{"id":47376,"date":"2019-11-04T05:25:15","date_gmt":"2019-11-04T04:25:15","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao\/"},"modified":"2020-03-05T06:57:09","modified_gmt":"2020-03-05T05:57:09","slug":"o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao\/","title":{"rendered":"O que \u00e9 queda de press\u00e3o &#8211; Conjunto de combust\u00edvel &#8211; Defini\u00e7\u00e3o"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Queda de press\u00e3o &#8211; conjunto de combust\u00edvel.\u00a0Em geral, a queda de press\u00e3o total do conjunto de combust\u00edvel \u00e9 formada pela queda de atrito do pacote de combust\u00edvel e outras quedas de press\u00e3o dos elementos estruturais<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Queda de press\u00e3o &#8211; Montagem de combust\u00edvel<\/h2>\n<p>Em geral,\u00a0<strong>a\u00a0<\/strong><a title=\"Perda de Cabe\u00e7a - Perda de Press\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/head-loss\/\"><strong>queda de press\u00e3o<\/strong><\/a>\u00a0total\u00a0<strong>do conjunto de combust\u00edvel<\/strong>\u00a0\u00e9 formada pela queda de atrito do feixe de combust\u00edvel (dependente da\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/relative-roughness-of-pipe\/\">rugosidade relativa<\/a>\u00a0das barras de combust\u00edvel,\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\">n\u00famero de reynolds<\/a>\u00a0,\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/internal-flow\/hydraulic-diameter-2\/\">di\u00e2metro hidr\u00e1ulico<\/a>\u00a0etc.) e outras quedas de press\u00e3o dos elementos estruturais (bico superior e inferior, grades espa\u00e7adoras ou grades de mistura) )<\/p>\n<p>Veja tamb\u00e9m:\u00a0<a title=\"Acelera\u00e7\u00e3o de Fluidos - Perda de Press\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/minor-head-loss-local-losses\/fluid-acceleration-pressure-loss\/\">Acelera\u00e7\u00e3o de fluidos &#8211; Perda de press\u00e3o<\/a><\/p>\n<p>Em geral, n\u00e3o \u00e9 t\u00e3o simples calcular quedas de press\u00e3o em conjuntos de combust\u00edvel (especialmente as grades espa\u00e7adoras) e isso pertence ao\u00a0<strong>conhecimento<\/strong>\u00a0essencial\u00a0de determinado fabricante de combust\u00edvel.\u00a0Principalmente, as quedas de press\u00e3o s\u00e3o medidas em\u00a0<strong>la\u00e7os hidr\u00e1ulicos experimentais<\/strong>\u00a0, em vez de calculadas.<\/p>\n<p>Os engenheiros usam o\u00a0<a title=\"Coeficiente de perda de press\u00e3o - PLC\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/head-loss\/pressure-loss-coefficient-plc\/\"><strong>coeficiente de perda de press\u00e3o<\/strong><\/a>\u00a0,\u00a0<strong>CLP<\/strong>\u00a0.\u00a0Nota-se K ou\u00a0<strong>\u03be<\/strong>\u00a0\u00a0(pronunciado \u201cxi\u201d).\u00a0Este coeficiente caracteriza a\u00a0<a title=\"Perda de Cabe\u00e7a - Perda de Press\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/head-loss\/\">perda<\/a>\u00a0de\u00a0<a title=\"Perda de Cabe\u00e7a - Perda de Press\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/bernoullis-equation-bernoullis-principle\/head-loss\/\">press\u00e3o<\/a>\u00a0de um determinado sistema hidr\u00e1ulico ou de uma parte de um sistema hidr\u00e1ulico.\u00a0Pode ser facilmente medido em loops hidr\u00e1ulicos.\u00a0O coeficiente de perda de press\u00e3o pode ser definido ou medido para tubos retos e especialmente para\u00a0<a title=\"Menor Perda de Cabe\u00e7a - Perdas Locais\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/minor-head-loss-local-losses\/\"><strong>perdas locais (menores)<\/strong><\/a>\u00a0.<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/PLC-Pressure-loss-coefficient-equations.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20526 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/PLC-Pressure-loss-coefficient-equations.png\" alt=\"CLP - Coeficiente de perda de press\u00e3o - equa\u00e7\u00f5es\" width=\"339\" height=\"375\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/PLC-Pressure-loss-coefficient-equations.png\" \/><\/a><\/p>\n<p>Utilizando dados do exemplo abaixo mencionado, o\u00a0<strong>coeficiente de perda de press\u00e3o<\/strong>\u00a0(somente por atrito do tubo reto) \u00e9 igual a\u00a0<strong>\u03be = f\u00a0<sub>D<\/sub>\u00a0L \/ D\u00a0<sub>H<\/sub>\u00a0= 4.9<\/strong>\u00a0.