{"id":48721,"date":"2019-11-11T23:54:21","date_gmt":"2019-11-11T22:54:21","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/libra-por-polegada-quadrada-psi-definicao\/"},"modified":"2020-01-30T10:30:17","modified_gmt":"2020-01-30T09:30:17","slug":"libra-por-polegada-quadrada-psi-definicao","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/pt-br\/libra-por-polegada-quadrada-psi-definicao\/","title":{"rendered":"Libra por polegada quadrada &#8211; psi &#8211; Defini\u00e7\u00e3o"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Libras por polegada quadrada &#8211; psi &#8211; psig &#8211; psia. A unidade padr\u00e3o no sistema ingl\u00eas \u00e9 a for\u00e7a da libra por polegada quadrada (psi). 1 psi \u00e9 aproximadamente 6895 Pa. Engenharia T\u00e9rmica<\/div>\n<\/div>\n<div><\/div>\n<div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<h2><span>O que \u00e9 press\u00e3o<\/span><\/h2>\n<p><strong><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Manometer-Pressure-Measurement.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-16368 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Manometer-Pressure-Measurement-235x300.png\" alt=\"man\u00f4metro-press\u00e3o-medida\" width=\"235\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Manometer-Pressure-Measurement-235x300.png\" \/><\/a><span>Press\u00e3o<\/span><\/strong><span>\u00a0\u00e9 uma medida da\u00a0<\/span><strong><span>for\u00e7a exercida<\/span><\/strong><span>\u00a0por unidade de \u00e1rea nos limites de uma subst\u00e2ncia.\u00a0A unidade padr\u00e3o de\u00a0<\/span><strong><span>press\u00e3o<\/span><\/strong><span>\u00a0no sistema SI \u00e9 o\u00a0<\/span><strong><span>Newton por metro quadrado ou pascal (Pa)<\/span><\/strong><span>\u00a0.\u00a0Matematicamente:<\/span><\/p>\n<p><strong><span>p = F \/ A<\/span><\/strong><\/p>\n<p><span>Onde<\/span><\/p>\n<ul>\n<li><strong><span>p \u00e9 a press\u00e3o<\/span><\/strong><\/li>\n<li><strong><span>F \u00e9 a for\u00e7a normal<\/span><\/strong><\/li>\n<li><strong><span>A \u00e9 a \u00e1rea do limite<\/span><\/strong><\/li>\n<\/ul>\n<p><span>Pascal \u00e9 definido como a for\u00e7a de 1N exercida na \u00e1rea da unidade.<\/span><\/p>\n<ul>\n<li><strong><span>1 Pascal = 1 N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-60 lgc-tablet-grid-60 lgc-mobile-grid-100 lgc-equal-heights  lgc-first\">\n<div class=\"inside-grid-column\"><span>No entanto, para a maioria dos problemas de engenharia, \u00e9 uma unidade relativamente pequena, portanto, \u00e9 conveniente trabalhar com m\u00faltiplos do pascal: o\u00a0<\/span><strong><span>kPa<\/span><\/strong><span>\u00a0, a\u00a0<\/span><strong><span>barra<\/span><\/strong><span>\u00a0e o\u00a0<\/span><strong><span>MPa<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<ul>\n<li><strong><span>1 MPa 10\u00a0<\/span><sup><span>6<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><strong><span>1 bar 10\u00a0<\/span><sup><span>5<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<li><strong><span>1 kPa 10\u00a0<\/span><sup><span>3<\/span><\/sup><span>\u00a0N \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<\/ul>\n<p><span>Em geral, a press\u00e3o ou a for\u00e7a exercida por unidade de \u00e1rea nos limites de uma subst\u00e2ncia \u00e9 causada pelas\u00a0<\/span><strong><span>colis\u00f5es<\/span><\/strong><span>\u00a0das\u00a0<\/span><strong><span>mol\u00e9culas<\/span><\/strong><span>\u00a0da subst\u00e2ncia com os limites do sistema.\u00a0Quando as mol\u00e9culas atingem as paredes, elas exercem for\u00e7as que tentam empurrar as paredes para fora.