{"id":53053,"date":"2020-03-02T17:02:24","date_gmt":"2020-03-02T16:02:24","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/quest-ce-que-la-perte-de-charge-mineure-pertes-locales-definition\/"},"modified":"2020-03-02T17:02:24","modified_gmt":"2020-03-02T16:02:24","slug":"quest-ce-que-la-perte-de-charge-mineure-pertes-locales-definition","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-perte-de-charge-mineure-pertes-locales-definition\/","title":{"rendered":"Qu\u2019est-ce que la perte de charge mineure &#8211; Pertes locales &#8211; D\u00e9finition"},"content":{"rendered":"<p><span>Les pertes de charge mineures sont des pertes de charge locales ou des chutes de pression de divers \u00e9l\u00e9ments hydrauliques tels que des coudes, des raccords, des vannes, des coudes, des t\u00e9s ou des canaux chauffants.\u00a0<\/span><span>G\u00e9nie thermique<\/span><\/p>\n<p>&nbsp;<\/p>\n<h2><span>Perte de t\u00eate mineure &#8211; Pertes locales<\/span><\/h2>\n<p><span>Dans l&#8217;industrie, tout syst\u00e8me de tuyauterie contient diff\u00e9rents \u00e9l\u00e9ments technologiques tels que des\u00a0<\/span><strong><span>coudes, des raccords, des vannes ou des canaux chauffants<\/span><\/strong><span>\u00a0.\u00a0Ces composants suppl\u00e9mentaires\u00a0<\/span><strong><span>augmentent la perte<\/span><\/strong><span>\u00a0de charge\u00a0<strong>globale<\/strong>\u00a0du syst\u00e8me.\u00a0Ces pertes sont g\u00e9n\u00e9ralement appel\u00e9es\u00a0<\/span><strong><span>pertes mineures<\/span><\/strong><span>\u00a0, bien qu&#8217;elles repr\u00e9sentent souvent une part importante de la\u00a0<\/span><a title=\"Perte de t\u00eate - Perte de pression\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/head-loss\/\"><span>perte de charge<\/span><\/a><span>\u00a0.\u00a0Pour les syst\u00e8mes de tuyaux relativement courts, avec un nombre relativement important de coudes et de raccords,\u00a0<\/span><strong><span>les pertes mineures peuvent facilement d\u00e9passer\u00a0<\/span><a title=\"Perte de t\u00eate majeure - Perte par friction\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/\"><span>les pertes majeures<\/span><\/a><\/strong><span>\u00a0(en particulier avec une vanne partiellement ferm\u00e9e qui peut provoquer une perte de pression plus importante qu&#8217;un long tuyau, en fait quand une vanne est ferm\u00e9e ou presque ferm\u00e9e, la perte mineure est infinie).<\/span><\/p>\n<p><span>Les pertes mineures sont g\u00e9n\u00e9ralement mesur\u00e9es exp\u00e9rimentalement.\u00a0Les donn\u00e9es, en particulier pour les vannes, d\u00e9pendent quelque peu de la conception particuli\u00e8re du fabricant.<\/span><\/p>\n<p><span>Tout comme le frottement des tuyaux, les pertes mineures sont \u00e0 peu\u00a0<\/span><strong><span>pr\u00e8s proportionnelles au carr\u00e9 du d\u00e9bit<\/span><\/strong><span>\u00a0et peuvent donc \u00eatre facilement int\u00e9gr\u00e9es dans l&#8217;\u00a0<\/span><strong><a title=\"\u00c9quation de Darcy-Weisbach\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/darcy-weisbach-equation\/\"><span>\u00e9quation de Darcy-Weisbach<\/span><\/a><\/strong><span>\u00a0.\u00a0<\/span><strong><span>K<\/span><\/strong><span>\u00a0est la somme de tous les coefficients de perte dans la longueur du tuyau, chacun contribuant \u00e0 la perte de charge globale.<\/span><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14589 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/minor-head-loss-equation.png\" alt=\"perte de t\u00eate mineure - \u00e9quation\" width=\"238\" height=\"72\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/minor-head-loss-equation.png\" \/><\/p>\n<p><span>Il existe\u00a0<\/span><strong><span>plusieurs m\u00e9thodes<\/span><\/strong><span> pour calculer la perte de charge des raccords, des coudes et des coudes. Dans la section suivante, ces m\u00e9thodes sont r\u00e9sum\u00e9es dans l&#8217;ordre du plus simple au plus sophistiqu\u00e9.