{"id":52504,"date":"2020-02-19T17:20:57","date_gmt":"2020-02-19T16:20:57","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quelle-est-la-theorie-du-cycle-dotto-moteur-a-essence-definition\/"},"modified":"2020-02-19T17:21:59","modified_gmt":"2020-02-19T16:21:59","slug":"quelle-est-la-theorie-du-cycle-dotto-moteur-a-essence-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-theorie-du-cycle-dotto-moteur-a-essence-definition\/","title":{"rendered":"Quelle est la th\u00e9orie du cycle d&#8217;Otto &#8211; Moteur \u00e0 essence &#8211; D\u00e9finition"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Th\u00e9orie du cycle d&#8217;Otto &#8211; Moteur \u00e0 essence.\u00a0Le cycle d&#8217;Otto comprend quatre processus r\u00e9versibles en interne.\u00a0L&#8217;efficacit\u00e9 thermique d\u00e9pend du taux de compression.\u00a0G\u00e9nie thermique<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights lgc-first\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Cycle Otto &#8211; Moteur Otto<\/h2>\n<p>En 1876, un ing\u00e9nieur allemand,\u00a0<strong>Nikolaus August Otto, a fait<\/strong>\u00a0progresser l\u2019\u00e9tude des moteurs thermiques en construisant le premier moteur \u00e0 quatre temps en fonctionnement.\u00a0un moteur fixe utilisant un m\u00e9lange charbon-air-air comme carburant.\u00a0Wilhelm Maybach (1846-1929), l&#8217;un des plus importants ing\u00e9nieurs allemands, perfectionna la construction, qui avait d\u00e9j\u00e0 \u00e9t\u00e9 produite en grande quantit\u00e9 \u00e0 la fin de 1876. Ces inventions ont rapidement transform\u00e9 le monde dans lequel elles vivaient.<\/p>\n<p>Le cycle du moteur Otto est appel\u00e9 cycle Otto.\u00a0C&#8217;est l&#8217;un des\u00a0<strong>cycles thermodynamiques<\/strong>\u00a0les plus courants\u00a0que l&#8217;on puisse trouver dans les\u00a0<strong>moteurs d&#8217;automobiles. Il<\/strong>\u00a0d\u00e9crit le fonctionnement d&#8217;un moteur \u00e0 piston \u00e0 allumage command\u00e9 typique.\u00a0Contrairement au cycle de Carnot, le cycle d&#8217;Otto n&#8217;ex\u00e9cute pas de processus isothermiques, ceux-ci devant \u00eatre effectu\u00e9s tr\u00e8s lentement.\u00a0Dans un cycle d&#8217;Otto id\u00e9al, le syst\u00e8me ex\u00e9cutant le cycle subit une s\u00e9rie de quatre processus r\u00e9versibles de mani\u00e8re interne: deux processus isentropiques (adiabatiques r\u00e9versibles) altern\u00e9s avec deux processus isochoriques.<\/p>\n<p>Puisque le\u00a0<strong>principe de Carnot<\/strong>\u00a0stipule qu&#8217;aucun moteur ne\u00a0peut \u00eatre plus efficace qu&#8217;un moteur r\u00e9versible (\u00a0<strong>un moteur thermique Carnot<\/strong>\u00a0) fonctionnant entre la m\u00eame temp\u00e9rature \u00e9lev\u00e9e et des\u00a0r\u00e9servoirs \u00e0\u00a0basse temp\u00e9rature, le moteur Otto doit avoir une\u00a0efficacit\u00e9 inf\u00e9rieure \u00e0 l&#8217;efficacit\u00e9 Carnot.\u00a0Un\u00a0<strong>moteur automobile \u00e0 essence<\/strong>\u00a0typique\u00a0fonctionne \u00e0 environ\u00a0<strong>25% \u00e0 30%<\/strong>\u00a0de l&#8217;efficacit\u00e9 thermique.\u00a0Environ 70-75% sont rejet\u00e9s sous forme de chaleur perdue sans \u00eatre convertis en travail utile, c&#8217;est-\u00e0-dire que le travail est livr\u00e9 \u00e0 des roues.<\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights lgc-last\">\n<div class=\"inside-grid-column\">\n<figure id=\"attachment_17548\" class=\"wp-caption aligncenter\" aria-describedby=\"caption-attachment-17548\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Four-Stroke-Engine-Otto-Engine.gif\"><img loading=\"lazy\" class=\"size-full wp-image-17548 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Four-Stroke-Engine-Otto-Engine.gif\" alt=\"Moteur quatre temps - Moteur Otto\" width=\"225\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Four-Stroke-Engine-Otto-Engine.gif\" \/><\/a><figcaption id=\"caption-attachment-17548\" class=\"wp-caption-text\">Moteur \u00e0 quatre temps &#8211; Moteur Otto<br \/>\nSource: wikipedia.org, oeuvre de Zephyris, CC BY-SA 3.0<\/figcaption><\/figure>\n<div class=\"su-youtube su-responsive-media-yes\"><iframe class=\"lazy-loaded\" src=\"https:\/\/www.youtube.com\/embed\/xflY5uS-nnw?\" width=\"340\" height=\"200\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\" data-lazy-type=\"iframe\" data-src=\"https:\/\/www.youtube.com\/embed\/xflY5uS-nnw?\" data-mce-fragment=\"1\"><\/iframe><\/div>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Cycle Otto &#8211; Processus<\/h2>\n<figure id=\"attachment_17461\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-17461\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-Cycle-PV-Diagram.png\"><img loading=\"lazy\" class=\"size-medium wp-image-17461 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-Cycle-PV-Diagram-300x245.png\" alt=\"Cycle Otto - Diagramme PV\" width=\"300\" height=\"245\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-Cycle-PV-Diagram-300x245.png\" \/><\/a><figcaption id=\"caption-attachment-17461\" class=\"wp-caption-text\">Diagramme pV du cycle d&#8217;Otto.\u00a0La zone d\u00e9limit\u00e9e par la piste cyclable compl\u00e8te repr\u00e9sente le travail total pouvant \u00eatre effectu\u00e9 au cours d&#8217;un cycle.<\/figcaption><\/figure>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<p><span>Dans un cycle Otto id\u00e9al, le syst\u00e8me ex\u00e9cutant le cycle subit une s\u00e9rie de quatre processus r\u00e9versibles en interne: deux processus isentropiques (adiabatiques r\u00e9versibles) altern\u00e9s avec deux processus isochoriques:<\/span><\/p>\n<ol>\n<li><strong><span>Compression isentropique<\/span><\/strong><span>\u00a0(course de compression) &#8211; Le gaz (m\u00e9lange air-carburant) est comprim\u00e9 adiabatiquement de l&#8217;\u00e9tat 1 \u00e0 l&#8217;\u00e9tat 2, lorsque le piston se d\u00e9place du point mort bas au point mort haut.\u00a0Les environs agissent sur le gaz, augmentant son \u00e9nergie interne (temp\u00e9rature) et le compressant.\u00a0En revanche, l&#8217;entropie reste inchang\u00e9e.\u00a0Les variations de volume et son rapport (\u00a0<\/span><em><span>V\u00a0<\/span><\/em><em><sub><span>1<\/span><\/sub><\/em><em><span>\u00a0\/ V\u00a0<\/span><\/em><em><sub><span>2<\/span><\/sub><\/em><span>\u00a0) sont connus comme le taux de compression.<\/span><\/li>\n<li><strong><span>Compression isochore<\/span><\/strong><span>\u00a0(phase d&#8217;allumage) &#8211; Dans cette phase (entre l&#8217;\u00e9tat 2 et l&#8217;\u00e9tat 3), il y a un transfert de chaleur \u00e0 volume constant (le piston est au repos) vers l&#8217;air \u00e0 partir d&#8217;une source externe tandis que le piston est au repos au point mort haut .\u00a0Ce processus est destin\u00e9 \u00e0 repr\u00e9senter l&#8217;inflammation du m\u00e9lange carburant-air inject\u00e9 dans la chambre et la combustion rapide qui en r\u00e9sulte.\u00a0La pression augmente et le rapport (\u00a0<\/span><em><span>P\u00a0<\/span><\/em><em><sub><span>3<\/span><\/sub><\/em><em><span>\u00a0\/ P\u00a0<\/span><\/em><em><sub><span>2<\/span><\/sub><\/em><span>\u00a0) est appel\u00e9 \u00abrapport d&#8217;explosion\u00bb.