{"id":48091,"date":"2019-11-08T02:53:52","date_gmt":"2019-11-08T01:53:52","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/exemplo-de-limitacao-e-processo-isentalpico-definicao\/"},"modified":"2020-01-27T14:03:59","modified_gmt":"2020-01-27T13:03:59","slug":"exemplo-de-limitacao-e-processo-isentalpico-definicao","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/pt-br\/exemplo-de-limitacao-e-processo-isentalpico-definicao\/","title":{"rendered":"Exemplo de limita\u00e7\u00e3o e processo isent\u00e1lpico – Defini\u00e7\u00e3o"},"content":{"rendered":"
\n
Exemplo de limita\u00e7\u00e3o e processo isent\u00e1lpico. Determine a qualidade do vapor quando regulado entre 1,15 MPa e 1,0 MPa. Engenharia T\u00e9rmica<\/div>\n<\/div>\n
<\/div>\n
\n

Processo de estrangulamento – processo isent\u00e1lpico<\/span><\/h2>\n

Um\u00a0<\/span>processo de estrangulamento<\/span><\/strong>\u00a0\u00e9 um\u00a0<\/span>processo termodin\u00e2mico<\/span><\/strong><\/a>\u00a0, no qual a\u00a0<\/span>entalpia<\/span><\/strong><\/a>\u00a0do g\u00e1s ou do meio\u00a0<\/span>permanece constante (h = const)<\/span><\/strong>\u00a0.\u00a0De fato, o\u00a0<\/span>processo de estrangulamento<\/span><\/strong>\u00a0\u00e9 um dos\u00a0<\/span>processos isent\u00e1licos<\/span><\/strong>\u00a0.\u00a0Durante o processo de estrangulamento,\u00a0<\/span>nenhum trabalho<\/span><\/strong>\u00a0\u00e9 realizado pelo sistema (dW = 0) e, geralmente, n\u00e3o\u00a0<\/span>h\u00e1 transfer\u00eancia de calor<\/span><\/strong>\u00a0(\u00a0<\/span>adiab\u00e1tica<\/span><\/strong>\u00a0) do ou para o sistema (dQ = 0).\u00a0Por outro lado, o processo de estrangulamento n\u00e3o pode ser isentr\u00f3pico, \u00e9 um\u00a0<\/span>processo fundamentalmente irrevers\u00edvel<\/span><\/strong><\/a>\u00a0.\u00a0Caracter\u00edsticas do processo de estrangulamento:<\/span><\/p>\n

    \n
  1. Transfer\u00eancia sem trabalho<\/span><\/li>\n
  2. Sem transfer\u00eancia de calor<\/span><\/li>\n
  3. Processo irrevers\u00edvel<\/span><\/li>\n
  4. Processo isent\u00e1lpico<\/span><\/li>\n<\/ol>\n<\/div>\n

     <\/p>\n

    \"Uma<\/a><\/p>\n

    Uma v\u00e1lvula parcialmente aberta ou um buj\u00e3o poroso pode ser usado para reduzir a press\u00e3o em um sistema.<\/span><\/p>\n

    <\/div>\n
    \n

    Exemplo: Regulagem de vapor \u00famido<\/span><\/h2>\n

    Um est\u00e1gio de alta press\u00e3o da turbina a vapor opera em estado estacion\u00e1rio com condi\u00e7\u00f5es de entrada de 6 MPa, t = 275,6 \u00b0 C, x = 1 (ponto C).\u00a0O vapor sai deste est\u00e1gio da turbina a uma press\u00e3o de 1,15 MPa, 186 \u00b0 C ex = 0,87 (ponto D).\u00a0Determine a qualidade do vapor quando regulado entre 1,15 MPa e 1,0 MPa.\u00a0Suponha que o processo seja adiab\u00e1tico e que nenhum trabalho seja realizado pelo sistema.<\/span><\/p>\n

    Veja tamb\u00e9m:\u00a0<\/span>Tabelas Steam<\/span><\/a><\/p>\n

    Solu\u00e7\u00e3o:<\/span><\/strong><\/p>\n

    A entalpia para o estado D deve ser calculada usando a qualidade do vapor:<\/span><\/p>\n

    h\u00a0<\/span><\/em><\/strong>D, \u00famido<\/span><\/sub><\/em><\/strong>\u00a0= h\u00a0<\/span><\/em><\/strong>D, vapor<\/span><\/sub><\/em><\/strong>\u00a0x + (1 – x) h\u00a0<\/span><\/em><\/strong>D, l\u00edquido<\/span><\/sub><\/em><\/strong>\u00a0\u00a0= 2782.\u00a00,87 + (1 – 0,87).\u00a0790 = 2420 + 103 =<\/span>\u00a02523 kJ \/ kg<\/span><\/strong><\/p>\n