\u00a0<\/span><\/p>\n<div class=\"su-accordion\">\n<div class=\"su-spoiler su-spoiler-style-default su-spoiler-icon-plus su-spoiler-closed\">\n<div class=\"su-spoiler-content su-clearfix\">\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"su-spacer\"><\/div>\n<h2><span>M\u00e9thode de longueur \u00e9quivalente<\/span><\/h2>\n<p><strong><span>La m\u00e9thode de longueur \u00e9quivalente<\/span><\/strong><span>\u00a0(\u00a0<strong>m\u00e9thode\u00a0<\/strong><\/span><strong><span>L\u00a0<\/span><sub><span>e<\/span><\/sub><span>\u00a0\/ D<\/span><\/strong><span>\u00a0) permet \u00e0 l&#8217;utilisateur de d\u00e9crire la perte de pression \u00e0 travers un coude ou un raccord comme une\u00a0<\/span><strong><span>longueur de tuyau droit<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><span>Cette m\u00e9thode est bas\u00e9e sur l&#8217;observation que les pertes importantes sont \u00e9galement proportionnelles \u00e0 la\u00a0<\/span><a title=\"T\u00eate de vitesse\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/velocity-head\/\"><span>t\u00eate de vitesse<\/span><\/a><span>\u00a0(\u00a0<\/span><strong><em><span>v\u00a0<\/span><\/em><em><sup><span>2<\/span><\/sup><\/em><em><span>\u00a0\/ 2g<\/span><\/em><\/strong><span>\u00a0).<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/equivalent-length-method.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14695 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/equivalent-length-method.png\" alt=\"m\u00e9thode de longueur \u00e9quivalente\" width=\"166\" height=\"62\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/equivalent-length-method.png\" \/><\/a><\/p>\n<p><span>La\u00a0m\u00e9thode\u00a0L\u00a0<\/span><sub><span>e<\/span><\/sub><span>\u00a0\/ D\u00a0<\/span><strong><span>augmente simplement le facteur multiplicateur<\/span><\/strong><span>\u00a0dans l&#8217;\u00a0<\/span><a title=\"\u00c9quation de Darcy-Weisbach\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/darcy-weisbach-equation\/\"><strong><span>\u00e9quation de Darcy-Weisbach<\/span><\/strong><\/a><span>\u00a0(c&#8217;est-\u00e0-dire\u00a0<strong><em>\u0192.L \/ D<\/em><\/strong>\u00a0) par une longueur de tuyau droit (c&#8217;est-\u00e0-dire\u00a0<em>L\u00a0<\/em><em><sub>e<\/sub><\/em>\u00a0) qui donnerait lieu \u00e0 une perte de pression \u00e9quivalente aux pertes dans le raccords, d&#8217;o\u00f9 le nom de \u00ablongueur \u00e9quivalente\u00bb.\u00a0Le facteur multiplicateur devient donc\u00a0<strong><em>\u0192 (L + L\u00a0<\/em><\/strong><strong><em><sub>e<\/sub><\/em><\/strong><strong><em>\u00a0) \/ D<\/em><\/strong>\u00a0et l&#8217;\u00e9quation pour le calcul de la perte de charge du syst\u00e8me est donc:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/equivalent-length.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14694 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/equivalent-length.png\" alt=\"longueur \u00e9quivalente\" width=\"235\" height=\"78\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/equivalent-length.png\" \/><\/a><\/p>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-equivalent-lengths-valves-elbows-bends.png\"><img loading=\"lazy\" class=\"alignright size-full wp-image-14693 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-equivalent-lengths-valves-elbows-bends.png\" alt=\"tableau des longueurs \u00e9quivalentes - soupapes, coudes, coudes\" width=\"260\" height=\"256\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-equivalent-lengths-valves-elbows-bends.png\" \/><\/a><span>Tous les raccords, coudes, t\u00e9s peuvent \u00eatre additionn\u00e9s pour faire\u00a0<\/span><strong><span>une longueur totale<\/span><\/strong><span>\u00a0et la perte de pression calcul\u00e9e \u00e0 partir de cette longueur.\u00a0<\/span><strong><span>Il a \u00e9t\u00e9 constat\u00e9 exp\u00e9rimentalement<\/span><\/strong><span>\u00a0que si les longueurs \u00e9quivalentes pour une gamme de tailles d&#8217;un type donn\u00e9 de raccord sont divis\u00e9es par les\u00a0<\/span><strong><span>diam\u00e8tres<\/span><\/strong><span>\u00a0des raccords, alors un rapport presque constant (c&#8217;est-\u00e0-dire L\u00a0<\/span><sub><span>e<\/span><\/sub><span>\u00a0\/ D) est obtenu.