<\/span><\/li>\n<li><strong><span>Expansion isentropique<\/span><\/strong><span>\u00a0(course de puissance) &#8211; Le gaz se d\u00e9tend adiabatiquement de l&#8217;\u00e9tat 3 \u00e0 l&#8217;\u00e9tat 4, lorsque le piston se d\u00e9place du point mort haut au point mort bas.\u00a0Le gaz travaille sur l&#8217;environnement (piston) et perd une quantit\u00e9 d&#8217;\u00e9nergie interne \u00e9gale au travail qui quitte le syst\u00e8me.\u00a0Encore une fois, l&#8217;entropie reste inchang\u00e9e.\u00a0Le rapport volumique (\u00a0<\/span><em><span>V\u00a0<\/span><\/em><em><sub><span>4<\/span><\/sub><\/em><em><span>\u00a0\/ V\u00a0<\/span><\/em><em><sub><span>3<\/span><\/sub><\/em><span>\u00a0) est connu sous le nom de ration d&#8217;expansion isentropique, mais pour le cycle d&#8217;Otto, il est \u00e9gal au taux de compression.<\/span><\/li>\n<li><strong><span>D\u00e9compression isochore (course d&#8217;\u00e9chappement)<\/span><\/strong><span>\u00a0&#8211; Dans cette phase, le cycle se termine par un processus \u00e0 volume constant dans lequel la chaleur est rejet\u00e9e de l&#8217;air tandis que le piston est au point mort bas.\u00a0La pression du gaz de travail chute instantan\u00e9ment du point 4 au point 1. La soupape d&#8217;\u00e9chappement s&#8217;ouvre au point 4. La course d&#8217;\u00e9chappement survient directement apr\u00e8s cette d\u00e9compression.\u00a0Lorsque le piston se d\u00e9place du point mort bas (point 1) au point mort haut (point 0) avec la soupape d&#8217;\u00e9chappement ouverte, le m\u00e9lange gazeux est \u00e9vacu\u00e9 vers l&#8217;atmosph\u00e8re et le processus recommence.<\/span><\/li>\n<\/ol>\n<p><span>Pendant le cycle d&#8217;Otto, le travail est effectu\u00e9 sur le gaz par le piston entre les \u00e9tats 1 et 2 (\u00a0<\/span><strong><span>compression isentropique<\/span><\/strong><span>\u00a0).\u00a0Le travail se fait par le gaz sur le piston entre les \u00e9tapes 3 et 4 (\u00a0<\/span><strong><span>d\u00e9tente isentropique<\/span><\/strong><span>\u00a0).\u00a0La diff\u00e9rence entre le travail effectu\u00e9 par le gaz et le travail effectu\u00e9 sur le gaz est le travail net produit par le cycle et il correspond \u00e0 la zone d\u00e9limit\u00e9e par la courbe du cycle.\u00a0Le travail produit par le cycle multiplie la vitesse du cycle (cycles par seconde) par la puissance produite par le moteur Otto.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights  lgc-first\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Processus isentropique<\/span><\/h2>\n<p><span>Un\u00a0<\/span><a title=\"Processus isentropique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quel-est-le-processus-isentropique-definition\/\"><strong><span>processus isentropique<\/span><\/strong><\/a><span>\u00a0est un\u00a0<\/span><a title=\"Processus thermodynamiques\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-processus-thermodynamique-definition\/\"><strong><span>processus thermodynamique<\/span><\/strong><\/a><span>\u00a0, dans lequel l&#8217;\u00a0<\/span><a title=\"Qu'est-ce que l'entropie\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/what-is-energy-physics\/what-is-entropy\/\"><strong><span>entropie<\/span><\/strong>\u00a0<\/a><span>du fluide ou du gaz reste constante.\u00a0Cela signifie que le\u00a0<\/span><strong><span>processus isentropique<\/span><\/strong><span>\u00a0est un cas particulier d&#8217;un\u00a0<\/span><strong><span>processus adiabatique<\/span><\/strong><span>\u00a0dans lequel il n&#8217;y a pas de transfert de chaleur ou de mati\u00e8re.\u00a0Il s&#8217;agit d&#8217;un\u00a0<\/span><strong><span>processus adiabatique r\u00e9versible<\/span><\/strong><span>\u00a0.\u00a0L&#8217;hypoth\u00e8se d&#8217;absence de transfert de chaleur est tr\u00e8s importante, car nous ne pouvons utiliser l&#8217;approximation adiabatique que dans\u00a0<\/span><strong><span>des processus tr\u00e8s rapides<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><strong><span>Processus isentropique et premi\u00e8re loi<\/span><\/strong><\/p>\n<p><span>Pour un syst\u00e8me ferm\u00e9, on peut \u00e9crire la\u00a0<\/span><strong><a title=\"Premi\u00e8re loi en termes d'enthalpie dH = dQ + Vdp\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/first-law-in-terms-of-enthalpy-dh-dq-vdp\/\"><span>premi\u00e8re loi de la thermodynamique en termes d&#8217;enthalpie<\/span><\/a><\/strong><span>\u00a0:<\/span><\/p>\n<p><strong><span>dH = dQ + Vdp<\/span><\/strong><\/p>\n<p><strong><span>ou<\/span><\/strong><\/p>\n<p><strong><span>dH = TdS + Vdp<\/span><\/strong><\/p>\n<p><strong><span>Processus isentropique (dQ = 0):<\/span><\/strong><\/p>\n<p><strong><span>dH = Vdp \u2192 W = H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><strong><span>\u00a0\u00a0\u00a0\u00a0\u00a0\u2192 H\u00a0<\/span><\/strong><strong><sub><span>2<\/span><\/sub><\/strong><strong><span>\u00a0&#8211; H\u00a0<\/span><\/strong><strong><sub><span>1<\/span><\/sub><\/strong><strong><span>\u00a0=\u00a0<\/span><em><span>C\u00a0<\/span><\/em><\/strong><strong><em><sub><span>p<\/span><\/sub><\/em><\/strong><strong><em><span>\u00a0(T\u00a0<\/span><\/em><\/strong><strong><em><sub><span>2<\/span><\/sub><\/em><\/strong><strong><em><span>\u00a0&#8211; T\u00a0<\/span><\/em><\/strong><strong><em><sub><span>1<\/span><\/sub><\/em><\/strong><strong><em><span>\u00a0) \u00a0\u00a0\u00a0<\/span><\/em><\/strong><em><span>\u00a0(pour\u00a0<\/span><a title=\"Qu'est-ce que le gaz parfait\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/ideal-gas-law\/what-is-ideal-gas\/\"><span>le gaz parfait<\/span><\/a><span>\u00a0)<\/span><\/em><\/p>\n<p><strong><span>Processus isentropique du gaz parfait<\/span><\/strong><\/p>\n<p><span>Le\u00a0<\/span><strong><span>processus isentropique<\/span><\/strong><span>\u00a0(un cas particulier du processus adiabatique) peut \u00eatre exprim\u00e9 avec la\u00a0<\/span><a title=\"Loi du gaz parfait\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/ideal-gas-law\/\"><strong><span>loi du gaz parfait<\/span><\/strong><\/a><span>\u00a0comme:<\/span><\/p>\n<p><strong><em><span>pV\u00a0<\/span><sup><span>\u03ba<\/span><\/sup><span>\u00a0= constant<\/span><\/em><\/strong><\/p>\n<p><span>ou<\/span><\/p>\n<p><em><strong><span>p\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>1\u00a0<\/span><\/sub><sup><span>\u03ba<\/span><\/sup><span>\u00a0= p\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>2\u00a0<\/span><\/sub><sup><span>\u03ba<\/span><\/sup><\/strong><\/em><\/p>\n<p><span>dans laquelle\u00a0<\/span><strong><span>\u03ba = c\u00a0<\/span><sub><span>p<\/span><\/sub><span>\u00a0\/ c\u00a0<\/span><sub><span>v<\/span><\/sub><\/strong><span>\u00a0est le rapport des\u00a0<a title=\"Capacit\u00e9 calorifique - Capacit\u00e9 calorifique sp\u00e9cifique\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/heat-capacity\/\"><strong>chaleurs sp\u00e9cifiques<\/strong><\/a>\u00a0(ou\u00a0<strong>capacit\u00e9s calorifiques<\/strong>\u00a0) pour le gaz.\u00a0Un pour\u00a0<strong>une pression constante (c\u00a0<\/strong><strong><sub>p<\/sub><\/strong><strong>\u00a0)<\/strong>\u00a0et un pour\u00a0<strong>un volume constant (c\u00a0<\/strong><strong><sub>v<\/sub><\/strong><strong>\u00a0)<\/strong>\u00a0.\u00a0Notez que ce rapport\u00a0<strong>\u03ba\u00a0\u00a0<\/strong><strong>= c\u00a0<\/strong><strong><sub>p<\/sub><\/strong><strong>\u00a0\/ c\u00a0<\/strong><strong><sub>v<\/sub><\/strong>\u00a0est un facteur d\u00e9terminant la vitesse du son dans un gaz et d&#8217;autres processus adiabatiques.