    Como \u00e9 um processo isent\u00e1lico, conhecemos a entalpia do ponto T. Nas tabelas de vapor, temos que encontrar a qualidade do vapor usando a mesma equa\u00e7\u00e3o e resolvendo a equa\u00e7\u00e3o para a qualidade do vapor, x:<\/span><\/p>\n

    h\u00a0<\/span><\/em><\/strong>T, \u00famido<\/span><\/sub><\/em><\/strong>\u00a0= h\u00a0<\/span><\/em><\/strong>T, vapor<\/span><\/sub><\/em><\/strong>\u00a0x + (1 – x) h\u00a0<\/span><\/em><\/strong>T, l\u00edquido<\/span><\/sub><\/em><\/strong><\/p>\n

    x = (\u00a0<\/span>h\u00a0<\/span><\/em><\/strong>T, \u00famido<\/span><\/sub><\/em><\/strong>\u00a0– h\u00a0<\/span><\/em><\/strong>T, l\u00edquido<\/span><\/sub><\/em><\/strong>\u00a0) \/ (\u00a0<\/span>h\u00a0<\/span><\/em><\/strong>T, vapor<\/span><\/sub><\/em><\/strong>\u00a0– h\u00a0<\/span><\/em><\/strong>T, l\u00edquido<\/span><\/sub><\/em><\/strong>\u00a0) = (2523 – 762) \/ (2777 – 762) = 0,874 = 87,4%<\/span><\/p>\n

    \"processo<\/a><\/p>\n

    Neste caso do processo de estrangulamento (1,15 MPa a 1MPa), a qualidade do vapor aumenta de 87% para 87,4% e a temperatura diminui de 186 \u00b0 C para 179,9 \u00b0 C.<\/span><\/p>\n<\/div>\n

    \"Regulagem<\/a><\/p>\n

    A limita\u00e7\u00e3o do vapor \u00famido geralmente causa aumento na qualidade do vapor, aumento da entropia e diminui\u00e7\u00e3o da temperatura.<\/span><\/p>\n

    ……………………………………………………………………………………………………………………………….<\/p>\n

    Este artigo \u00e9 baseado na tradu\u00e7\u00e3o autom\u00e1tica do artigo original em ingl\u00eas. Para mais informa\u00e7\u00f5es, consulte o artigo em ingl\u00eas. Voc\u00ea pode nos ajudar. Se voc\u00ea deseja corrigir a tradu\u00e7\u00e3o, envie-a para: translations@nuclear-power.com ou preencha o formul\u00e1rio de tradu\u00e7\u00e3o on-line. Agradecemos sua ajuda, atualizaremos a tradu\u00e7\u00e3o o mais r\u00e1pido poss\u00edvel. Obrigado.<\/p>\n","protected":false},"excerpt":{"rendered":"

    Exemplo de limita\u00e7\u00e3o e processo isent\u00e1lpico. Determine a qualidade do vapor quando regulado entre 1,15 MPa e 1,0 MPa. Engenharia T\u00e9rmica Processo de estrangulamento – processo isent\u00e1lpico Um\u00a0processo de estrangulamento\u00a0\u00e9 um\u00a0processo termodin\u00e2mico\u00a0, no qual a\u00a0entalpia\u00a0do g\u00e1s ou do meio\u00a0permanece constante (h = const)\u00a0.\u00a0De fato, o\u00a0processo de estrangulamento\u00a0\u00e9 um dos\u00a0processos isent\u00e1licos\u00a0.\u00a0Durante o processo de estrangulamento,\u00a0nenhum trabalho\u00a0\u00e9 … Ler mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[14],"tags":[],"yoast_head":"\nExemplo de limita\u00e7\u00e3o e processo isent\u00e1lpico - Defini\u00e7\u00e3o<\/title>\n<meta name=\"description\" content=\"Exemplo de limita\u00e7\u00e3o e processo isent\u00e1lpico. Determine a qualidade do vapor quando regulado entre 1,15 MPa e 1,0 MPa. 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