\u00a0L&#8217;avantage de la m\u00e9thode de longueur \u00e9quivalente est qu&#8217;une seule valeur de donn\u00e9es est suffisante pour\u00a0<\/span><strong><span>couvrir toutes les tailles<\/span><\/strong><span>\u00a0de cet ajustement et donc la tabulation de donn\u00e9es de longueur \u00e9quivalente est relativement facile.\u00a0Certaines longueurs \u00e9quivalentes typiques sont indiqu\u00e9es dans le tableau.<\/span><span>Voir aussi:\u00a0<\/span><a href=\"http:\/\/www.katmarsoftware.com\/articles\/pipe-fitting-equivalent-length.htm\"><span>Logiciel de dimensionnement de tuyaux et de calcul de d\u00e9bit<\/span><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>M\u00e9thode du coefficient de r\u00e9sistance &#8211; M\u00e9thode K &#8211; T\u00eate exc\u00e9dentaire<\/span><\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-K-values-valves-elbows-bends.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-14692 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-K-values-valves-elbows-bends-300x292.png\" alt=\"tableau des valeurs K - soupapes, coudes, coudes\" width=\"300\" height=\"292\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/table-of-K-values-valves-elbows-bends-300x292.png\" \/><\/a><strong><span>La m\u00e9thode de coefficient de r\u00e9sistance (ou K-proc\u00e9d\u00e9, ou proc\u00e9d\u00e9 de t\u00eate en\u00a0exc\u00e8s)<\/span><\/strong><span>\u00a0permet \u00e0\u00a0l&#8217;utilisateur de d\u00e9crire la\u00a0<\/span><strong><span>chute de pression<\/span><\/strong><span>\u00a0\u00e0 travers un coude ou un raccord par un\u00a0<\/span><strong><span>num\u00e9ro de dimension &#8211; K<\/span><\/strong><span>\u00a0.\u00a0Ce nombre sans dimension (K) peut \u00eatre incorpor\u00e9 dans l&#8217;\u00a0<\/span><a title=\"\u00c9quation de Darcy-Weisbach\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/darcy-weisbach-equation\/\"><strong><span>\u00e9quation de Darcy-Weisbach<\/span><\/strong><\/a><span>\u00a0d&#8217;une mani\u00e8re tr\u00e8s similaire \u00e0 la m\u00e9thode de la longueur \u00e9quivalente.\u00a0Au lieu de donn\u00e9es de longueur \u00e9quivalente dans ce cas, le nombre sans dimension (K) est utilis\u00e9 pour caract\u00e9riser le raccord sans le lier aux propri\u00e9t\u00e9s du tuyau.<\/span><\/p>\n<p><span>La valeur K repr\u00e9sente le\u00a0<\/span><strong><span>multiple des\u00a0<\/span><a title=\"T\u00eate de vitesse\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/velocity-head\/\"><span>t\u00eates<\/span><\/a><\/strong><span><strong>\u00a0de\u00a0<\/strong><strong><a title=\"T\u00eate de vitesse\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/velocity-head\/\">vitesse<\/a><\/strong>\u00a0qui seront perdues par le fluide traversant le raccord.\u00a0L&#8217;\u00e9quation de calcul de la perte de charge de l&#8217;\u00e9l\u00e9ment hydraulique est donc:<\/span><br \/>\n<a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-method.png\"><img loading=\"lazy\" class=\"size-full wp-image-14691 aligncenter lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-method.png\" alt=\"M\u00e9thode de la valeur K\" width=\"133\" height=\"63\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-method.png\" \/><\/a><span>Par cons\u00e9quent, l&#8217;\u00e9quation pour le calcul de la perte de pression de l&#8217;ensemble du syst\u00e8me hydraulique est:<\/span><br \/>\n<a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-head-loss.