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights  lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Processus isochorique<\/span><\/h2>\n<p><span>Un\u00a0<\/span><a title=\"Processus isochorique - Processus isom\u00e9trique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-processus-isochorique-processus-isometrique-definition\/\"><strong><span>processus isochore<\/span><\/strong><\/a><span>\u00a0est un processus thermodynamique, dans lequel le\u00a0<\/span><strong><span>volume<\/span><\/strong><span>\u00a0du syst\u00e8me ferm\u00e9\u00a0<\/span><strong><span>reste constant<\/span><\/strong><span>\u00a0(V = const).\u00a0Il d\u00e9crit le comportement du gaz \u00e0 l&#8217;int\u00e9rieur du conteneur, qui ne peut pas \u00eatre d\u00e9form\u00e9.\u00a0\u00c9tant donn\u00e9 que le volume reste constant, le transfert de chaleur dans ou hors du syst\u00e8me ne fonctionne pas avec le\u00a0<\/span><a title=\"Travaux p\u0394V - Travaux aux limites et travaux V\u0394p\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/p%ce%b4v-work-boundary-work-and-v%ce%b4p-work\/\"><span>p\u2206V<\/span><\/a><span>\u00a0, mais modifie uniquement l&#8217;\u00a0<\/span><a href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lenergie-interne-energie-thermique-definition\/\"><strong><span>\u00e9nergie interne<\/span><\/strong><\/a><span>\u00a0(la temp\u00e9rature) du syst\u00e8me.<\/span><\/p>\n<p><strong><span>Processus isochorique et premi\u00e8re loi<\/span><\/strong><\/p>\n<p><span>La forme classique de la\u00a0<\/span><a title=\"Premi\u00e8re loi de la thermodynamique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-premiere-loi-de-la-thermodynamique-definition\/\"><span>premi\u00e8re loi de la thermodynamique<\/span><\/a><span>\u00a0est l&#8217;\u00e9quation suivante:<\/span><\/p>\n<p><strong><span>dU = dQ &#8211; dW<\/span><\/strong><\/p>\n<p><span>Dans cette \u00e9quation, dW est \u00e9gal \u00e0\u00a0<\/span><strong><span>dW = pdV<\/span><\/strong><span>\u00a0et est connu comme le\u00a0<\/span><a title=\"Travaux p\u0394V - Travaux aux limites et travaux V\u0394p\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/p%ce%b4v-work-boundary-work-and-v%ce%b4p-work\/\"><span>travail<\/span><\/a><span>\u00a0aux\u00a0<a title=\"Travaux p\u0394V - Travaux aux limites et travaux V\u0394p\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/laws-of-thermodynamics\/first-law-of-thermodynamics\/p%ce%b4v-work-boundary-work-and-v%ce%b4p-work\/\">limites<\/a>\u00a0.\u00a0Alors:<\/span><\/p>\n<p><strong><span>dU = dQ &#8211; pdV<\/span><\/strong><\/p>\n<p><span>Dans le\u00a0<\/span><strong><span>processus isochore<\/span><\/strong><span>\u00a0et le\u00a0<\/span><strong><span>gaz parfait<\/span><\/strong><span>\u00a0, toute la chaleur ajout\u00e9e au syst\u00e8me sera utilis\u00e9e pour augmenter l&#8217;\u00e9nergie interne.<\/span><\/p>\n<p><strong><span>Processus isochorique (pdV = 0):<\/span><\/strong><\/p>\n<p><strong><span>dU = dQ \u00a0\u00a0\u00a0\u00a0<\/span><\/strong><em><span>(pour le gaz parfait)<\/span><\/em><\/p>\n<p><strong><span>dU = 0 = Q &#8211; W \u2192 W = Q \u00a0\u00a0<\/span><em>\u00a0\u00a0\u00a0\u00a0<\/em><\/strong><em><span>(pour le gaz parfait)<\/span><\/em><\/p>\n<p><strong><span>Processus isochorique du gaz parfait<\/span><\/strong><\/p>\n<p><span>Le\u00a0<\/span><strong><span>processus isochore<\/span><\/strong><span>\u00a0peut s&#8217;exprimer avec la\u00a0<\/span><a title=\"Loi du gaz parfait\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/ideal-gas-law\/\"><strong><span>loi du gaz parfait<\/span><\/strong><\/a><span>\u00a0comme:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isochoric-process-equation-1.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17465 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isochoric-process-equation-1.png\" alt=\"processus isochore - \u00e9quation 1\" width=\"138\" height=\"52\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isochoric-process-equation-1.png\" \/><\/a><\/p>\n<p><span>ou<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isochoric-process-equation-2.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17466 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isochoric-process-equation-2.png\" alt=\"processus isochore - \u00e9quation 2\" width=\"86\" height=\"66\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/isochoric-process-equation-2.png\" \/><\/a><\/p>\n<p><span>Sur un\u00a0<\/span><strong><span>diagramme pV<\/span><\/strong><span>\u00a0, le processus se produit le long d&#8217;une ligne horizontale qui a l&#8217;\u00e9quation V = constante.<\/span><\/p>\n<p><span>Voir aussi:\u00a0\u00a0<\/span><a title=\"Loi de Guy-Lussac\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-loi-gay-lussac-definition\/\"><span>Loi de Guy-Lussac<\/span><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights  lgc-first\">\n<div class=\"inside-grid-column\">\n<figure id=\"attachment_17280\" class=\"wp-caption aligncenter\" aria-describedby=\"caption-attachment-17280\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isentropic-Process-characteristics.png\"><img loading=\"lazy\" class=\"size-full wp-image-17280 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isentropic-Process-characteristics.png\" alt=\"Processus isentropique - caract\u00e9ristiques\" width=\"386\" height=\"609\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isentropic-Process-characteristics.png\" \/><\/a><figcaption id=\"caption-attachment-17280\" class=\"wp-caption-text\"><span>Processus isentropique &#8211; principales caract\u00e9ristiques<\/span><\/figcaption><\/figure>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-50 lgc-tablet-grid-50 lgc-mobile-grid-100 lgc-equal-heights  lgc-last\">\n<div class=\"inside-grid-column\">\n<figure id=\"attachment_17463\" class=\"wp-caption aligncenter\" aria-describedby=\"caption-attachment-17463\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isochoric-process-main-characteristics.png\"><img loading=\"lazy\" class=\"size-full wp-image-17463 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isochoric-process-main-characteristics.png\" alt=\"Processus isochorique - principales caract\u00e9ristiques\" width=\"382\" height=\"468\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Isochoric-process-main-characteristics.png\" \/><\/a><figcaption id=\"caption-attachment-17463\" class=\"wp-caption-text\"><span>Processus isochorique &#8211; principales caract\u00e9ristiques<\/span><\/figcaption><\/figure>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Comparaison des cycles Otto r\u00e9els et id\u00e9aux<\/span><\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-engine-vs.-Otto-cycle.png\"><img loading=\"lazy\" class=\"alignright  wp-image-17556 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-engine-vs.-Otto-cycle.png\" alt=\"Moteur Otto vs cycle Otto\" width=\"332\" height=\"556\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-engine-vs.