u00a0<\/strong><strong><sub>v<\/sub><\/strong><strong>\u00a0= 1,4<\/strong><\/li>\n<\/ul>\n<p><strong><span>Calculer:<\/span><\/strong><\/p>\n<ol>\n<li><strong><span>la masse d&#8217;air d&#8217;admission<\/span><\/strong><\/li>\n<li><strong><span>la temp\u00e9rature T\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><\/li>\n<li><strong><span>la pression p\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><\/li>\n<li><strong><span>la temp\u00e9rature T\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><\/li>\n<li><strong><span>la quantit\u00e9 de chaleur ajout\u00e9e par la combustion du m\u00e9lange air-carburant<\/span><\/strong><\/li>\n<li><strong><span>l&#8217;efficacit\u00e9 thermique de ce cycle<\/span><\/strong><\/li>\n<li><strong><span>le d\u00e9put\u00e9 europ\u00e9en<\/span><\/strong><\/li>\n<\/ol>\n<p><strong><span>Solution:<\/span><\/strong><\/p>\n<p><span>1)<\/span><\/p>\n<p><span>Au d\u00e9but des calculs, nous devons d\u00e9terminer la quantit\u00e9 de gaz dans le cylindre avant la course de compression.\u00a0En utilisant la loi du gaz parfait, nous pouvons trouver la masse:<\/span><\/p>\n<p><em><span>pV = mR\u00a0<\/span><\/em><em><sub><span>sp\u00e9cifique<\/span><\/sub><\/em><em><span>\u00a0T<\/span><\/em><\/p>\n<p><span>o\u00f9:<\/span><\/p>\n<ul>\n<li><em><span>p<\/span><\/em><span>\u00a0est la pression absolue du gaz<\/span><\/li>\n<li><em><span>m<\/span><\/em><span>\u00a0est la masse de substance<\/span><\/li>\n<li><em><span>T<\/span><\/em><span>\u00a0est la temp\u00e9rature absolue<\/span><\/li>\n<li><em><span>V<\/span><\/em><span>\u00a0est le volume<\/span><\/li>\n<li><em><span>R\u00a0<\/span><\/em><em><sub><span>sp\u00e9cifique<\/span><\/sub><\/em><span>\u00a0est la constante de gaz sp\u00e9cifique, \u00e9gale \u00e0 la constante de gaz universelle divis\u00e9e par la masse molaire (M) du gaz ou du m\u00e9lange.\u00a0Pour l&#8217;air sec R\u00a0<\/span><sub><span>sp\u00e9cifique<\/span><\/sub><span>\u00a0= 287,1 J.kg\u00a0<\/span><sup><span>-1<\/span><\/sup><span>\u00a0.K\u00a0<\/span><sup><span>-1<\/span><\/sup><span>\u00a0.<\/span><\/li>\n<\/ul>\n<p><span>Donc<\/span><\/p>\n<p><strong><span>m<\/span><\/strong><span>\u00a0= p\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0\/ R\u00a0<\/span><sub><span>sp\u00e9cifique<\/span><\/sub><span>\u00a0T\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0= (100000 \u00d7 500 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0) \/ (287,1 \u00d7 293) =\u00a0<\/span><strong><span>5,95 \u00d7 10\u00a0<\/span><\/strong><strong><sup><span>-4<\/span><\/sup><\/strong><strong><span>\u00a0kg<\/span><\/strong><\/p>\n<p><strong><span>2)<\/span><\/strong><\/p>\n<p><strong><span>Dans ce probl\u00e8me, tous les volumes sont connus:<\/span><\/strong><\/p>\n<ul>\n<li><span>V\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>4<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0= 500 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0m\u00a0<\/span><sup><span>3<\/span><\/sup><span>\u00a0(0,5 l)<\/span><\/li>\n<li><span>V\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>min<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0\/ CR = 25 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0m\u00a0<\/span><sup><span>3<\/span><\/sup><\/li>\n<\/ul>\n<p><span>Notez que (V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0&#8211; V\u00a0<\/span><sub><span>min<\/span><\/sub><span>\u00a0) x nombre de cylindres = cylindr\u00e9e totale du moteur<\/span><\/p>\n<p><span>Puisque le processus est adiabatique, nous pouvons utiliser la relation p, V, T suivante pour les processus adiabatiques:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17558 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\" alt=\"\" width=\"154\" height=\"84\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\" \/><\/a><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-formula-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17563 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-formula-example.png\" alt=\"\" width=\"155\" height=\"78\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-formula-example.png\" \/><\/a><\/p>\n<p><span>Donc<\/span><\/p>\n<p><span>T\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0= T\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0.\u00a0CR\u00a0<\/span><sup><span>\u03ba &#8211; 1<\/span><\/sup><span>\u00a0= 293.