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14690 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-head-loss.png\" alt=\"Valeur K - perte de charge\" width=\"240\" height=\"61\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/K-value-head-loss.png\" \/><\/a><br \/>\n<span>La\u00a0<\/span><strong><span>valeur K<\/span><\/strong><span>\u00a0peut \u00eatre caract\u00e9ris\u00e9e pour diff\u00e9rents\u00a0<\/span><a title=\"R\u00e9gime de flux\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/flow-regime\/\"><span>r\u00e9gimes d&#8217;\u00e9coulement<\/span><\/a><span>\u00a0(c&#8217;est-\u00e0-dire selon le\u00a0<\/span><a title=\"Le num\u00e9ro de Reynold\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\"><span>nombre de Reynolds<\/span><\/a><span>\u00a0), ce qui la rend plus pr\u00e9cise que la m\u00e9thode de la longueur \u00e9quivalente.<\/span><\/p>\n<p><span>Il existe plusieurs autres m\u00e9thodes pour calculer la perte de pression des raccords, ces m\u00e9thodes sont\u00a0<\/span><strong><span>plus sophistiqu\u00e9es<\/span><\/strong><span>\u00a0et \u00e9galement\u00a0<\/span><strong><span>plus pr\u00e9cises<\/span><\/strong><span>\u00a0:<\/span><\/p>\n<ul>\n<li><strong><span>M\u00e9thode 2K<\/span><\/strong><span>\u00a0.\u00a0La m\u00e9thode 2K est une technique d\u00e9velopp\u00e9e par Hooper BW pour pr\u00e9dire la perte de charge dans un coude, une valve ou un t\u00e9.\u00a0La m\u00e9thode 2K am\u00e9liore la m\u00e9thode de la t\u00eate exc\u00e9dentaire en caract\u00e9risant la variation de la perte de pression due \u00e0 la\u00a0<\/span><strong><span>variation du nombre de Reynolds<\/span><\/strong><span>\u00a0.\u00a0La m\u00e9thode 2-K est avantageuse par rapport \u00e0 une autre m\u00e9thode, en particulier dans la\u00a0<\/span><a title=\"\u00c9coulement laminaire - \u00c9coulement visqueux\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lecoulement-laminaire-ecoulement-visqueux-definition\/\"><strong><span>r\u00e9gion d&#8217;\u00e9coulement laminaire<\/span><\/strong><\/a><span>\u00a0.<\/span><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/2K-method.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14689 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/2K-method.png\" alt=\"M\u00e9thode 2K\" width=\"199\" height=\"49\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/2K-method.png\" \/><\/a><\/li>\n<\/ul>\n<ul>\n<li><strong><span>M\u00e9thode 3K<\/span><\/strong><span>\u00a0.\u00a0La m\u00e9thode 3K (par Ron Darby en 1999) am\u00e9liore encore la pr\u00e9cision du calcul de la perte de pression en caract\u00e9risant \u00e9galement le\u00a0<\/span><strong><span>changement des proportions g\u00e9om\u00e9triques<\/span><\/strong><span>\u00a0d&#8217;un raccord \u00e0 mesure que sa taille change.\u00a0Cela rend la m\u00e9thode 3K particuli\u00e8rement\u00a0<\/span><strong><span>pr\u00e9cise pour un syst\u00e8me avec de grands raccords<\/span><\/strong><span>\u00a0.<\/span><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/3K-method.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14688 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/3K-method.png\" alt=\"M\u00e9thode 3K\" width=\"215\" height=\"58\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/3K-method.png\" \/><\/a><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<h2><span>Sommaire:<\/span><\/h2>\n<ul>\n<li><span>La perte de charge du syst\u00e8me hydraulique est divis\u00e9e en\u00a0<\/span><strong><span>deux cat\u00e9gories principales<\/span><\/strong><span>\u00a0:<\/span>\n<ul>\n<li><a title=\"Perte de t\u00eate majeure - Perte par friction\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/\"><strong><span>Perte de charge importante<\/span><\/strong><\/a><span>\u00a0&#8211; due au frottement dans des tuyaux droits<\/span><\/li>\n<li><strong><span>Perte de charge mineure<\/span><\/strong><span>\u00a0&#8211; due \u00e0 des composants comme des valves, des coudes\u2026<\/span><\/li>\n<\/ul>\n<\/li>\n<li><span>Une\u00a0<\/span><strong><span>forme sp\u00e9ciale de l&#8217;\u00e9quation de Darcy<\/span><\/strong><span>\u00a0peut \u00eatre utilis\u00e9e pour calculer\u00a0<\/span><strong><span>les pertes mineures<\/span><\/strong><span>\u00a0.