\u00a0As for\u00e7as resultantes de todas essas colis\u00f5es causam a\u00a0<\/span><strong><span>press\u00e3o<\/span><\/strong><span>\u00a0exercida por um sistema em seu entorno.\u00a0A press\u00e3o como\u00a0<\/span><a title=\"Propriedades extensivas e intensivas\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/extensive-and-intensive-properties\/\"><strong><span>vari\u00e1vel intensiva<\/span><\/strong>\u00a0<\/a><span>\u00e9 constante em um sistema fechado.\u00a0Realmente s\u00f3 \u00e9 relevante em sistemas l\u00edquidos ou gasosos.<\/span><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-40 lgc-tablet-grid-40 lgc-mobile-grid-100 lgc-equal-heights  lgc-last\">\n<div class=\"inside-grid-column\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/What-is-Pressure.png\"><img loading=\"lazy\" class=\"aligncenter size-medium wp-image-16371 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/What-is-Pressure-300x129.png\" alt=\"O que \u00e9 press\u00e3o\" width=\"300\" height=\"129\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/What-is-Pressure-300x129.png\" \/><\/a><span>[snippet xyz-ihs = \u201dpress\u00e3o\u201d]<\/span><\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Libras por polegada quadrada &#8211; psi<\/span><\/h2>\n<p><span>A unidade padr\u00e3o no sistema ingl\u00eas \u00e9 a\u00a0<\/span><strong><span>libra-for\u00e7a por polegada quadrada (psi)<\/span><\/strong><span>\u00a0.\u00a0\u00c9 a press\u00e3o resultante de uma for\u00e7a de uma libra-for\u00e7a aplicada a uma \u00e1rea de uma polegada quadrada.<\/span><\/p>\n<ul>\n<li><strong><span>1 psi 1 lbf \/ in\u00a0<\/span><sup><span>2<\/span><\/sup><span>\u00a0= 4,45 N \/ (0,0254 m)\u00a0<\/span><sup><span>2<\/span><\/sup><span>\u00a0\u2248 6895 kg \/ m\u00a0<\/span><sup><span>2<\/span><\/sup><\/strong><\/li>\n<\/ul>\n<p><span>Portanto, uma libra por polegada quadrada \u00e9 aproximadamente 6895 Pa.<\/span><\/p>\n<p><span>A unidade de medida denominada atmosfera padr\u00e3o (atm) \u00e9 definida como:<\/span><\/p>\n<ul>\n<li><strong><span>1 atm = 14,7 psi<\/span><\/strong><\/li>\n<\/ul>\n<p><span>A atmosfera padr\u00e3o aproxima-se da press\u00e3o m\u00e9dia ao n\u00edvel do mar na latitude de 45 \u00b0 N. Observe que h\u00e1 uma diferen\u00e7a entre a\u00a0<\/span><strong><span>atmosfera padr\u00e3o<\/span><\/strong><span>\u00a0(atm) e a\u00a0<\/span><strong><span>atmosfera t\u00e9cnica<\/span><\/strong><span>\u00a0(em).<\/span><\/p>\n<p><span>Uma atmosfera t\u00e9cnica \u00e9 uma unidade de press\u00e3o n\u00e3o SI igual a um quilograma-for\u00e7a por cent\u00edmetro quadrado.<\/span><\/p>\n<ul>\n<li><strong><span>1 a = 14,2 psi<\/span><\/strong><\/li>\n<\/ul>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Pressure-Units-pascal-bar-psi-atmosphere.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-16280 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Pressure-Units-pascal-bar-psi-atmosphere.png\" alt=\"Tabela - Convers\u00e3o entre unidades de press\u00e3o - pascal, bar, psi, atmosfera\" width=\"659\" height=\"289\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Pressure-Units-pascal-bar-psi-atmosphere.png\" \/><\/a><\/p>\n<p><span>Veja tamb\u00e9m:\u00a0<\/span><a title=\"Pascal - Unidade de Press\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/pascal-unit-of-pressure\/\"><span>Pascal &#8211; Unidade de Press\u00e3o<\/span><\/a><\/p>\n<p><span>Veja tamb\u00e9m:\u00a0<\/span><a title=\"Bar - Unidade de Press\u00e3o\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/bar-unit-of-pressure\/\"><span>Bar &#8211; Unidade de press\u00e3o<\/span><\/a><\/p>\n<p><span>Vide tamb\u00e9m:\u00a0<\/span><a title=\"Press\u00f5es t\u00edpicas em engenharia - Exemplos\" href=\"https:\/\/www.nuclear-power.com\/nuclear-engineering\/thermodynamics\/thermodynamic-properties\/what-is-pressure-physics\/typical-pressures-in-engineering-examples\/\"><span>Press\u00f5es t\u00edpicas em engenharia<\/span><\/a><\/p>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2><span>Press\u00e3o absoluta vs. press\u00e3o manom\u00e9trica<\/span><\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/absolute-vs.