\u00a020\u00a0<\/span><sup><span>0,4<\/span><\/sup><span>\u00a0= 971 K<\/span><\/p>\n<p><span>3)<\/span><\/p>\n<p><span>Encore une fois, nous pouvons utiliser la loi du gaz parfait pour trouver la pression \u00e0 la fin de la course de compression comme:<\/span><\/p>\n<p><strong><span>p\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><span>\u00a0= mR\u00a0<\/span><sub><span>sp\u00e9cifique<\/span><\/sub><span>\u00a0T\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0\/ V\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0= 5,95 \u00d7 10\u00a0<\/span><sup><span>-4<\/span><\/sup><span>\u00a0x 287,1 x\u00a0971\/25\u00a0\u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0= 6635000 Pa =\u00a0<\/span><strong><span>66,35 bar<\/span><\/strong><\/p>\n<p><span>4)<\/span><\/p>\n<p><span>Comme le processus 2 \u2192 3 se produit \u00e0 pression constante, l&#8217;\u00e9quation d&#8217;\u00e9tat du gaz parfait donne<\/span><\/p>\n<p><span>T\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0= (V\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0\/ V\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0) x T\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0= 1942 K<\/span><\/p>\n<p><span>Pour calculer la quantit\u00e9 de chaleur ajout\u00e9e par la combustion du m\u00e9lange carburant-air,\u00a0<\/span><sub><span>ajoutons<\/span><\/sub><span>\u00a0Q\u00a0, nous devons utiliser le premi\u00e8re principe de la thermodynamique pour le processus isobare, qui stipule:<\/span><\/p>\n<p><span>Q\u00a0<\/span><sub><span>add<\/span><\/sub><span>\u00a0= mc\u00a0<\/span><sub><span>p<\/span><\/sub><span>\u00a0(T\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0&#8211; T\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0) = 5,95 \u00d7 10\u00a0<\/span><sup><span>-4<\/span><\/sup><span>\u00a0x 1010 x 971 =\u00a0<\/span><strong><span>583,5 J<\/span><\/strong><\/p>\n<p><span>5)<\/span><\/p>\n<p><span>Efficacit\u00e9 thermique pour ce cycle Diesel:<\/span><\/p>\n<p><span>Comme il a \u00e9t\u00e9 d\u00e9riv\u00e9 dans la section pr\u00e9c\u00e9dente, l&#8217;efficacit\u00e9 thermique du cycle Diesel est fonction du taux de compression, du taux de coupure et de \u03ba:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Diesel-cycle-Thermal-Efficiency2.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-18420 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Diesel-cycle-Thermal-Efficiency2.png\" alt=\"\" width=\"300\" height=\"65\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Diesel-cycle-Thermal-Efficiency2.png\" \/><\/a><span>o\u00f9<\/span><\/p>\n<ul>\n<li><span>\u03b7\u00a0<\/span><sub><span>Diesel<\/span><\/sub><span>\u00a0est l&#8217;efficacit\u00e9 thermique maximale d&#8217;un cycle Diesel<\/span><\/li>\n<li><span>\u03b1 est le rapport de coupure V\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0\/ V\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0(c&#8217;est-\u00e0-dire le rapport des volumes \u00e0 la fin et au d\u00e9but de la phase de combustion)<\/span><\/li>\n<li><span>CR est le taux de compression<\/span><\/li>\n<li><strong><span>\u03ba = c\u00a0<\/span><\/strong><strong><sub><span>p<\/span><\/sub><\/strong><strong><span>\u00a0\/ c\u00a0<\/span><\/strong><strong><sub><span>v<\/span><\/sub><\/strong><strong><span>\u00a0= 1,4<\/span><\/strong><\/li>\n<\/ul>\n<p><span>Pour cet exemple:<\/span><\/p>\n<p><span>\u03b7\u00a0<\/span><sub><span>Diesel<\/span><\/sub><span>\u00a0= 0,6467 = 64,7%<\/span><\/p>\n<p><span>6)<\/span><\/p>\n<p><span>Le d\u00e9put\u00e9 europ\u00e9en a \u00e9t\u00e9 d\u00e9fini comme:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17565 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\" alt=\"\" width=\"300\" height=\"63\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\" \/><\/a><\/p>\n<p><span>Si cette \u00e9quation, le volume de d\u00e9placement est \u00e9gal \u00e0 V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0&#8211; V\u00a0<\/span><sub><span>min<\/span><\/sub><span>\u00a0.\u00a0Le travail net pour un cycle peut \u00eatre calcul\u00e9 en utilisant la chaleur ajout\u00e9e et l&#8217;efficacit\u00e9 thermique:<\/span><\/p>\n<p><strong><em><span>W\u00a0<\/span><\/em><\/strong><strong><em><sub><span>net<\/span><\/sub><\/em><\/strong><em><span>\u00a0=\u00a0<\/span><\/em><em><span>Q\u00a0<\/span><\/em><em><sub><span>add<\/span><\/sub><\/em><em><span>\u00a0.\u00a0\u03b7\u00a0<\/span><\/em><em><sub><span>Otto<\/span><\/sub><\/em><em><span>\u00a0=\u00a0<\/span><\/em><em><span>583,5 x 0,6467 =\u00a0<\/span><strong><span>377,3 J<\/span><\/strong><\/em><\/p>\n<p><strong><em><span>MEP<\/span><\/em><\/strong><em><span>\u00a0= 377,3 \/ (<\/span><\/em><span>\u00a0500 \u00d7 10<\/span><sup><span>\u00a0-6<\/span><\/sup><span>\u00a0&#8211; 25 \u00d7 10<\/span><sup><span>\u00a0-6\u00a0<\/span><\/sup><em><span>) = 794,3 kPa =\u00a0<\/span><strong><span>7,943 bar<\/span><\/strong><\/em><\/p>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Exemple de cycle diesel &#8211; Probl\u00e8me de solution.\u00a0Laissons supposer un cycle diesel typique.