<\/span><\/li>\n<li><span>Les pertes mineures sont \u00e0\u00a0peu pr\u00e8s proportionnelle \u00e0 la\u00a0<\/span><strong><span>place du d\u00e9bit<\/span><\/strong><span>\u00a0et par\u00a0cons\u00e9quent ,\u00a0ils peuvent \u00eatre int\u00e9gr\u00e9s facilement dans l&#8217;\u00e9quation de\u00a0Darcy-Weisbach par\u00a0<\/span><strong><span>coefficient de r\u00e9sistance K<\/span><\/strong><span>\u00a0.<\/span><\/li>\n<li><span>En tant que perte de pression locale,\u00a0<\/span><strong><span>l&#8217;acc\u00e9l\u00e9ration du fluide dans un canal chauff\u00e9<\/span><\/strong><span>\u00a0peut \u00e9galement \u00eatre envisag\u00e9e.<\/span><\/li>\n<\/ul>\n<p><span>Il existe les m\u00e9thodes suivantes:<\/span><\/p>\n<ul>\n<li><strong><span>M\u00e9thode de longueur \u00e9quivalente<\/span><\/strong><\/li>\n<li><strong><span>M\u00e9thode K (m\u00e9thode du coefficient de r\u00e9sistance)<\/span><\/strong><\/li>\n<li><strong><span>M\u00e9thode 2K<\/span><\/strong><\/li>\n<li><strong><span>M\u00e9thode 3K<\/span><\/strong><\/li>\n<\/ul>\n<h2><span>Pourquoi la perte de t\u00eate est tr\u00e8s importante?<\/span><\/h2>\n<p><span>Comme on peut le voir sur la photo, la perte de charge est\u00a0<\/span><strong><span>une caract\u00e9ristique cl\u00e9<\/span><\/strong><span>\u00a0de tout syst\u00e8me hydraulique.\u00a0Dans les syst\u00e8mes dans lesquels un certain d\u00e9bit doit \u00eatre maintenu (par exemple pour assurer un refroidissement ou un transfert de chaleur suffisant \u00e0 partir d&#8217;un\u00a0<\/span><a title=\"Noyau du r\u00e9acteur\" href=\"https:\/\/www.reactor-physics.com\/what-is-reactor-core-definition\/\"><span>c\u0153ur de r\u00e9acteur<\/span><\/a><span>\u00a0),\u00a0<\/span><strong><span>l&#8217;\u00e9quilibre<\/span><\/strong><span>\u00a0de la\u00a0<\/span><strong><span>perte de charge<\/span><\/strong><span>\u00a0et de la\u00a0\u00a0<\/span><strong><span>t\u00eate ajout\u00e9e<\/span><\/strong><span>\u00a0par une pompe d\u00e9termine le d\u00e9bit \u00e0 travers le syst\u00e8me.<\/span><\/p>\n<figure id=\"attachment_14299\" class=\"wp-caption aligncenter\" aria-describedby=\"caption-attachment-14299\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Head-Q-H.png\"><img loading=\"lazy\" class=\"size-medium wp-image-14299 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Head-Q-H-300x207.png\" alt=\"Diagramme caract\u00e9ristique QH de la pompe centrifuge et de la canalisation\" width=\"300\" height=\"207\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Head-Q-H-300x207.png\" \/><\/a><figcaption id=\"caption-attachment-14299\" class=\"wp-caption-text\"><span>Diagramme caract\u00e9ristique QH de la pompe centrifuge et de la canalisation<\/span><\/figcaption><\/figure>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>\u00c9coulement \u00e0 travers le coude &#8211; perte mineure<\/span><\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/flow-through-elbow-minor-loss.png\"><img loading=\"lazy\" class=\"alignright size-full wp-image-14687 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/flow-through-elbow-minor-loss.png\" alt=\"\u00e9coulement \u00e0 travers le coude - perte mineure\" width=\"252\" height=\"498\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/flow-through-elbow-minor-loss.png\" \/><\/a><span>L&#8217;\u00e9coulement \u00e0 travers les coudes est assez\u00a0<\/span><strong><span>compliqu\u00e9<\/span><\/strong><span>\u00a0.\u00a0En fait, tout tuyau courbe induit toujours une perte plus importante que le simple tuyau droit.\u00a0Cela est d\u00fb au fait que dans un tuyau courbe, le\u00a0<\/span><strong><span>flux se s\u00e9pare<\/span><\/strong><span>\u00a0sur les parois courbes.\u00a0Pour un tr\u00e8s petit rayon de courbure, le flux entrant est m\u00eame incapable de faire le virage au coude, donc le flux se s\u00e9pare et\u00a0<\/span><strong><span>stagne en partie<\/span><\/strong><span>\u00a0contre le c\u00f4t\u00e9 oppos\u00e9 du tuyau.\u00a0Dans cette partie du virage, la pression augmente (en raison du\u00a0<\/span><a title=\"\u00c9quation de Bernoulli - Principe de Bernoulli\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-lequation-de-bernoulli-principe-de-bernoulli-definition\/\"><span>principe de Bernoulli<\/span><\/a><span>\u00a0) et la vitesse diminue.