{"id":48457,"date":"2019-11-10T19:04:00","date_gmt":"2019-11-10T18:04:00","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/o-que-e-a-energia-cinetica-de-proton-definicao\/"},"modified":"2020-01-29T13:09:56","modified_gmt":"2020-01-29T12:09:56","slug":"o-que-e-a-energia-cinetica-de-proton-definicao","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-a-energia-cinetica-de-proton-definicao\/","title":{"rendered":"O que \u00e9 a energia cin\u00e9tica de Proton – Defini\u00e7\u00e3o"},"content":{"rendered":"
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De acordo com a rela\u00e7\u00e3o relativ\u00edstica, a acelera\u00e7\u00e3o de um feixe de pr\u00f3tons para 5,7 GeV requer energias que est\u00e3o na ordem diferente.\u00a0Engenharia T\u00e9rmica<\/div>\n<\/div>\n
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Exemplo: energia cin\u00e9tica de Proton<\/h2>\n

\"O<\/a>Um pr\u00f3ton (\u00a0m = 1,67 x\u00a010-27<\/sup>\u00a0kg<\/strong>\u00a0) viaja a uma velocidade\u00a0v = 0,9900c = 2,968 x 10\u00a08<\/sup>\u00a0m \/ s<\/strong>\u00a0.\u00a0Qual \u00e9 a sua\u00a0energia cin\u00e9tica<\/strong>\u00a0?<\/p>\n

De acordo com um c\u00e1lculo cl\u00e1ssico, que n\u00e3o est\u00e1 correto, obter\u00edamos:<\/p>\n

K = 1 \/ 2mv\u00a02<\/sup>\u00a0= \u00bd x (1,67 x\u00a010-27<\/sup>\u00a0kg) x (2,968 x 10\u00a08<\/sup>\u00a0m \/ s)\u00a02<\/sup>\u00a0=\u00a07,355 x 10\u00a0-11<\/sup>\u00a0J<\/strong><\/p>\n

Com a corre\u00e7\u00e3o\u00a0relativ\u00edstica, a energia cin\u00e9tica relativ\u00edstica<\/strong>\u00a0\u00e9 igual a:<\/p>\n

K = (\u0263 – 1) mc\u00a02<\/sup><\/strong><\/p>\n

onde o fator de Lorentz<\/p>\n

\u0263 = 7.089<\/p>\n

Portanto<\/p>\n

K = 6,089 x (1,67 x 10\u00a0-27<\/sup>\u00a0kg) x (2,9979 x 10\u00a08<\/sup>\u00a0m \/ s)\u00a02<\/sup>\u00a0=\u00a09,139 x\u00a010-10<\/sup>\u00a0J = 5,701 GeV<\/strong><\/p>\n

Isso \u00e9 cerca de\u00a012 vezes mais<\/strong>\u00a0energia do que no c\u00e1lculo cl\u00e1ssico.\u00a0De acordo com essa rela\u00e7\u00e3o, a acelera\u00e7\u00e3o de um feixe de pr\u00f3tons para 5,7 GeV requer energias da ordem diferente.<\/p>\n<\/div>\n<\/div>\n

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……………………………………………………………………………………………………………………………….<\/p>\n

Este artigo \u00e9 baseado na tradu\u00e7\u00e3o autom\u00e1tica do artigo original em ingl\u00eas. Para mais informa\u00e7\u00f5es, consulte o artigo em ingl\u00eas. Voc\u00ea pode nos ajudar. Se voc\u00ea deseja corrigir a tradu\u00e7\u00e3o, envie-a para: translations@nuclear-power.com ou preencha o formul\u00e1rio de tradu\u00e7\u00e3o on-line. Agradecemos sua ajuda, atualizaremos a tradu\u00e7\u00e3o o mais r\u00e1pido poss\u00edvel. Obrigado.<\/p>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

De acordo com a rela\u00e7\u00e3o relativ\u00edstica, a acelera\u00e7\u00e3o de um feixe de pr\u00f3tons para 5,7 GeV requer energias que est\u00e3o na ordem diferente.\u00a0Engenharia T\u00e9rmica Exemplo: energia cin\u00e9tica de Proton Um pr\u00f3ton (\u00a0m = 1,67 x\u00a010-27\u00a0kg\u00a0) viaja a uma velocidade\u00a0v = 0,9900c = 2,968 x 10\u00a08\u00a0m \/ s\u00a0.\u00a0Qual \u00e9 a sua\u00a0energia cin\u00e9tica\u00a0? De acordo com um … Ler mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[14],"tags":[],"yoast_head":"\nO que \u00e9 a energia cin\u00e9tica de Proton - Defini\u00e7\u00e3o<\/title>\n<meta name=\"description\" content=\"De acordo com a rela\u00e7\u00e3o relativ\u00edstica, a acelera\u00e7\u00e3o de um feixe de pr\u00f3tons para 5,7 GeV requer energias que est\u00e3o na ordem diferente. 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