\u00a0Calculez les caract\u00e9ristiques cl\u00e9s telles que les temp\u00e9ratures, les pressions, le MEP et l&#8217;efficacit\u00e9.\u00a0G\u00e9nie thermique Cycle diesel &#8211; Probl\u00e8me de solution Diagramme pv d&#8217;un cycle diesel id\u00e9al Cycle diesel &#8211; Probl\u00e8me de solution Supposons le cycle Diesel, qui est l\u2019un des\u00a0cycles thermodynamiques\u00a0les plus &#8230; <a title=\"Qu&#8217;est-ce que le cycle du diesel &#8211; Probl\u00e8me de solution &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/\" aria-label=\"En savoir plus sur Qu&#8217;est-ce que le cycle du diesel &#8211; Probl\u00e8me de solution &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Qu&#039;est-ce que le cycle du diesel - Probl\u00e8me de solution - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"Exemple de cycle diesel - Probl\u00e8me de solution. Laissons supposer un cycle diesel typique. Calculez les caract\u00e9ristiques cl\u00e9s telles que les temp\u00e9ratures, les pressions, le MEP et l&#039;efficacit\u00e9. G\u00e9nie thermique\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/\" \/>\n<meta property=\"og:locale\" content=\"fr_FR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Qu&#039;est-ce que le cycle du diesel - Probl\u00e8me de solution - D\u00e9finition\" \/>\n<meta property=\"og:description\" content=\"Exemple de cycle diesel - Probl\u00e8me de solution. Laissons supposer un cycle diesel typique. Calculez les caract\u00e9ristiques cl\u00e9s telles que les temp\u00e9ratures, les pressions, le MEP et l&#039;efficacit\u00e9. G\u00e9nie thermique\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/\" \/>\n<meta property=\"og:site_name\" content=\"Thermal Engineering\" \/>\n<meta property=\"article:published_time\" content=\"2019-11-17T19:58:38+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2020-02-19T12:56:15+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Diesel-cycle-pV-Diagram-300x280.png\" \/>\n<meta name=\"twitter:card\" content=\"summary\" \/>\n<meta name=\"twitter:label1\" content=\"\u00c9crit par\">\n\t<meta name=\"twitter:data1\" content=\"Nick Connor\">\n\t<meta name=\"twitter:label2\" content=\"Dur\u00e9e de lecture est.\">\n\t<meta name=\"twitter:data2\" content=\"3 minutes\">\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebSite\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#website\",\"url\":\"https:\/\/www.thermal-engineering.org\/fr\/\",\"name\":\"Thermal Engineering\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":\"https:\/\/www.thermal-engineering.org\/fr\/?s={search_term_string}\",\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"fr-FR\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/#primaryimage\",\"inLanguage\":\"fr-FR\",\"url\":\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Diesel-cycle-pV-Diagram-300x280.png\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/#webpage\",\"url\":\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/\",\"name\":\"Qu'est-ce que le cycle du diesel - Probl\\u00e8me de solution - D\\u00e9finition\",\"isPartOf\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/#primaryimage\"},\"datePublished\":\"2019-11-17T19:58:38+00:00\",\"dateModified\":\"2020-02-19T12:56:15+00:00\",\"author\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#\/schema\/person\/e8c544db9afedaec8574d6464f9398bb\"},\"description\":\"Exemple de cycle diesel - Probl\\u00e8me de solution. Laissons supposer un cycle diesel typique. Calculez les caract\\u00e9ristiques cl\\u00e9s telles que les temp\\u00e9ratures, les pressions, le MEP et l'efficacit\\u00e9. G\\u00e9nie thermique\",\"inLanguage\":\"fr-FR\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-cycle-du-diesel-probleme-de-solution-definition\/\"]}]},{\"@type\":\"Person\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#\/schema\/person\/e8c544db9afedaec8574d6464f9398bb\",\"name\":\"Nick Connor\",\"image\":{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#personlogo\",\"inLanguage\":\"fr-FR\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/84c0dec310b44b65da29dc9df6925239?s=96&d=mm&r=g\",\"caption\":\"Nick Connor\"}}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","_links":{"self":[{"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/posts\/49374"}],"collection":[{"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/comments?post=49374"}],"version-history":[{"count":0,"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/posts\/49374\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/media?parent=49374"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/categories?post=49374"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.thermal-engineering.org\/fr\/wp-json\/wp\/v2\/tags?post=49374"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}