{"id":374403,"date":"2024-06-26T12:43:36","date_gmt":"2024-06-26T11:43:36","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/%e3%83%8a%e3%83%8e%e6%b5%81%e4%bd%93%e3%81%ae%e7%86%b1%e4%bc%9d%e5%b0%8e%e7%8e%87\/"},"modified":"2024-06-26T12:43:36","modified_gmt":"2024-06-26T11:43:36","slug":"%e3%83%8a%e3%83%8e%e6%b5%81%e4%bd%93%e3%81%ae%e7%86%b1%e4%bc%9d%e5%b0%8e%e7%8e%87","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/ja\/%e3%83%8a%e3%83%8e%e6%b5%81%e4%bd%93%e3%81%ae%e7%86%b1%e4%bc%9d%e5%b0%8e%e7%8e%87\/","title":{"rendered":"\u30ca\u30ce\u6d41\u4f53\u306e\u71b1\u4f1d\u5c0e\u7387"},"content":{"rendered":"<p class=\"sidekick\">\u30ca\u30ce\u6d41\u4f53\u306e\u71b1\u4f1d\u5c0e\u7387\u306e\u5411\u4e0a\u30e1\u30ab\u30cb\u30ba\u30e0\u3001\u57fa\u672c\u69cb\u6210\u8981\u7d20\u3001\u7406\u8ad6\u30e2\u30c7\u30eb\u3001\u304a\u3088\u3073\u5b9f\u969b\u306e\u5fdc\u7528\u306b\u3064\u3044\u3066\u8aac\u660e\u3002<\/p>\n<p><img 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\u30ca\u30ce\u7c92\u5b50\u3068\u6db2\u4f53\u306e\u754c\u9762\u3067\u306e\u71b1\u62b5\u6297\u304c\u4f4e\u6e1b\u3057\u3001\u5168\u4f53\u306e\u71b1\u4f1d\u5c0e\u7387\u304c\u9ad8\u307e\u308a\u307e\u3059\u3002<\/li>\n<\/ol>\n<h2>\u71b1\u4f1d\u5c0e\u7387\u306e\u30e2\u30c7\u30eb\u5316<\/h2>\n<p>\u30ca\u30ce\u6d41\u4f53\u306e\u71b1\u4f1d\u5c0e\u7387\u3092\u4e88\u6e2c\u3059\u308b\u305f\u3081\u306e\u7406\u8ad6\u30e2\u30c7\u30eb\u304c\u3044\u304f\u3064\u304b\u63d0\u5531\u3055\u308c\u3066\u3044\u307e\u3059\u3002\u4f8b\u3048\u3070\u3001Hamilton-Crosser\u30e2\u30c7\u30eb\u3084Maxwell\u30e2\u30c7\u30eb\u306f\u30ca\u30ce\u6d41\u4f53\u306e\u884c\u52d5\u3092\u89e3\u6790\u3059\u308b\u4e0a\u3067\u6709\u52b9\u3067\u3059\u3002\u3057\u304b\u3057\u3001\u30ca\u30ce\u6d41\u4f53\u306e\u7279\u6b8a\u306a\u7279\u6027\u3092\u8003\u616e\u3059\u308b\u305f\u3081\u306b\u306f\u3001\u3088\u308a\u8907\u96d1\u306a\u30e2\u30c7\u30eb\u304c\u5fc5\u8981\u3068\u3055\u308c\u308b\u5834\u5408\u304c\u3042\u308a\u307e\u3059\u3002<\/p>\n<h2>\u516c\u5f0f<\/h2>\n<p>\u30ca\u30ce\u6d41\u4f53\u306e\u52b9\u679c\u7684\u306a\u71b1\u4f1d\u5c0e\u7387 (k<sub>nf<\/sub>) \u306f\u3001\u4ee5\u4e0b\u306e\u3088\u3046\u306b\u8868\u3055\u308c\u308b\u3053\u3068\u304c\u3042\u308a\u307e\u3059\u3002<\/p>\n<p>\\[<br \/>\nk_{nf} = k_f \\left( \\frac{k_p + 2k_f &#8211; 2\\phi (k_f &#8211; k_p)}{k_p + 2k_f + \\phi (k_f &#8211; k_p)} \\right)<br 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