{"id":47639,"date":"2019-11-05T18:57:33","date_gmt":"2019-11-05T17:57:33","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/o-que-e-a-distribuicao-de-temperatura-no-revestimento-de-combustivel-definicao\/"},"modified":"2020-03-05T12:45:47","modified_gmt":"2020-03-05T11:45:47","slug":"o-que-e-a-distribuicao-de-temperatura-no-revestimento-de-combustivel-definicao","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-a-distribuicao-de-temperatura-no-revestimento-de-combustivel-definicao\/","title":{"rendered":"O que \u00e9 a distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel &#8211; Defini\u00e7\u00e3o"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel.\u00a0O revestimento \u00e9 a camada externa das barras de combust\u00edvel, situada entre o l\u00edquido de arrefecimento do reator e o combust\u00edvel nuclear (ou seja, pellets de combust\u00edvel)<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel<\/h2>\n<p><strong>O<\/strong>\u00a0revestimento \u00e9 a camada externa das barras de combust\u00edvel, situada entre o\u00a0<strong>l\u00edquido de arrefecimento<\/strong>\u00a0do\u00a0<strong>reator<\/strong>\u00a0e o\u00a0<strong>combust\u00edvel nuclear<\/strong>\u00a0(isto \u00e9,\u00a0<strong>granulados de combust\u00edvel<\/strong>\u00a0).\u00a0\u00c9 feito de um material resistente \u00e0 corros\u00e3o com se\u00e7\u00e3o transversal de baixa absor\u00e7\u00e3o para n\u00eautrons t\u00e9rmicos, geralmente\u00a0<strong>liga de zirc\u00f4nio<\/strong>\u00a0.\u00a0<strong>O revestimento<\/strong>\u00a0evita que os produtos de fiss\u00e3o radioativa escapem da matriz de combust\u00edvel para o l\u00edquido de arrefecimento do reator e os contaminem.\u00a0O revestimento constitui uma das barreiras na\u00a0abordagem de\u00a0&#8216;\u00a0<strong>defesa em profundidade<\/strong>\u00a0&#8216;.<\/p>\n<p>Considere o revestimento de combust\u00edvel do raio interno\u00a0<strong>r\u00a0<sub>Zr, 2<\/sub>\u00a0= 0,408 cm<\/strong>\u00a0e raio externo\u00a0<strong>r\u00a0<sub>Zr, 1<\/sub>\u00a0= 0,465 cm<\/strong>\u00a0.\u00a0Em compara\u00e7\u00e3o com o pellet de combust\u00edvel, quase n\u00e3o h\u00e1 gera\u00e7\u00e3o de calor no revestimento do combust\u00edvel (o revestimento \u00e9\u00a0<a title=\"Libera\u00e7\u00e3o de energia da fiss\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power\/fission\/energy-release-from-fission\/\">levemente aquecido pela radia\u00e7\u00e3o<\/a>\u00a0).\u00a0Todo o calor gerado no combust\u00edvel deve ser transferido por\u00a0<strong>condu\u00e7\u00e3o<\/strong>\u00a0atrav\u00e9s do revestimento e, portanto, a superf\u00edcie interna \u00e9 mais quente que a superf\u00edcie externa.<\/p>\n<p>Para encontrar a distribui\u00e7\u00e3o de temperatura atrav\u00e9s do revestimento, precisamos resolver a\u00a0<strong>equa\u00e7\u00e3o de condu\u00e7\u00e3o de calor<\/strong>\u00a0.\u00a0Devido \u00e0 simetria na dire\u00e7\u00e3o z e na dire\u00e7\u00e3o azimutal, podemos separar as vari\u00e1veis \u200b\u200be simplificar esse problema para um problema unidimensional.\u00a0Assim, resolveremos apenas a temperatura em fun\u00e7\u00e3o do raio T (r).\u00a0Neste exemplo, assumiremos que n\u00e3o existe estritamente gera\u00e7\u00e3o de calor no revestimento.\u00a0Para condutividade t\u00e9rmica constante, k, a forma apropriada da equa\u00e7\u00e3o de calor cil\u00edndrica \u00e9:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20241 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding.png\" alt=\"equa\u00e7\u00e3o do calor - revestimento\" width=\"190\" height=\"72\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding.png\" \/><\/a><\/p>\n<p>A solu\u00e7\u00e3o geral desta equa\u00e7\u00e3o \u00e9:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding-general-solution.