-gauge-pressure.png\"><img loading=\"lazy\" class=\"alignright size-full wp-image-16281 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/absolute-vs.-gauge-pressure.png\" alt=\"press\u00e3o absoluta versus man\u00f4metro\" width=\"388\" height=\"247\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/absolute-vs.-gauge-pressure.png\" \/><\/a><span>A press\u00e3o como discutido acima \u00e9 chamada\u00a0<\/span><strong><span>press\u00e3o absoluta<\/span><\/strong><span>\u00a0.\u00a0Frequentemente, ser\u00e1 importante distinguir entre\u00a0<\/span><strong><span>press\u00e3o absoluta<\/span><\/strong><span>\u00a0e\u00a0<\/span><strong><span>press\u00e3o manom\u00e9trica<\/span><\/strong><span>\u00a0.\u00a0Neste artigo, o termo press\u00e3o refere-se \u00e0 press\u00e3o absoluta, a menos que seja explicitamente indicado o contr\u00e1rio.\u00a0Por\u00e9m, na engenharia, geralmente lidamos com press\u00f5es\u00a0<\/span><strong><span>medidas<\/span><\/strong><span>\u00a0por alguns dispositivos.\u00a0Embora press\u00f5es absolutas devam ser usadas em rela\u00e7\u00f5es termodin\u00e2micas,\u00a0<\/span><strong><span>os<\/span><\/strong><span>\u00a0dispositivos de\u00a0<strong>medi\u00e7\u00e3o de press\u00e3o<\/strong>\u00a0geralmente indicam a\u00a0<\/span><strong><span>diferen\u00e7a<\/span><\/strong><span>\u00a0entre a press\u00e3o absoluta em um sistema e a press\u00e3o absoluta da atmosfera existente fora do dispositivo de medi\u00e7\u00e3o.\u00a0Eles medem a\u00a0<\/span><strong><span>press\u00e3o<\/span><\/strong><span>\u00a0do\u00a0<strong>man\u00f4metro<\/strong>\u00a0.<\/span><\/p>\n<ul>\n<li><strong><span>Press\u00e3o absoluta.\u00a0<\/span><\/strong><span>Quando a press\u00e3o \u00e9 medida em rela\u00e7\u00e3o a um v\u00e1cuo perfeito, \u00e9 chamada press\u00e3o absoluta (psia).\u00a0Libras por polegada quadrada absoluta (psia) s\u00e3o usadas para deixar claro que a press\u00e3o \u00e9 relativa ao v\u00e1cuo e n\u00e3o \u00e0 press\u00e3o atmosf\u00e9rica ambiente.\u00a0Como a press\u00e3o atmosf\u00e9rica ao n\u00edvel do mar \u00e9 de cerca de 101,3 kPa (14,7 psi), isso ser\u00e1 adicionado a qualquer leitura de press\u00e3o feita no ar ao n\u00edvel do mar.<\/span><\/li>\n<li><strong><span>Press\u00e3o manom\u00e9trica.\u00a0<\/span><\/strong><span>Quando a press\u00e3o \u00e9 medida em rela\u00e7\u00e3o \u00e0 press\u00e3o atmosf\u00e9rica (14,7 psi), \u00e9 chamada press\u00e3o manom\u00e9trica (psig).\u00a0O termo press\u00e3o manom\u00e9trica \u00e9 aplicado quando a press\u00e3o no sistema \u00e9 maior que a press\u00e3o atmosf\u00e9rica local, p\u00a0<\/span><sub><span>atm<\/span><\/sub><span>\u00a0.\u00a0A \u00faltima escala de press\u00e3o foi desenvolvida porque quase todos os man\u00f4metros registram zero quando abertos para a atmosfera.\u00a0As press\u00f5es do man\u00f4metro s\u00e3o positivas se estiverem acima da press\u00e3o atmosf\u00e9rica e negativas se estiverem abaixo da press\u00e3o atmosf\u00e9rica.<\/span><\/li>\n<\/ul>\n<p><em><span>p\u00a0<\/span><\/em><em><sub><span>gauge<\/span><\/sub><\/em><em><span>\u00a0= p\u00a0<\/span><\/em><em><sub><span>absoluto<\/span><\/sub><\/em><em><span>\u00a0&#8211; p\u00a0<\/span><\/em><em><sub><span>absoluto;\u00a0atm<\/span><\/sub><\/em><\/p>\n<ul>\n<li><strong><span>Press\u00e3o atmosf\u00e9rica.