-Otto-cycle.png\" \/><\/a><span>Dans cette section, il est montr\u00e9 un\u00a0<\/span><strong><span>cycle Otto id\u00e9al<\/span><\/strong><span>\u00a0dans lequel il y a beaucoup d&#8217;\u00a0<\/span><strong><span>hypoth\u00e8ses<\/span><\/strong><span>\u00a0diff\u00e9rentes du\u00a0<\/span><strong><span>cycle Otto r\u00e9el<\/span><\/strong><span>\u00a0.\u00a0Les principales diff\u00e9rences entre le moteur Otto r\u00e9el et id\u00e9al apparaissent sur la figure.\u00a0En r\u00e9alit\u00e9, le cycle id\u00e9al ne se produit pas et il y a de nombreuses pertes associ\u00e9es \u00e0 chaque processus.\u00a0Pour un cycle r\u00e9el, la forme du diagramme pV est similaire \u00e0 l&#8217;id\u00e9al, mais la zone (travail) entour\u00e9e par le diagramme pV est toujours inf\u00e9rieure \u00e0 la valeur id\u00e9ale.\u00a0Le cycle Otto id\u00e9al est bas\u00e9 sur les hypoth\u00e8ses suivantes:<\/span><\/p>\n<ul>\n<li><strong><span>Cycle ferm\u00e9.\u00a0<\/span><\/strong><span>\u00a0La plus grande diff\u00e9rence entre les deux diagrammes est la simplification des courses d&#8217;admission et d&#8217;\u00e9chappement dans le cycle id\u00e9al.\u00a0Dans la course d&#8217;\u00e9chappement, la chaleur Q\u00a0<\/span><sub><span>out<\/span><\/sub><span>\u00a0est \u00e9ject\u00e9e dans l&#8217;environnement, dans un vrai moteur, le gaz quitte le moteur et est remplac\u00e9 par un nouveau m\u00e9lange d&#8217;air et de carburant.<\/span><\/li>\n<li><strong><span>Ajout de chaleur instantan\u00e9<\/span><\/strong><span>\u00a0(ajout de chaleur isochore).\u00a0Dans les moteurs r\u00e9els, l&#8217;apport de chaleur n&#8217;est pas instantan\u00e9, donc la pression de pointe n&#8217;est pas au PMH, mais juste apr\u00e8s le PMH.<\/span><\/li>\n<li><strong><span>Pas de transfert de chaleur (adiabatique)<\/span><\/strong>\n<ul>\n<li><span>Compression &#8211; Le gaz (m\u00e9lange carburant-air) est comprim\u00e9 de mani\u00e8re adiabatique de l&#8217;\u00e9tat 1 \u00e0 l&#8217;\u00e9tat 2. Dans les moteurs r\u00e9els, il y a toujours des inefficacit\u00e9s qui r\u00e9duisent l&#8217;efficacit\u00e9 thermique.<\/span><\/li>\n<li><span>Expansion.\u00a0Le gaz (m\u00e9lange carburant-air) se d\u00e9tend adiabatiquement de l&#8217;\u00e9tat 3 \u00e0 l&#8217;\u00e9tat 4.<\/span><\/li>\n<\/ul>\n<\/li>\n<li><strong><span>Combustion compl\u00e8te<\/span><\/strong><span>\u00a0du m\u00e9lange air-carburant.<\/span><\/li>\n<li><strong><span>Aucun travail de pompage<\/span><\/strong><span>\u00a0.\u00a0Le travail de pompage est la diff\u00e9rence entre le travail effectu\u00e9 pendant la course d&#8217;\u00e9chappement et le travail effectu\u00e9 pendant la course d&#8217;admission.\u00a0Dans les cycles r\u00e9els, il existe une diff\u00e9rence de pression entre les pressions d&#8217;\u00e9chappement et d&#8217;entr\u00e9e.<\/span><\/li>\n<li><strong><span>Aucune perte de purge<\/span><\/strong><span>\u00a0.\u00a0La perte de purge est caus\u00e9e par l&#8217;ouverture pr\u00e9coce des soupapes d&#8217;\u00e9chappement.\u00a0Il en r\u00e9sulte une perte de rendement de travail pendant la course d&#8217;expansion.<\/span><\/li>\n<li><strong><span>Pas de perte par coup<\/span><\/strong><span>\u00a0.\u00a0La perte par soufflage est caus\u00e9e par la fuite de gaz comprim\u00e9s \u00e0 travers les segments de piston et autres crevasses.<\/span><\/li>\n<li><strong><span>Pas de pertes par friction<\/span><\/strong><span>\u00a0.<\/span><\/li>\n<\/ul>\n<p><span>Ces hypoth\u00e8ses et pertes simplificatrices conduisent au fait que la zone ferm\u00e9e (travail) du diagramme pV pour un moteur r\u00e9el est significativement plus petite que la taille de la zone (travail) incluse par le diagramme pV du cycle id\u00e9al.\u00a0En d&#8217;autres termes, le cycle moteur id\u00e9al surestimera le travail net et, si les moteurs tournent \u00e0 la m\u00eame vitesse, une plus grande puissance produite par le moteur r\u00e9el d&#8217;environ 20%.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Taux de compression &#8211; Otto Engine<\/span><\/h2>\n<p><span>Le\u00a0<\/span><strong><span>taux de compression<\/span><\/strong><span>\u00a0,\u00a0<\/span><strong><span>CR<\/span><\/strong><span>\u00a0, est d\u00e9fini comme le rapport du volume au point mort bas et du volume au point mort haut.\u00a0Il s&#8217;agit d&#8217;une caract\u00e9ristique cl\u00e9 pour de nombreux moteurs \u00e0 combustion interne.\u00a0Dans la section suivante, il sera montr\u00e9 que le\u00a0<\/span><strong><span>taux de compression<\/span><\/strong><span>\u00a0d\u00e9termine l&#8217;\u00a0<\/span><strong><span>efficacit\u00e9 thermique<\/span><\/strong><span>\u00a0du cycle thermodynamique utilis\u00e9 du moteur \u00e0 combustion.\u00a0En g\u00e9n\u00e9ral, on souhaite avoir un taux de compression \u00e9lev\u00e9, car cela permet \u00e0 un moteur d&#8217;atteindre une efficacit\u00e9 thermique plus \u00e9lev\u00e9e.<\/span><\/p>\n<p><span>Par exemple, supposons un cycle Otto avec un taux de compression de CR = 10: 1. Le volume de la chambre est de 500 cm\u00b3 = 500 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0m\u00a0<\/span><sup><span>3<\/span><\/sup><span>\u00a0(0,5 l) avant la course de compression.\u00a0Pour ce moteur\u00a0<\/span><strong><span>un<\/span><\/strong><span>\u00a0ll requis volumes sont connus:<\/span><\/p>\n<ul>\n<li><span>V\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>4<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0= 500 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0m\u00a0<\/span><sup><span>3<\/span><\/sup><span>\u00a0(0,5 l)<\/span><\/li>\n<li><span>V\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>min<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0\/ CR = 55,56 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0m\u00a0<\/span><sup><span>3<\/span><\/sup><\/li>\n<\/ul>\n<p><span>Notez que (V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0&#8211; V\u00a0<\/span><sub><span>min<\/span><\/sub><span>\u00a0) x nombre de cylindres = cylindr\u00e9e totale du moteur.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Efficacit\u00e9 thermique pour le cycle Otto<\/span><\/h2>\n<p><span>En g\u00e9n\u00e9ral ,\u00a0le\u00a0<a title=\"Efficacit\u00e9 thermique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lefficacite-thermique-definition\/\"><strong>rendement thermique<\/strong><\/a><a title=\"Efficacit\u00e9 thermique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lefficacite-thermique-definition\/\">\u00a0,\u00a0<\/a><a title=\"Efficacit\u00e9 thermique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lefficacite-thermique-definition\/\"><strong><em>\u03b7\u00a0<\/em><\/strong><\/a><a title=\"Efficacit\u00e9 thermique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lefficacite-thermique-definition\/\"><strong><em><sub>e<\/sub><\/em><\/strong><\/a>\u00a0, d&#8217;un moteur thermique est d\u00e9finie comme \u00e9tant le rapport entre le\u00a0<a href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-le-travail-en-thermodynamique-definition\/\">travail<\/a>\u00a0qu&#8217;elle fait,\u00a0<strong>W<\/strong>\u00a0, \u00e0 la\u00a0<a href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-chaleur-en-physique-chaleur-definition\/\">chaleur<\/a>\u00a0d&#8217; entr\u00e9e \u00e0 la temp\u00e9rature \u00e9lev\u00e9e, Q\u00a0<sub>H<\/sub>\u00a0.<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-formula-1.