<\/span><\/p>\n<p><span>Une caract\u00e9ristique int\u00e9ressante des\u00a0<\/span><strong><span>valeurs K<\/span><\/strong><span>\u00a0pour les coudes est leur\u00a0<\/span><strong><span>comportement non monotone<\/span><\/strong><span>\u00a0lorsque le rapport\u00a0<\/span><strong><span>R \/ D<\/span><\/strong><span>\u00a0augmente.\u00a0Les valeurs K incluent \u00e0 la fois les pertes locales et les pertes par frottement du tuyau.\u00a0Les pertes locales, caus\u00e9es par la s\u00e9paration des flux et le flux secondaire, diminuent avec R \/ D, tandis que les pertes par frottement augmentent car la longueur de pliage augmente.\u00a0Par cons\u00e9quent, il y a un\u00a0<\/span><strong><span>minimum dans la valeur K<\/span><\/strong><span>\u00a0pr\u00e8s du rayon de courbure normalis\u00e9 de 3.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Acc\u00e9l\u00e9ration fluide<\/span><\/h2>\n<figure id=\"attachment_14174\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-14174\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/water-density-temperature.png\"><img loading=\"lazy\" class=\"size-medium wp-image-14174 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/water-density-temperature-300x211.png\" alt=\"Graphique - densit\u00e9 - eau - temp\u00e9rature\" width=\"300\" height=\"211\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/water-density-temperature-300x211.png\" \/><\/a><figcaption id=\"caption-attachment-14174\" class=\"wp-caption-text\"><span>Densit\u00e9 de l&#8217;eau liquide (comprim\u00e9e) en fonction de la temp\u00e9rature de l&#8217;eau<\/span><\/figcaption><\/figure>\n<p><strong><span>Il est connu que lorsque le fluide est\u00a0<\/span><span>chauff\u00e9<\/span><span>\u00a0(par exemple dans un canal de carburant), le\u00a0<\/span><span>fluide se dilate<\/span><span>\u00a0(modification de la densit\u00e9 du fluide) et\u00a0<\/span><span>augmente sa vitesse d&#8217;\u00e9coulement<\/span><span>\u00a0en raison de l&#8217;\u00a0<\/span><a title=\"\u00c9quation de continuit\u00e9\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-lequation-de-continuite-definition\/\"><span>\u00e9quation de continuit\u00e9<\/span><\/a><span>\u00a0(la section transversale du canal reste la m\u00eame).\u00a0<\/span><span>Pour un volume de contr\u00f4le qui a une seule entr\u00e9e et une seule sortie, cette \u00e9quation indique que, pour un d\u00e9bit en r\u00e9gime permanent, le d\u00e9bit massique dans le volume doit \u00eatre \u00e9gal au d\u00e9bit massique sortant.<\/span><\/strong><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/fluid-acceleration-pressure-drop.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14725 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/fluid-acceleration-pressure-drop.png\" alt=\"acc\u00e9l\u00e9ration du fluide - chute de pression\" width=\"143\" height=\"69\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/fluid-acceleration-pressure-drop.png\" \/><\/a><br \/>\n<span>Masse entrant par unit\u00e9 de temps = Masse sortant par unit\u00e9 de temps<\/span><\/p>\n<p><span>Voir aussi:\u00a0<\/span><a title=\"Liquide satur\u00e9 et sous-refroidi\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/materials-nuclear-engineering\/properties-steam-what-is-steam\/saturated-and-subcooled-liquid\/\"><span>Propri\u00e9t\u00e9s de l&#8217;eau sous-refroidie<\/span><\/a><\/p>\n<p><span>Un autre principe tr\u00e8s important stipule (\u00a0<\/span><a title=\"\u00c9quation de Bernoulli - Principe de Bernoulli\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quelle-est-lequation-de-bernoulli-principe-de-bernoulli-definition\/\"><span>le principe de Bernoulli<\/span><\/a><span>\u00a0) que l&#8217;\u00a0<\/span><strong><span>augmentation de la vitesse d&#8217;\u00e9coulement<\/span><\/strong><span>\u00a0dans le canal chauff\u00e9 provoque l&#8217;\u00a0<\/span><strong><span>abaissement de la pression du fluide<\/span><\/strong><span>\u00a0.