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20242 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding-general-solution.png\" alt=\"equa\u00e7\u00e3o do calor - revestimento - solu\u00e7\u00e3o geral\" width=\"245\" height=\"133\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding-general-solution.png\" \/><\/a><\/p>\n<p>onde C\u00a0<sub>1<\/sub>\u00a0e C\u00a0<sub>2<\/sub>\u00a0s\u00e3o as constantes de integra\u00e7\u00e3o.<\/p>\n<p>1)<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Thermal-conduction-fuel-pellet.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-20223 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Thermal-conduction-fuel-pellet-244x300.png\" alt=\"Condu\u00e7\u00e3o t\u00e9rmica - pellet de combust\u00edvel\" width=\"244\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Thermal-conduction-fuel-pellet-244x300.png\" \/><\/a>Calcule a distribui\u00e7\u00e3o de temperatura, T (r), neste revestimento de combust\u00edvel, se:<\/p>\n<ul>\n<li>a temperatura na superf\u00edcie interna do revestimento \u00e9 T\u00a0<sub>Zr, 2<\/sub>\u00a0= 360 \u00b0 C<\/li>\n<li>a temperatura do l\u00edquido de arrefecimento do reator nesta coordenada axial \u00e9 T a\u00a0<sub>granel<\/sub>\u00a0= 300 \u00b0 C<\/li>\n<li>o coeficiente de transfer\u00eancia de calor (convec\u00e7\u00e3o; fluxo turbulento) \u00e9 h = 41 kW \/ m\u00a0<sup>2<\/sup>\u00a0.K.<\/li>\n<li>a condutividade m\u00e9dia do material \u00e9 k = 18 W \/ mK<\/li>\n<li>a taxa linear de calor do combust\u00edvel \u00e9 q\u00a0<sub>L<\/sub>\u00a0= 300 W \/ cm e, portanto, a taxa volum\u00e9trica de calor \u00e9 q\u00a0<sub>V<\/sub>\u00a0= 597 x 10\u00a0<sup>6<\/sup>\u00a0W \/ m\u00a0<sup>3<\/sup><\/li>\n<\/ul>\n<p>A partir da rela\u00e7\u00e3o b\u00e1sica para transfer\u00eancia de calor por convec\u00e7\u00e3o, podemos calcular a superf\u00edcie externa do revestimento como:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/newtons-law-cladding.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20269 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/newtons-law-cladding.png\" alt=\"newtons law - revestimento\" width=\"423\" height=\"299\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/newtons-law-cladding.png\" \/><\/a><\/p>\n<p>Como pode ser visto, tamb\u00e9m neste caso, fornecemos temperaturas de superf\u00edcie T\u00a0<sub>Zr, 1<\/sub>\u00a0e T\u00a0<sub>Zr, 2<\/sub>\u00a0.\u00a0Isso corresponde \u00e0 condi\u00e7\u00e3o de limite de Dirichlet.\u00a0As constantes podem ser avaliadas usando a substitui\u00e7\u00e3o na solu\u00e7\u00e3o geral e t\u00eam a forma:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-general-solution-cladding.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20264 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-general-solution-cladding.png\" alt=\"equa\u00e7\u00e3o do calor - solu\u00e7\u00e3o geral - revestimento\" width=\"352\" height=\"53\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-general-solution-cladding.png\" \/><\/a><\/p>\n<p>Resolvendo C\u00a0<sub>1<\/sub>\u00a0e C\u00a0<sub>2<\/sub>\u00a0e substituindo na solu\u00e7\u00e3o geral, obtemos ent\u00e3o:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding-solution.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20265 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding-solution.png\" alt=\"equa\u00e7\u00e3o do calor - revestimento - solu\u00e7\u00e3o\" width=\"381\" height=\"84\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/heat-equation-cladding-solution.png\" \/><\/a><\/p>\n<p><strong>\u2206T &#8211; superf\u00edcie de revestimento &#8211; refrigerante<\/strong><\/p>\n<p>O conhecimento detalhado da geometria, raio externo do revestimento, taxa de calor linear, coeficiente de transfer\u00eancia de calor por convec\u00e7\u00e3o e temperatura do l\u00edquido de refrigera\u00e7\u00e3o determina\u00a0<strong>\u2206T<\/strong>\u00a0entre o l\u00edquido de arrefecimento (T a\u00a0<sub>granel<\/sub>\u00a0) e a superf\u00edcie do revestimento (T\u00a0<sub>Zr, 1<\/sub>\u00a0).