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-16945 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-formula-1.png\" alt=\"formule d'efficacit\u00e9 thermique - 1\" width=\"125\" height=\"82\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-formula-1.png\" \/><\/a><\/p>\n<p><span>L&#8217;\u00a0<\/span><strong><span>efficacit\u00e9 thermique<\/span><\/strong><span>\u00a0,\u00a0<\/span><strong><em><span>\u03b7\u00a0<\/span><\/em><\/strong><strong><em><sub><span>th<\/span><\/sub><\/em><\/strong><span>\u00a0, repr\u00e9sente la fraction de\u00a0<\/span><strong><span>chaleur<\/span><\/strong><span>\u00a0,\u00a0<\/span><strong><span>Q\u00a0<\/span><\/strong><strong><sub><span>H<\/span><\/sub><\/strong><span>\u00a0, qui est convertie\u00a0<\/span><strong><span>en travail<\/span><\/strong><span>\u00a0.\u00a0Puisque l&#8217;\u00e9nergie est conserv\u00e9e selon la\u00a0<\/span><a href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-premiere-loi-de-la-thermodynamique-definition\/\"><strong><span>premi\u00e8re loi de la thermodynamique<\/span><\/strong><\/a><span>\u00a0et que l&#8217;\u00e9nergie ne peut pas \u00eatre convertie pour fonctionner compl\u00e8tement, l&#8217;apport de chaleur, Q\u00a0<\/span><sub><span>H<\/span><\/sub><span>\u00a0, doit \u00eatre \u00e9gal au travail effectu\u00e9, W, plus la chaleur qui doit \u00eatre dissip\u00e9e sous forme de\u00a0<\/span><strong><span>chaleur r\u00e9siduelle Q\u00a0<\/span><\/strong><strong><sub><span>C<\/span><\/sub><\/strong><span>\u00a0dans le environnement.\u00a0Par cons\u00e9quent, nous pouvons r\u00e9\u00e9crire la formule de l&#8217;efficacit\u00e9 thermique comme suit:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-formula-2.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-16944 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-formula-2.png\" alt=\"formule d'efficacit\u00e9 thermique - 2\" width=\"352\" height=\"83\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-formula-2.png\" \/><\/a><\/p>\n<p><span>La chaleur absorb\u00e9e se produit pendant la combustion du m\u00e9lange carburant-air, lorsque l&#8217;\u00e9tincelle se produit, \u00e0 peu pr\u00e8s \u00e0 volume constant.\u00a0Puisqu&#8217;au cours d&#8217;un\u00a0<\/span><a title=\"Processus isochorique - Processus isom\u00e9trique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-processus-isochorique-processus-isometrique-definition\/\"><span>processus isochore,<\/span><\/a><span>\u00a0aucun travail n&#8217;est effectu\u00e9 par ou sur le syst\u00e8me, la\u00a0<\/span><strong><span>premi\u00e8re loi de la thermodynamique<\/span><\/strong><span>\u00a0dicte\u00a0<\/span><em><span>\u2206U = \u2206Q.\u00a0<\/span><\/em><span>Par cons\u00e9quent, la chaleur ajout\u00e9e et rejet\u00e9e est donn\u00e9e par:<\/span><\/p>\n<p><strong><span>Q\u00a0<\/span><sub><span>add<\/span><\/sub><span>\u00a0= mc\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0(T\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0&#8211; T\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0)<\/span><\/strong><\/p>\n<p><strong><span>Q\u00a0<\/span><sub><span>out<\/span><\/sub><span>\u00a0= mc\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0(T\u00a0<\/span><sub><span>4<\/span><\/sub><span>\u00a0&#8211; T\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0)<\/span><\/strong><\/p>\n<p><span>En substituant ces expressions \u00e0 la chaleur ajout\u00e9e et rejet\u00e9e dans l&#8217;expression pour l&#8217;efficacit\u00e9 thermique, on obtient:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-cycle-efficiency-equation.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17557 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-cycle-efficiency-equation.png\" alt=\"Cycle d'Otto - efficacit\u00e9 - \u00e9quation\" width=\"193\" height=\"65\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-cycle-efficiency-equation.png\" \/><\/a><\/p>\n<p><span>Nous pouvons simplifier l&#8217;expression ci-dessus en utilisant le fait que les processus\u00a0<\/span><strong><span>1 \u2192 2<\/span><\/strong><span>\u00a0et de\u00a0<\/span><strong><span>3 \u2192 4<\/span><\/strong><span>\u00a0sont adiabatiques et pour un processus adiabatique la formule p, V, T suivante est valide:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17558 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\" alt=\"processus adiabatique - formule\" width=\"154\" height=\"84\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\" \/><\/a><\/p>\n<p><span>On peut d\u00e9duire que:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula2.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17559 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula2.png\" alt=\"processus adiabatique - formule 2\" width=\"193\" height=\"77\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula2.png\" \/><\/a><\/p>\n<p><span>Dans cette \u00e9quation, le\u00a0<\/span><strong><span>rapport V\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0\/ V\u00a0<\/span><sub><span>2<\/span><\/sub><\/strong><span>\u00a0est appel\u00e9\u00a0<\/span><strong><span>taux de compression CR<\/span><\/strong><span>\u00a0.\u00a0Lorsque nous r\u00e9\u00e9crivons l&#8217;expression de l&#8217;efficacit\u00e9 thermique en utilisant le taux de compression, nous concluons que l&#8217;\u00a0efficacit\u00e9 thermique du\u00a0<\/span><strong><span>cycle d&#8217;Otto standard de<\/span><\/strong><span>\u00a0l&#8217;\u00a0<strong>air<\/strong>\u00a0est fonction du\u00a0<\/span><strong><span>taux<\/span><\/strong><span>\u00a0de\u00a0<strong>compression<\/strong>\u00a0et de\u00a0\u00a0<\/span><strong><span>\u03ba = c\u00a0<\/span><\/strong><strong><sub><span>p<\/span><\/sub><\/strong><strong><span>\u00a0\/ c\u00a0<\/span><\/strong><strong><sub><span>v<\/span><\/sub><\/strong><span>\u00a0.<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-Otto-Cycle-Compression-ratio.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17560 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-Otto-Cycle-Compression-ratio.png\" alt=\"efficacit\u00e9 thermique - Cycle d'Otto - Taux de compression\" width=\"570\" height=\"80\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-Otto-Cycle-Compression-ratio.png\" \/><\/a><\/p>\n<figure id=\"attachment_17561\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-17561\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-Otto-Cycle-Engine.png\"><img loading=\"lazy\" class=\"size-medium wp-image-17561 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-Otto-Cycle-Engine-300x256.png\" alt=\"efficacit\u00e9 thermique - Cycle Otto - Moteur\" width=\"300\" height=\"256\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/thermal-efficiency-Otto-Cycle-Engine-300x256.png\" \/><\/a><figcaption id=\"caption-attachment-17561\" class=\"wp-caption-text\"><span>Efficacit\u00e9 thermique pour le cycle d&#8217;Otto &#8211; \u03ba = 1,4<\/span><\/figcaption><\/figure>\n<p><span>C&#8217;est une conclusion tr\u00e8s utile, car il est souhaitable d&#8217;atteindre un\u00a0<\/span><strong><span>taux de compression \u00e9lev\u00e9<\/span><\/strong><span>\u00a0pour extraire plus d&#8217;\u00e9nergie m\u00e9canique d&#8217;une masse donn\u00e9e de m\u00e9lange air-carburant.