\u00a0Cette perte de pression peut \u00e9galement \u00eatre consid\u00e9r\u00e9e comme une perte de pression locale et peut \u00eatre calcul\u00e9e \u00e0 partir de l&#8217;\u00e9quation suivante:<\/span><br \/>\n<a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/fluid-acceleration-equation.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14724 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/fluid-acceleration-equation.png\" alt=\"acc\u00e9l\u00e9ration fluide - \u00e9quation\" width=\"259\" height=\"38\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/fluid-acceleration-equation.png\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>D\u00e9bit \u00e0 travers un c\u0153ur de r\u00e9acteur &#8211; acc\u00e9l\u00e9ration du liquide de refroidissement<\/span><\/h2>\n<p><span>Il s&#8217;agit d&#8217;un exemple illustratif, les donn\u00e9es suivantes ne correspondent \u00e0 aucune conception de r\u00e9acteur.<\/span><\/p>\n<figure id=\"attachment_14206\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-14206\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Continuity-Equation-Flow-Rate-min.png\"><img loading=\"lazy\" class=\"size-medium wp-image-14206 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Continuity-Equation-Flow-Rate-min-300x300.png\" alt=\"\u00c9quation de continuit\u00e9 - D\u00e9bits dans le r\u00e9acteur\" width=\"300\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Continuity-Equation-Flow-Rate-min-300x300.png\" \/><\/a><figcaption id=\"caption-attachment-14206\" class=\"wp-caption-text\"><span>Exemple de d\u00e9bits dans un r\u00e9acteur.\u00a0Il s&#8217;agit d&#8217;un exemple illustratif, les donn\u00e9es ne repr\u00e9sentent aucune conception de r\u00e9acteur.<\/span><\/figcaption><\/figure>\n<p><a title=\"PWR - R\u00e9acteur \u00e0 eau sous pression\" href=\"https:\/\/www.nuclear-power.com\/pwr-pressurized-water-reactor\/\"><b><span>Les r\u00e9acteurs \u00e0 eau sous pression<\/span><\/b><\/a><span>\u00a0sont refroidis et\u00a0<\/span><a title=\"Mod\u00e9rateur de neutrons\" href=\"https:\/\/www.nuclear-power.com\/neutron-moderator\/\"><span>mod\u00e9r\u00e9s<\/span><\/a><span>\u00a0par de l&#8217;eau liquide \u00e0 haute pression (par exemple 16 MPa).\u00a0<\/span><span>\u00c0 cette pression, l&#8217;eau bout \u00e0 environ 350 \u00b0 C (662 \u00b0 F).\u00a0La temp\u00e9rature d&#8217;entr\u00e9e de l&#8217;eau est d&#8217;environ 290 \u00b0 C (\u2374 ~ 720 kg \/ m<\/span><sup><span>\u00a03<\/span><\/sup><span>\u00a0).\u00a0L&#8217;eau (liquide de refroidissement) est chauff\u00e9e dans le<\/span><a title=\"Noyau du r\u00e9acteur\" href=\"https:\/\/www.reactor-physics.com\/what-is-reactor-core-definition\/\"><span>\u00a0c\u0153ur<\/span><\/a><span>\u00a0du<a title=\"Noyau du r\u00e9acteur\" href=\"https:\/\/www.reactor-physics.com\/what-is-reactor-core-definition\/\">\u00a0r\u00e9acteur<\/a>\u00a0\u00e0 environ 325 \u00b0 C (65 ~ 654 kg \/ m<\/span><sup><span>\u00a03<\/span><\/sup><span>\u00a0) lorsque l&#8217;eau s&#8217;\u00e9coule \u00e0 travers le c\u0153ur.<\/span><\/p>\n<p><span>Le circuit primaire des REP typiques est divis\u00e9 en 4 boucles ind\u00e9pendantes (diam\u00e8tre de la tuyauterie ~ 700 mm), chaque boucle comprend un\u00a0<\/span><a title=\"G\u00e9n\u00e9rateur de vapeur\" href=\"https:\/\/www.nuclear-power.com\/steam-generator\/\"><span>g\u00e9n\u00e9rateur de vapeur<\/span><\/a><span>\u00a0et une\u00a0<\/span><a title=\"Pompe de refroidissement du r\u00e9acteur\" href=\"https:\/\/www.nuclear-power.com\/reactor-coolant-pump\/\"><span>pompe de refroidissement principale<\/span><\/a><span>\u00a0.\u00a0\u00c0 l&#8217;int\u00e9rieur de la cuve du r\u00e9acteur (RPV), le liquide de refroidissement descend d&#8217;abord \u00e0 l&#8217;ext\u00e9rieur du c\u0153ur du r\u00e9acteur (\u00e0 travers le tuyau de descente).