\u00a0Mas o coeficiente de perda de press\u00e3o geral (incluindo grades espa\u00e7adoras, bocais superior e inferior etc.) \u00e9 geralmente cerca de tr\u00eas vezes maior.\u00a0Este PLC (\u00a0<strong>\u03be = 4,9<\/strong>\u00a0) faz com que a queda de press\u00e3o \u00e9 da ordem de (usando as entradas anteriores)\u00a0<strong>Ap\u00a0<sub>atrito<\/sub><\/strong>\u00a0= 4,9 x 714 x 5\u00a0<sup>2<\/sup>\u00a0\/2 =\u00a0<strong>43,7 kPa<\/strong>\u00a0(sem grelhas de espa\u00e7amento, de topo e bocais inferiores).\u00a0O CLP real cerca de tr\u00eas vezes maior significa que o\u00a0<strong><sub>combust\u00edvel\u00a0<\/sub><\/strong><strong>\u00a0\u0394p<\/strong>\u00a0cerca de tr\u00eas vezes maior\u00a0ser\u00e1.<\/p>\n<p>A perda geral de press\u00e3o do\u00a0<strong><sub>reator<\/sub><\/strong>\u00a0,\u00a0<strong><sub>reator<\/sub><\/strong><strong>\u00a0\u0394p<\/strong>\u00a0, deve incluir:<\/p>\n<ul>\n<li>downcomer e fundo do reator<\/li>\n<li>placa de suporte inferior<\/li>\n<li>conjunto de combust\u00edvel, incluindo grades espa\u00e7adoras, bocais superior e inferior e outros componentes estruturais &#8211;\u00a0\u00a0<strong>\u0394p\u00a0<sub>fuel<\/sub><\/strong><\/li>\n<li>montagem da estrutura da guia superior<\/li>\n<\/ul>\n<p>Como resultado, a perda total de press\u00e3o do reator &#8211;\u00a0\u00a0<strong>\u0394p do\u00a0<sub>reator<\/sub><\/strong>\u00a0\u00e9 geralmente da ordem de centenas de kPa (digamos 300 &#8211; 400 kPa) para par\u00e2metros de projeto.<\/p>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<p>\u00c9 um exemplo ilustrativo, dados anteriores\u00a0\u00a0<strong>n\u00e3o<\/strong>\u00a0\u00a0correspondem a nenhum projeto de reator.<\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Exemplo: perda de press\u00e3o por atrito &#8211; pacote de combust\u00edvel<\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-20407 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel-254x300.png\" alt=\"Di\u00e2metro hidr\u00e1ulico - canal de combust\u00edvel\" width=\"254\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-Fuel-Channel-254x300.png\" \/><\/a>Calcule a\u00a0<a title=\"Perda de Cabe\u00e7a Maior - Perda de Fric\u00e7\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/\"><strong>perda<\/strong><\/a>\u00a0de\u00a0<a title=\"Perda de Cabe\u00e7a Maior - Perda de Fric\u00e7\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/\"><strong>press\u00e3o de atrito<\/strong><\/a>\u00a0de uma\u00a0<strong>\u00fanica barra de combust\u00edvel<\/strong>\u00a0\u00a0dentro de um n\u00facleo do reator em opera\u00e7\u00e3o normal (taxa de fluxo de projeto).\u00a0Suponha que essa barra de combust\u00edvel fa\u00e7a parte de um pacote de combust\u00edvel com a estrutura retangular de combust\u00edvel e esse pacote de combust\u00edvel n\u00e3o contenha grades de espa\u00e7amento.\u00a0Sua altura \u00e9\u00a0<strong>h = 4m<\/strong>\u00a0e a velocidade de fluxo do n\u00facleo \u00e9 constante e igual a\u00a0<strong>V\u00a0<\/strong><strong><sub>core<\/sub><\/strong><strong>\u00a0= 5 m \/ s.<\/strong><\/p>\n<p>Assuma isso:<\/p>\n<ul>\n<li>o di\u00e2metro externo do revestimento \u00e9:\u00a0<strong>d = 2 xr\u00a0<\/strong><strong><sub>Zr, 1<\/sub><\/strong><strong>\u00a0= 9,3 mm<\/strong><\/li>\n<li>o passo dos pinos de combust\u00edvel \u00e9:\u00a0<strong>p = 13 mm<\/strong><\/li>\n<li>a\u00a0<a title=\"Rugosidade relativa do tubo\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/relative-roughness-of-pipe\/\">rugosidade relativa<\/a>\u00a0\u00e9\u00a0<strong>\u03b5 \/ D = 5 \u00d7 10\u00a0<\/strong><strong><sup>-4<\/sup><\/strong><\/li>\n<li>a\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-density-physics\/\">densidade<\/a>\u00a0do fluido\u00a0\u00e9:\u00a0<strong>\u03c1 = 714 kg \/ m\u00a0<\/strong><strong><sup>3<\/sup><\/strong><\/li>\n<li>a velocidade de fluxo do n\u00facleo \u00e9 constante