\u00a0Un taux de compression plus \u00e9lev\u00e9 permet d&#8217;atteindre la m\u00eame temp\u00e9rature de combustion avec moins de carburant, tout en prolongeant le cycle de d\u00e9tente.\u00a0Cela cr\u00e9e plus de puissance m\u00e9canique et\u00a0<\/span><strong><span>abaisse la temp\u00e9rature d&#8217;\u00e9chappement<\/span><\/strong><span>\u00a0.\u00a0L&#8217;abaissement de la temp\u00e9rature d&#8217;\u00e9chappement provoque l&#8217;abaissement de l&#8217;\u00e9nergie rejet\u00e9e dans l&#8217;atmosph\u00e8re.\u00a0Cette relation est repr\u00e9sent\u00e9e sur la figure pour \u03ba = 1,4, repr\u00e9sentant l&#8217;air ambiant.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Pression moyenne effective &#8211; MEP<\/span><\/h2>\n<figure id=\"attachment_17562\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-17562\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Mean-Effective-Pressure-Otto-cycle-chart.png\"><img loading=\"lazy\" class=\"size-medium wp-image-17562 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Mean-Effective-Pressure-Otto-cycle-chart-300x250.png\" alt=\"Le MEP est une mesure tr\u00e8s utile de la capacit\u00e9 d'un moteur \u00e0 effectuer un travail ind\u00e9pendant de la cylindr\u00e9e du moteur. \" width=\"300\" height=\"250\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Mean-Effective-Pressure-Otto-cycle-chart-300x250.png\" \/><\/a><figcaption id=\"caption-attachment-17562\" class=\"wp-caption-text\"><span>Le MEP est une mesure tr\u00e8s utile de la capacit\u00e9 d&#8217;un moteur \u00e0 effectuer un travail ind\u00e9pendant de la cylindr\u00e9e du moteur.<\/span><\/figcaption><\/figure>\n<p><span>Un param\u00e8tre utilis\u00e9 par les ing\u00e9nieurs pour d\u00e9crire les performances des moteurs \u00e0 pistons alternatifs est connu sous le nom de\u00a0<\/span><strong><span>pression effective moyenne<\/span><\/strong><span>\u00a0, ou\u00a0<\/span><strong><span>MEP<\/span><\/strong><span>\u00a0.\u00a0<\/span><strong><span>Le MEP<\/span><\/strong><span>\u00a0est une mesure tr\u00e8s utile de la capacit\u00e9 d&#8217;un moteur \u00e0 effectuer un travail ind\u00e9pendant de la cylindr\u00e9e du moteur.\u00a0Il existe plusieurs types de d\u00e9put\u00e9s europ\u00e9ens.\u00a0Ces eurod\u00e9put\u00e9s sont d\u00e9finis par la mesure de l&#8217;emplacement et la m\u00e9thode de calcul (par exemple BMEP ou IMEP).<\/span><\/p>\n<p><span>En g\u00e9n\u00e9ral, la\u00a0<\/span><strong><span>pression moyenne effective<\/span><\/strong><span>\u00a0est la pression constante th\u00e9orique qui, si elle agissait sur le piston pendant la course de puissance, produirait le m\u00eame travail net que celui r\u00e9ellement d\u00e9velopp\u00e9 en un cycle complet.\u00a0Le MEP peut \u00eatre d\u00e9fini comme:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17565 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\" alt=\"pression moyenne effective - d\u00e9finition\" width=\"300\" height=\"63\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\" \/><\/a><\/p>\n<p><span>Par exemple, la\u00a0<\/span><strong><span>pression effective moyenne<\/span><\/strong><span>\u00a0nette\u00a0<strong>indiqu\u00e9e<\/strong>\u00a0, connue sous le nom d&#8217;\u00a0<\/span><strong><span>IMEP\u00a0<\/span><sub><span>n,<\/span><\/sub><\/strong><span>\u00a0est \u00e9gale \u00e0 la pression effective moyenne calcul\u00e9e \u00e0 partir de la pression dans le cylindre (il doit y avoir cette mesure) sur tout le cycle du moteur.\u00a0Notez que c&#8217;est 720 \u00b0 pour un moteur \u00e0 quatre temps et 360 \u00b0 pour un moteur \u00e0 deux temps.<\/span><\/p>\n<p><span>Quelques exemples:<\/span><\/p>\n<ul>\n<li><span>La MEP d&#8217;un moteur \u00e0 essence atmosph\u00e9rique peut varier de 8 \u00e0 11 bars dans la r\u00e9gion du couple maximal.<\/span><\/li>\n<li><span>La MEP d&#8217;un moteur \u00e0 essence turbocompress\u00e9 peut varier de 12 \u00e0 17 bar.<\/span><\/li>\n<li><span>La MEP d&#8217;un moteur diesel atmosph\u00e9rique peut aller de 7 \u00e0 9 bar.<\/span><\/li>\n<li><span>La MEP d&#8217;un moteur diesel turbocompress\u00e9 peut aller de 14 \u00e0 18 bar<\/span><\/li>\n<\/ul>\n<p><span>Par exemple, un moteur \u00e0 essence \u00e0 quatre temps produisant 200 N \u00b7 m \u00e0 partir de 2 litres de cylindr\u00e9e a une MEP de (4\u03c0) (200 N \u00b7 m) \/ (0,002 m\u00b3) = 1256000 Pa = 12 bar.\u00a0Comme on peut le voir, le MEP est des\u00a0<\/span><strong><span>caract\u00e9ristiques<\/span><\/strong><span>\u00a0utiles\u00a0<strong>d&#8217;un moteur<\/strong>\u00a0.\u00a0Pour deux moteurs de cylindr\u00e9e \u00e9gale, celui avec un\u00a0<\/span><strong><span>MEP plus \u00e9lev\u00e9<\/span><\/strong><span>\u00a0produirait le\u00a0<\/span><strong><span>travail net plus important<\/span><\/strong><span>\u00a0et, si les moteurs tournent \u00e0 la m\u00eame vitesse, une\u00a0<\/span><strong><span>plus grande puissance<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Cycle d&#8217;Otto &#8211; Probl\u00e8me avec la solution<\/span><\/h2>\n<p><span>Supposons le\u00a0<\/span><a title=\"Cycle Otto - Moteur Otto\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-otto-cycle-otto-engine-definition\/\"><strong><span>cycle Otto<\/span><\/strong><\/a><span>\u00a0, qui est l&#8217;un des\u00a0<\/span><strong><span>cycles thermodynamiques<\/span><\/strong><span>\u00a0les plus courants\u00a0que l&#8217;on puisse trouver dans les\u00a0<\/span><strong><span>moteurs d&#8217;automobiles<\/span><\/strong><span>\u00a0.\u00a0L&#8217;un des param\u00e8tres cl\u00e9s de ces moteurs est le changement de volume entre le point mort haut (TDC) et le point mort bas (BDC).\u00a0Le rapport de ces volumes (\u00a0<\/span><em><span>V\u00a0<\/span><\/em><em><sub><span>1<\/span><\/sub><\/em><em><span>\u00a0\/ V\u00a0<\/span><\/em><em><sub><span>2<\/span><\/sub><\/em><span>\u00a0) est appel\u00e9\u00a0<\/span><strong><span>taux de compression<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><span>Le\u00a0<\/span><strong><span>taux de compression<\/span><\/strong><span>\u00a0dans un moteur \u00e0 essence ne sera g\u00e9n\u00e9ralement pas beaucoup plus \u00e9lev\u00e9 que 10: 1 en raison du potentiel cognement du moteur (auto-inflammation) et pas inf\u00e9rieur \u00e0 6: 1.\u00a0Par exemple, certains moteurs de voitures de sport peuvent avoir un taux de compression allant jusqu&#8217;\u00e0 12,5: 1 (par exemple Ferrari 458 Italia).<\/span><\/p>\n<figure id=\"attachment_17461\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-17461\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-Cycle-PV-Diagram.png\"><img loading=\"lazy\" class=\"size-medium wp-image-17461 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-Cycle-PV-Diagram-300x245.png\" alt=\"Cycle d'Otto - Diagramme PV\" width=\"300\" height=\"245\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-Cycle-PV-Diagram-300x245.png\" \/><\/a><figcaption id=\"caption-attachment-17461\" class=\"wp-caption-text\"><span>Diagramme pV du cycle d&#8217;Otto.\u00a0La zone d\u00e9limit\u00e9e par la piste cyclable compl\u00e8te repr\u00e9sente le travail total qui peut \u00eatre effectu\u00e9 pendant un cycle.