\u00a0Depuis le fond de l&#8217;enceinte sous pression, le flux est invers\u00e9 \u00e0 travers le c\u0153ur, o\u00f9 la\u00a0<\/span><strong><span>temp\u00e9rature<\/span><\/strong><span>\u00a0du\u00a0<strong>liquide de refroidissement augmente<\/strong>\u00a0lors de son passage \u00e0 travers les crayons combustibles et les assemblages form\u00e9s par eux.<\/span><\/p>\n<p><strong><span>Calculer:<\/span><\/strong><\/p>\n<ul>\n<li><span>Perte de pression due \u00e0 l&#8217;\u00a0<\/span><strong><span>acc\u00e9l\u00e9ration<\/span><\/strong><span>\u00a0du\u00a0<strong>liquide de refroidissement<\/strong>\u00a0dans un canal de carburant isol\u00e9<\/span><\/li>\n<\/ul>\n<p><span>quand<\/span><\/p>\n<ul>\n<li><span>la\u00a0<\/span><span>vitesse d&#8217;\u00e9coulement \u00e0 l&#8217;\u00a0entr\u00e9e du canal\u00a0<\/span><span>est \u00e9gale \u00e0 5,17 m \/ s<\/span><\/li>\n<li><span>la\u00a0<\/span><span>vitesse d&#8217;\u00e9coulement de\u00a0sortie du canal\u00a0<\/span><span>est \u00e9gale \u00e0 5,69 m \/ s<\/span><\/li>\n<\/ul>\n<p><span>Solution:<\/span><\/p>\n<p><span>La perte de charge due \u00e0 l&#8217;acc\u00e9l\u00e9ration du liquide de refroidissement dans un canal de carburant isol\u00e9 est alors:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/coolant-acceleration-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14727 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/coolant-acceleration-example.png\" alt=\"acc\u00e9l\u00e9ration du liquide de refroidissement - exemple\" width=\"515\" height=\"50\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/coolant-acceleration-example.png\" \/><\/a><\/p>\n<p><span>Ce fait a des cons\u00e9quences importantes.\u00a0En raison de la puissance relative diff\u00e9rente des assemblages combustibles dans un c\u0153ur, ces assemblages combustibles ont\u00a0<\/span><strong><span>une r\u00e9sistance hydraulique diff\u00e9rente<\/span><\/strong><span>\u00a0, ce qui peut induire un \u00e9coulement lat\u00e9ral local du liquide de refroidissement primaire et cela doit \u00eatre pris en compte dans les calculs thermo-hydrauliques.<\/span><\/p>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Cet article est bas\u00e9 sur la traduction automatique de l&#8217;article original en anglais. Pour plus d&#8217;informations, voir l&#8217;article en anglais. Pouvez vous nous aider Si vous souhaitez corriger la traduction, envoyez-la \u00e0 l&#8217;adresse: translations@nuclear-power.com ou remplissez le formulaire de traduction en ligne. Nous appr\u00e9cions votre aide, nous mettrons \u00e0 jour la traduction le plus rapidement possible. Merci<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Les pertes de charge mineures sont des pertes de charge locales ou des chutes de pression de divers \u00e9l\u00e9ments hydrauliques tels que des coudes, des raccords, des vannes, des coudes, des t\u00e9s ou des canaux chauffants.\u00a0G\u00e9nie thermique &nbsp; Perte de t\u00eate mineure &#8211; Pertes locales Dans l&#8217;industrie, tout syst\u00e8me de tuyauterie contient diff\u00e9rents \u00e9l\u00e9ments technologiques &#8230; <a title=\"Qu\u2019est-ce que la perte de charge mineure &#8211; Pertes locales &#8211; D\u00e9finition\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/fr\/quest-ce-que-la-perte-de-charge-mineure-pertes-locales-definition\/\" aria-label=\"En savoir plus sur Qu\u2019est-ce que la perte de charge mineure &#8211; Pertes locales &#8211; D\u00e9finition\">Lire la suite<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[8],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Qu&#039;est-ce qu&#039;une perte de t\u00eate mineure - Pertes locales - D\u00e9finition<\/title>\n<meta name=\"description\" content=\"Les pertes de charge mineures sont des pertes de charge locales ou des chutes de pression de divers \u00e9l\u00e9ments hydrauliques tels que des coudes, des raccords, des vannes, des coudes, des t\u00e9s ou des canaux chauffants. 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