e igual a\u00a0<strong>V\u00a0<\/strong><strong><sub>core<\/sub><\/strong><strong>\u00a0= 5 m \/ s<\/strong><\/li>\n<li>a\u00a0<a title=\"O que \u00e9 temperatura - F\u00edsica\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-temperatura-fisica-definicao\/\">temperatura<\/a>\u00a0m\u00e9dia\u00a0do l\u00edquido de refrigera\u00e7\u00e3o do reator \u00e9:\u00a0<strong>T a\u00a0<\/strong><strong><sub>granel<\/sub><\/strong><strong>\u00a0= 296 \u00b0 C<\/strong><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>C\u00e1lculo do n\u00famero de Reynolds<\/h2>\n<p>Para calcular o\u00a0<a title=\"N\u00famero de Reynolds\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/reynolds-number\/\">n\u00famero de Reynolds<\/a>\u00a0, precisamos saber:<\/p>\n<ul>\n<li>o di\u00e2metro externo do revestimento \u00e9:\u00a0<strong>d = 2 xr\u00a0<\/strong><strong><sub>Zr, 1<\/sub><\/strong><strong>\u00a0= 9,3 mm<\/strong>\u00a0(para calcular o di\u00e2metro hidr\u00e1ulico)<\/li>\n<li>o passo dos pinos de combust\u00edvel \u00e9:\u00a0<strong>p = 13 mm<\/strong>\u00a0\u00a0(para calcular o di\u00e2metro hidr\u00e1ulico)<\/li>\n<li>a viscosidade din\u00e2mica da \u00e1gua saturada a 300 \u00b0 C \u00e9:\u00a0<strong>\u03bc = 0,0000859 Ns \/ m\u00a0<\/strong><strong><sup>2<\/sup><\/strong><\/li>\n<li>a densidade do fluido \u00e9:\u00a0<strong>\u03c1 = 714 kg \/ m\u00a0<\/strong><strong><sup>3<\/sup><\/strong><\/li>\n<\/ul>\n<p><strong>O di\u00e2metro hidr\u00e1ulico, D\u00a0<\/strong><strong><sub>h<\/sub><\/strong>\u00a0, \u00e9 um termo comumente usado ao manipular o fluxo em\u00a0<strong>tubos e canais n\u00e3o circulares<\/strong>\u00a0.\u00a0O\u00a0<strong>di\u00e2metro hidr\u00e1ulico do canal de combust\u00edvel<\/strong>\u00a0,\u00a0<em>D\u00a0<\/em><em><sub>h<\/sub><\/em>\u00a0, \u00e9 igual a\u00a0<strong>13,85 mm<\/strong>\u00a0.<\/p>\n<p>Veja tamb\u00e9m:\u00a0<a href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/internal-flow\/hydraulic-diameter-2\/\">Di\u00e2metro hidr\u00e1ulico<\/a><\/p>\n<p>O\u00a0<strong>n\u00famero de Reynolds<\/strong>\u00a0dentro do canal de combust\u00edvel \u00e9 ent\u00e3o igual a:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20412 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\" alt=\"n\u00famero de reynolds - exemplo\" width=\"593\" height=\"78\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/reynolds-number-example.png\" \/><\/a><\/p>\n<p>Isso satisfaz plenamente as\u00a0<a href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-fluxo-turbulento-definicao\/\"><strong>condi\u00e7\u00f5es turbulentas<\/strong><\/a>\u00a0.<\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>C\u00e1lculo do fator de atrito de Darcy<\/h2>\n<p><strong>O fator de atrito<\/strong>\u00a0para escoamento turbulento depende fortemente da\u00a0<strong>rugosidade relativa.\u00a0<\/strong>\u00c9 determinado pela equa\u00e7\u00e3o de Colebrook ou pode ser determinado usando o\u00a0<a title=\"Moody Diagram\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/moody-diagram\/\"><strong>gr\u00e1fico Moody<\/strong><\/a>\u00a0.\u00a0O\u00a0<strong>gr\u00e1fico Moody<\/strong>\u00a0para\u00a0<strong>Re = 575 600<\/strong>\u00a0e\u00a0<strong>\u03b5 \/ D = 5 x 10\u00a0<\/strong><strong><sup>-4<\/sup><\/strong>\u00a0retorna os seguintes valores:<\/p>\n<ul>\n<li>o\u00a0<a title=\"Fator de atrito de Darcy\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-o-fator-de-atrito-de-darcy-definicao\/\"><strong>fator de atrito de Darcy<\/strong><\/a>\u00a0\u00e9 igual a\u00a0<strong>f\u00a0<\/strong><strong><sub>D<\/sub><\/strong><strong>\u00a0= 0,017<\/strong><\/li>\n<li>o\u00a0<a title=\"Fator de Fric\u00e7\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/fluid-dynamics\/major-head-loss-friction-loss\/fanning-friction-factor\/\"><strong>fator de atrito de Fanning<\/strong><\/a>\u00a0\u00e9 igual a\u00a0<strong>f\u00a0<\/strong><strong><sub>F<\/sub><\/strong><strong>\u00a0= f\u00a0<\/strong><strong><sub>D<\/sub><\/strong><strong>\u00a0\/ 4 = 0,00425<\/strong><\/li>\n<\/ul>\n<p>Portanto, o\u00a0\u00a0<strong>coeficiente de perda de press\u00e3o<\/strong>\u00a0\u00a0(somente friccional do tubo reto) \u00e9 igual a\u00a0\u00a0<strong>\u03be = f\u00a0<sub>D<\/sub>\u00a0L \/ D\u00a0<sub>H<\/sub>\u00a0\u00a0= 4.9<\/strong>\u00a0.