<\/span><\/figcaption><\/figure>\n<p><span>Dans cet exemple, supposons un cycle Otto avec\u00a0<\/span><strong><span>un taux<\/span><\/strong><span>\u00a0de\u00a0<strong>compression<\/strong>\u00a0de\u00a0<\/span><strong><span>CR = 9: 1<\/span><\/strong><span>\u00a0.\u00a0L&#8217;air d&#8217;admission est \u00e0 100 kPa = 1 bar, 20 \u00b0 C, et le volume de la chambre est de 500 cm\u00b3 avant la course de compression.\u00a0La temp\u00e9rature en fin d&#8217;\u00a0<\/span><a title=\"Processus adiabatique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quel-est-le-processus-adiabatique-definition\/\"><span>expansion adiabatique<\/span><\/a><span>\u00a0est T\u00a0<\/span><sub><span>4<\/span><\/sub><span>\u00a0= 800 K.<\/span><\/p>\n<ul>\n<li><span>Capacit\u00e9 thermique sp\u00e9cifique \u00e0 pression d&#8217;air constante \u00e0 pression atmosph\u00e9rique et temp\u00e9rature ambiante:\u00a0<\/span><strong><span>c\u00a0<\/span><\/strong><strong><sub><span>p<\/span><\/sub><\/strong><strong><span>\u00a0= 1,01 kJ \/ kgK.<\/span><\/strong><\/li>\n<li><span>Capacit\u00e9 calorifique sp\u00e9cifique \u00e0 volume d&#8217;air constant \u00e0 pression atmosph\u00e9rique et temp\u00e9rature ambiante:\u00a0<\/span><strong><span>c\u00a0<\/span><\/strong><strong><sub><span>v<\/span><\/sub><\/strong><strong><span>\u00a0= 0,718 kJ \/ kgK.<\/span><\/strong><\/li>\n<li><strong><span>\u03ba = c\u00a0<\/span><\/strong><strong><sub><span>p<\/span><\/sub><\/strong><strong><span>\u00a0\/ c\u00a0<\/span><\/strong><strong><sub><span>v<\/span><\/sub><\/strong><strong><span>\u00a0= 1,4<\/span><\/strong><\/li>\n<\/ul>\n<p><strong><span>Calculer:<\/span><\/strong><\/p>\n<ol>\n<li><strong><span>la masse d&#8217;air d&#8217;admission<\/span><\/strong><\/li>\n<li><strong><span>la temp\u00e9rature T\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><\/li>\n<li><strong><span>la pression p\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><\/li>\n<li><strong><span>la quantit\u00e9 de chaleur ajout\u00e9e par la combustion du m\u00e9lange air-carburant<\/span><\/strong><\/li>\n<li><strong><span>l&#8217;efficacit\u00e9 thermique de ce cycle<\/span><\/strong><\/li>\n<li><strong><span>le d\u00e9put\u00e9 europ\u00e9en<\/span><\/strong><\/li>\n<\/ol>\n<p><strong><span>Solution:<\/span><\/strong><\/p>\n<p><span>1)\u00a0\u00a0<\/span><strong><span>la masse d&#8217;air d&#8217;admission<\/span><\/strong><\/p>\n<p><span>Au d\u00e9but des calculs, nous devons d\u00e9terminer la quantit\u00e9 de gaz dans le cylindre avant la course de compression.\u00a0En utilisant la loi du gaz parfait, nous pouvons trouver la masse:<\/span><\/p>\n<p><strong><em><span>pV = mR\u00a0<\/span><\/em><em><sub><span>sp\u00e9cifique<\/span><\/sub><\/em><em><span>\u00a0T<\/span><\/em><\/strong><\/p>\n<p><span>o\u00f9:<\/span><\/p>\n<ul>\n<li><em><span>p<\/span><\/em><span>\u00a0est la\u00a0<\/span><a title=\"Pression absolue\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/absolute-pressure\/\"><span>pression absolue<\/span><\/a><span>\u00a0du gaz<\/span><\/li>\n<li><em><span>m<\/span><\/em><span>\u00a0est la masse de substance<\/span><\/li>\n<li><em><span>T<\/span><\/em><span>\u00a0est la\u00a0<\/span><a title=\"\u00c9chelle Kelvin - Temp\u00e9rature absolue\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-temperature-physics\/kelvin-scale-absolute-temperature\/\"><span>temp\u00e9rature absolue<\/span><\/a><\/li>\n<li><em><span>V<\/span><\/em><span>\u00a0est le volume<\/span><\/li>\n<li><em><span>R\u00a0<\/span><\/em><em><sub><span>sp\u00e9cifique<\/span><\/sub><\/em><span>\u00a0\u00a0est la constante de gaz sp\u00e9cifique, \u00e9gale \u00e0 la constante de gaz universelle divis\u00e9e par la masse molaire (M) du gaz ou du m\u00e9lange.\u00a0Pour l&#8217;air sec R\u00a0<\/span><sub><span>sp\u00e9cifique<\/span><\/sub><span>\u00a0= 287,1 J.kg\u00a0<\/span><sup><span>-1<\/span><\/sup><span>\u00a0.K\u00a0<\/span><sup><span>-1<\/span><\/sup><span>\u00a0.<\/span><\/li>\n<\/ul>\n<p><span>par cons\u00e9quent<\/span><\/p>\n<p><strong><span>m<\/span><\/strong><span>\u00a0= p\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0V\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0\/ R\u00a0<\/span><sub><span>sp\u00e9cifique<\/span><\/sub><span>\u00a0T\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0= (100000 \u00d7 500 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0) \/ (287,1 \u00d7 293) =\u00a0<\/span><strong><span>5,95 \u00d7 10\u00a0<\/span><\/strong><strong><sup><span>-4<\/span><\/sup><\/strong><strong><span>\u00a0kg<\/span><\/strong><\/p>\n<p><strong><span>Dans ce probl\u00e8me, tous les volumes sont connus:<\/span><\/strong><\/p>\n<ul>\n<li><span>V\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>4<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>max\u00a0<\/span><\/sub><strong><span>=<\/span><\/strong><span>\u00a0500 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0m\u00a0<\/span><sup><span>3<\/span><\/sup><span>\u00a0(0,5 l)<\/span><\/li>\n<li><span>V\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>min<\/span><\/sub><span>\u00a0= V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0\/ CR = 55,56 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0m\u00a0<\/span><sup><span>3<\/span><\/sup><\/li>\n<\/ul>\n<p><span>Notez que (V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0&#8211; V\u00a0<\/span><sub><span>min<\/span><\/sub><span>\u00a0) x nombre de cylindres = cylindr\u00e9e totale du moteur.<\/span><\/p>\n<p><span>2)\u00a0\u00a0<\/span><strong><span>la temp\u00e9rature T\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><\/p>\n<p><span>Puisque le processus est adiabatique, nous pouvons utiliser la relation p, V, T suivante pour les\u00a0<\/span><a title=\"Processus adiabatique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quel-est-le-processus-adiabatique-definition\/\"><span>processus adiabatiques<\/span><\/a><span>\u00a0:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-formula-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17563 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-formula-example.png\" alt=\"formule adiabatique - exemple\" width=\"155\" height=\"78\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-formula-example.png\" \/><\/a><\/p>\n<p><span>Donc<\/span><\/p>\n<p><strong><span>T\u00a0<\/span><sub><span>3<\/span><\/sub><\/strong><span>\u00a0= T\u00a0<\/span><sub><span>4<\/span><\/sub><span>\u00a0.\u00a0CR\u00a0<\/span><sup><span>\u03ba &#8211; 1<\/span><\/sup><span>\u00a0= 800.