\u00a0Portanto, podemos calcular a temperatura da superf\u00edcie do revestimento (T\u00a0<sub>Zr, 1<\/sub>\u00a0) simplesmente usando a\u00a0<strong>Lei de Newton<\/strong>\u00a0:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/%E2%88%86T-cladding-surface-coolant-newtons-law.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20266 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/%E2%88%86T-cladding-surface-coolant-newtons-law.png\" alt=\"\u2206T - superf\u00edcie de revestimento - refrigerante - newtons law\" width=\"425\" height=\"306\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/\u2206T-cladding-surface-coolant-newtons-law.png\" \/><\/a><\/p>\n<p><strong>\u2206T no revestimento do combust\u00edvel<\/strong><\/p>\n<p>O conhecimento detalhado da geometria, raio externo e interno do revestimento, taxa de calor linear e temperatura da superf\u00edcie do revestimento (T\u00a0<sub>Zr, 1<\/sub>\u00a0) determina\u00a0<strong>\u2206T<\/strong>\u00a0entre as superf\u00edcies externa e interna do revestimento.\u00a0Portanto, podemos calcular a temperatura da superf\u00edcie interna do revestimento (T\u00a0<sub>Zr, 2<\/sub>\u00a0) simplesmente usando a\u00a0<strong>Lei de Fourier<\/strong>\u00a0:<\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/%E2%88%86T-in-fuel-cladding-fouriers-law.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-20267 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/%E2%88%86T-in-fuel-cladding-fouriers-law.png\" alt=\"\u2206T no revestimento de combust\u00edvel - lei de fouriers\" width=\"370\" height=\"460\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/\u2206T-in-fuel-cladding-fouriers-law.png\" \/><\/a><\/p>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Este artigo \u00e9 baseado na tradu\u00e7\u00e3o autom\u00e1tica do artigo original em ingl\u00eas. Para mais informa\u00e7\u00f5es, consulte o artigo em ingl\u00eas. Voc\u00ea pode nos ajudar. Se voc\u00ea deseja corrigir a tradu\u00e7\u00e3o, envie-a para: translations@nuclear-power.com ou preencha o formul\u00e1rio de tradu\u00e7\u00e3o on-line. Agradecemos sua ajuda, atualizaremos a tradu\u00e7\u00e3o o mais r\u00e1pido poss\u00edvel. Obrigado.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel.\u00a0O revestimento \u00e9 a camada externa das barras de combust\u00edvel, situada entre o l\u00edquido de arrefecimento do reator e o combust\u00edvel nuclear (ou seja, pellets de combust\u00edvel) Distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel O\u00a0revestimento \u00e9 a camada externa das barras de combust\u00edvel, situada entre o\u00a0l\u00edquido de arrefecimento\u00a0do\u00a0reator\u00a0e o\u00a0combust\u00edvel &#8230; <a title=\"O que \u00e9 a distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel &#8211; Defini\u00e7\u00e3o\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-a-distribuicao-de-temperatura-no-revestimento-de-combustivel-definicao\/\" aria-label=\"More on O que \u00e9 a distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel &#8211; Defini\u00e7\u00e3o\">Ler mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[14],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>O que \u00e9 a distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel - Defini\u00e7\u00e3o<\/title>\n<meta name=\"description\" content=\"Distribui\u00e7\u00e3o de temperatura no revestimento de combust\u00edvel. 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