<\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\"><\/div>\n<\/div>\n<\/div>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Este artigo \u00e9 baseado na tradu\u00e7\u00e3o autom\u00e1tica do artigo original em ingl\u00eas. Para mais informa\u00e7\u00f5es, consulte o artigo em ingl\u00eas. Voc\u00ea pode nos ajudar. Se voc\u00ea deseja corrigir a tradu\u00e7\u00e3o, envie-a para: translations@nuclear-power.com ou preencha o formul\u00e1rio de tradu\u00e7\u00e3o on-line. Agradecemos sua ajuda, atualizaremos a tradu\u00e7\u00e3o o mais r\u00e1pido poss\u00edvel. Obrigado.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Queda de press\u00e3o &#8211; conjunto de combust\u00edvel.\u00a0Em geral, a queda de press\u00e3o total do conjunto de combust\u00edvel \u00e9 formada pela queda de atrito do pacote de combust\u00edvel e outras quedas de press\u00e3o dos elementos estruturais Queda de press\u00e3o &#8211; Montagem de combust\u00edvel Em geral,\u00a0a\u00a0queda de press\u00e3o\u00a0total\u00a0do conjunto de combust\u00edvel\u00a0\u00e9 formada pela queda de atrito do &#8230; <a title=\"O que \u00e9 queda de press\u00e3o &#8211; Conjunto de combust\u00edvel &#8211; Defini\u00e7\u00e3o\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao\/\" aria-label=\"More on O que \u00e9 queda de press\u00e3o &#8211; Conjunto de combust\u00edvel &#8211; Defini\u00e7\u00e3o\">Ler mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[14],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>O que \u00e9 queda de press\u00e3o - Conjunto de combust\u00edvel - Defini\u00e7\u00e3o<\/title>\n<meta name=\"description\" content=\"Queda de press\u00e3o - conjunto de combust\u00edvel. 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Em geral, a queda de press\u00e3o total do conjunto de combust\u00edvel \u00e9 formada pela queda de atrito do pacote de combust\u00edvel e outras quedas de press\u00e3o dos elementos estruturais\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao\/\" \/>\n<meta property=\"og:site_name\" content=\"Thermal Engineering\" \/>\n<meta property=\"article:published_time\" content=\"2019-11-04T04:25:15+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2020-03-05T05:57:09+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/PLC-Pressure-loss-coefficient-equations.png\" \/>\n<meta name=\"twitter:card\" content=\"summary\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\">\n\t<meta name=\"twitter:data1\" content=\"Nick Connor\">\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\">\n\t<meta name=\"twitter:data2\" content=\"4 minutos\">\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebSite\",\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#website\",\"url\":\"https:\/\/www.thermal-engineering.org\/fr\/\",\"name\":\"Thermal Engineering\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":\"https:\/\/www.thermal-engineering.org\/fr\/?s={search_term_string}\",\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"pt-BR\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao\/#primaryimage\",\"inLanguage\":\"pt-BR\",\"url\":\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/PLC-Pressure-loss-coefficient-equations.png\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao\/#webpage\",\"url\":\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao\/\",\"name\":\"O que \\u00e9 queda de press\\u00e3o - Conjunto de combust\\u00edvel - Defini\\u00e7\\u00e3o\",\"isPartOf\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-queda-de-pressao-conjunto-de-combustivel-definicao\/#primaryimage\"},\"datePublished\":\"2019-11-04T04:25:15+00:00\",\"dateModified\":\"2020-03-05T05:57:09+00:00\",\"author\":{\"@id\":\"https:\/\/www.thermal-engineering.org\/fr\/#\/schema\/person\/e8c544db9afedaec8574d6464f9398bb\"},\"description\":\"Queda de press\\u00e3o - conjunto de combust\\u00edvel. 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