\u00a09\u00a0<\/span><sup><span>0,4<\/span><\/sup><span>\u00a0=\u00a0<\/span><strong><span>1926 K<\/span><\/strong><\/p>\n<p><span>3)\u00a0\u00a0<\/span><strong><span>la pression p\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><\/p>\n<p><span>Encore une fois, nous pouvons utiliser la\u00a0<\/span><a title=\"Loi du gaz parfait\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/ideal-gas-law\/\"><span>loi du gaz parfait<\/span><\/a><span>\u00a0pour trouver la pression au d\u00e9but de la course de puissance comme:<\/span><\/p>\n<p><strong><span>p\u00a0<\/span><\/strong><strong><sub><span>3<\/span><\/sub><\/strong><span>\u00a0= mR\u00a0<\/span><sub><span>sp\u00e9cifique<\/span><\/sub><span>\u00a0T\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0\/ V\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0= 5,95 \u00d7 10\u00a0<\/span><sup><span>-4<\/span><\/sup><span>\u00a0x 287,1 x 1926 \/ 55,56 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0= 5920000 Pa =\u00a0<\/span><strong><span>59,2 bar<\/span><\/strong><\/p>\n<p><span>4)\u00a0\u00a0<\/span><strong><span>la quantit\u00e9 de chaleur ajout\u00e9e<\/span><\/strong><\/p>\n<p><span>Pour calculer la quantit\u00e9 de chaleur ajout\u00e9e par la combustion du m\u00e9lange air-carburant, Q\u00a0<\/span><sub><span>add<\/span><\/sub><span>\u00a0, nous devons utiliser la\u00a0<\/span><a title=\"Premi\u00e8re loi de la thermodynamique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-premiere-loi-de-la-thermodynamique-definition\/\"><span>premi\u00e8re loi de la thermodynamique<\/span><\/a><span>\u00a0pour le\u00a0<\/span><a title=\"Processus isochorique - Processus isom\u00e9trique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-quun-processus-isochorique-processus-isometrique-definition\/\"><span>processus isochore<\/span><\/a><span>\u00a0, qui indique que Q\u00a0<\/span><sub><span>add<\/span><\/sub><span>\u00a0= \u2206U, donc:<\/span><\/p>\n<p><strong><span>Q\u00a0<\/span><sub><span>add<\/span><\/sub><span>\u00a0= mc\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0(T\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0&#8211; T\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0)<\/span><\/strong><\/p>\n<p><span>la temp\u00e9rature \u00e0 la fin de la course de compression peut \u00eatre d\u00e9termin\u00e9e en utilisant la relation p, V, T pour les processus adiabatiques entre les points\u00a0<\/span><strong><span>1 \u2192 2.<\/span><\/strong><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17558 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\" alt=\"processus adiabatique - formule\" width=\"154\" height=\"84\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/adiabatic-process-formula.png\" \/><\/a><\/p>\n<p><strong><span>T\u00a0<\/span><sub><span>2<\/span><\/sub><\/strong><span>\u00a0= T\u00a0<\/span><sub><span>1<\/span><\/sub><span>\u00a0.\u00a0CR\u00a0<\/span><sup><span>\u03ba &#8211; 1<\/span><\/sup><span>\u00a0= 293.\u00a09\u00a0<\/span><sup><span>0,4<\/span><\/sup><span>\u00a0=\u00a0<\/span><strong><span>706 K<\/span><\/strong><\/p>\n<p><span>ensuite<\/span><\/p>\n<p><strong><span>Q\u00a0<\/span><\/strong><strong><sub><span>add<\/span><\/sub><\/strong><span>\u00a0= mc\u00a0<\/span><sub><span>v<\/span><\/sub><span>\u00a0(T\u00a0<\/span><sub><span>3<\/span><\/sub><span>\u00a0&#8211; T\u00a0<\/span><sub><span>2<\/span><\/sub><span>\u00a0) = 5,95 \u00d7 10\u00a0<\/span><sup><span>-4<\/span><\/sup><span>\u00a0x 718 x 1220 =\u00a0<\/span><strong><span>521,2 J<\/span><\/strong><\/p>\n<p><span>5)\u00a0\u00a0<\/span><strong><span>l&#8217;efficacit\u00e9 thermique<\/span><\/strong><\/p>\n<p><a title=\"Efficacit\u00e9 thermique\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lefficacite-thermique-definition\/\"><strong><span>Efficacit\u00e9 thermique<\/span><\/strong><\/a><span>\u00a0pour un cycle Otto:<\/span><\/p>\n<p><span>Comme d\u00e9riv\u00e9 dans la section pr\u00e9c\u00e9dente, l&#8217;efficacit\u00e9 thermique d&#8217;un cycle d&#8217;Otto est fonction du taux de compression et de \u03ba:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-cycle-efficiency-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17564 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-cycle-efficiency-example.png\" alt=\"Cycle d'Otto - efficacit\u00e9 - exemple\" width=\"309\" height=\"172\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Otto-cycle-efficiency-example.png\" \/><\/a><\/p>\n<p><span>6)\u00a0\u00a0<\/span><strong><span>la pression moyenne effective<\/span><\/strong><\/p>\n<p><span>Le\u00a0<\/span><strong><span>d\u00e9put\u00e9 europ\u00e9en a<\/span><\/strong><span>\u00a0\u00e9t\u00e9 d\u00e9fini comme:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-17565 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\" alt=\"pression moyenne effective - d\u00e9finition\" width=\"300\" height=\"63\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/mean-effective-pressure-definition.png\" \/><\/a><\/p>\n<p><span>Si cette \u00e9quation, le volume de d\u00e9placement est \u00e9gal \u00e0 V\u00a0<\/span><sub><span>max<\/span><\/sub><span>\u00a0&#8211; V\u00a0<\/span><sub><span>min<\/span><\/sub><span>\u00a0.\u00a0Le travail net pour un cycle peut \u00eatre calcul\u00e9 en utilisant la chaleur ajout\u00e9e et l&#8217;efficacit\u00e9 thermique:<\/span><\/p>\n<p><strong><em><span>W\u00a0<\/span><\/em><\/strong><strong><em><sub><span>net<\/span><\/sub><\/em><\/strong><em><span>\u00a0=\u00a0<\/span><\/em><em><span>Q\u00a0<\/span><\/em><em><sub><span>add<\/span><\/sub><\/em><em><span>\u00a0.\u00a0\u03b7\u00a0<\/span><\/em><em><sub><span>Otto<\/span><\/sub><\/em><em><span>\u00a0=\u00a0<\/span><\/em><em><span>521,2 x 0,5847 =\u00a0<\/span><strong><span>304,7 J<\/span><\/strong><\/em><br \/>\n<strong><em><span>MEP<\/span><\/em><\/strong><em><span>\u00a0= 304,7 \/ (<\/span><\/em><span>\u00a0500 \u00d7 10<\/span><sup><span>\u00a0-6<\/span><\/sup><span>\u00a0&#8211; 55,56 \u00d7 10<\/span><sup><span>\u00a0-6\u00a0<\/span><\/sup><em><span>) = 685,6 kPa =\u00a0<\/span><strong><span>6,856 bar<\/span><\/strong><\/em><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\"><\/div>\n<\/div>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Th\u00e9orie du cycle d&#8217;Otto &#8211; Moteur \u00e0 essence.\u00a0Le cycle d&#8217;Otto comprend quatre processus r\u00e9versibles en interne.\u00a0L&#8217;efficacit\u00e9 thermique d\u00e9pend du taux de compression.\u00a0G\u00e9nie thermique Cycle Otto &#8211; Moteur Otto En 1876, un ing\u00e9nieur allemand,\u00a0Nikolaus August Otto, a fait\u00a0progresser l\u2019\u00e9tude des moteurs thermiques en construisant le premier moteur \u00e0 quatre temps en fonctionnement.\u00a0un moteur fixe utilisant un &#8230; <a title=\"Quelle est la th\u00e9orie du cycle d&#8217;Otto &#8211; Moteur \u00e0 essence &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-theorie-du-cycle-dotto-moteur-a-essence-definition\/\" aria-label=\"En savoir plus sur Quelle est la th\u00e9orie du cycle d&#8217;Otto &#8211; Moteur \u00e0 essence &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Quelle est la th\u00e9orie du cycle d&#039;Otto - Moteur \u00e0 essence - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"Th\u00e9orie du cycle d&#039;Otto - Moteur \u00e0 essence. Le cycle d&#039;Otto comprend quatre processus r\u00e9versibles en interne. L&#039;efficacit\u00e9 thermique d\u00e9pend du taux de compression. G\u00e9nie thermique\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-la-theorie-du-cycle-dotto-moteur-a-essence-definition\/\" \/>\n<meta property=\"og:locale\" content=\"fr_FR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Quelle est la th\u00e9orie du cycle d&#039;Otto - Moteur \u00e0 essence - D\u00e9finition\" \/>\n<meta property=\"og:description\" content=\"Th\u00e9orie du cycle d&#039;Otto - Moteur \u00e0 essence. Le cycle d&#039;Otto comprend quatre processus r\u00e9versibles en interne. L&#039;efficacit\u00e9 thermique d\u00e9pend du taux de compression. 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