\u00a0<\/span><\/strong><span>Press\u00e3o atmosf\u00e9rica \u00e9 a press\u00e3o no ar circundante na &#8211; ou &#8220;pr\u00f3ximo&#8221; da &#8211; superf\u00edcie da terra.\u00a0A press\u00e3o atmosf\u00e9rica varia com a temperatura e a altitude acima do n\u00edvel do mar.\u00a0A\u00a0<\/span><strong><span>press\u00e3o atmosf\u00e9rica padr\u00e3o<\/span><\/strong><span>\u00a0aproxima-se da press\u00e3o m\u00e9dia ao n\u00edvel do mar na latitude de 45 \u00b0 N. A\u00a0<\/span><strong><span>press\u00e3o atmosf\u00e9rica padr\u00e3o<\/span><\/strong><span>\u00a0\u00e9 definida ao n\u00edvel do mar a\u00a0<\/span><em><span>273\u00a0<\/span><\/em><em><sup><span>o<\/span><\/sup><\/em><em><span>\u00a0K (0\u00a0<\/span><\/em><em><sup><span>o<\/span><\/sup><\/em><em><span>\u00a0C)<\/span><\/em><span>\u00a0e \u00e9:<\/span>\n<ul>\n<li><strong><em><span>101325 Pa<\/span><\/em><\/strong><\/li>\n<li><strong><em><span>1.01325 bar<\/span><\/em><\/strong><\/li>\n<li><strong><em><span>14.696 psi<\/span><\/em><\/strong><\/li>\n<li><strong><em><span>760 mmHg<\/span><\/em><\/strong><\/li>\n<li><strong><em><span>760 torr<\/span><\/em><\/strong><\/li>\n<\/ul>\n<\/li>\n<li><strong><span>Press\u00e3o negativa do man\u00f4metro &#8211; Press\u00e3o de v\u00e1cuo.\u00a0<\/span><\/strong><span>Quando a press\u00e3o atmosf\u00e9rica local \u00e9 maior que a press\u00e3o no sistema, o termo\u00a0<\/span><strong><span>press\u00e3o de v\u00e1cuo<\/span><\/strong><span>\u00a0\u00e9 usado.\u00a0Um v\u00e1cuo perfeito corresponderia \u00e0 press\u00e3o zero absoluta.\u00a0Certamente \u00e9 poss\u00edvel ter uma press\u00e3o manom\u00e9trica negativa, mas n\u00e3o \u00e9 poss\u00edvel ter uma press\u00e3o absoluta negativa.\u00a0Por exemplo, uma press\u00e3o absoluta de 80 kPa pode ser descrita como uma press\u00e3o manom\u00e9trica de -21 kPa (ou seja, 21 kPa abaixo de uma press\u00e3o atmosf\u00e9rica de 101 kPa).<\/span><\/li>\n<\/ul>\n<p><em><span>p\u00a0<\/span><\/em><em><sub><span>v\u00e1cuo<\/span><\/sub><\/em><em><span>\u00a0= p\u00a0<\/span><\/em><em><sub><span>absoluto;\u00a0atm<\/span><\/sub><\/em><em><span>\u00a0&#8211; p\u00a0<\/span><\/em><em><sub><span>absoluto<\/span><\/sub><\/em><\/p>\n<p><span>Por exemplo, um pneu de carro bombeado at\u00e9 2,5 atm (36,75 psig) acima da press\u00e3o atmosf\u00e9rica local (digamos 1 atm ou 14,7 psia localmente), ter\u00e1 uma press\u00e3o absoluta de 2,5 + 1 = 3,5 atm (36,75 + 14,7 = 51,45 psia ou 36,75 psig).<\/span><\/p>\n<p><span>Por outro lado, as\u00a0<\/span><span>turbinas a<\/span><span>\u00a0vapor de condensa\u00e7\u00e3o\u00a0\u00a0(em\u00a0<a title=\"Usina nuclear\" href=\"https:\/\/www.nuclear-power.com\/nuclear-power-plant\/\">usinas nucleares<\/a>\u00a0) descarregam o\u00a0<a title=\"Propriedades do Steam - O que \u00e9 o Steam\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-o-steam-propriedades-do-steam-definicao\/\">vapor<\/a>\u00a0a uma press\u00e3o bem abaixo da atmosf\u00e9rica\u00a0<\/span><span>(por exemplo, a 0,08 bar ou 8 kPa ou 1,16 psia)\u00a0<\/span><span>e em um estado parcialmente condensado.\u00a0Em unidades relativas, \u00e9 uma press\u00e3o manom\u00e9trica negativa de cerca de &#8211; 0,92 bar, &#8211; 92 kPa ou &#8211; 13,54 psig.<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<div><\/div>\n<div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Este artigo \u00e9 baseado na tradu\u00e7\u00e3o autom\u00e1tica do artigo original em ingl\u00eas. Para mais informa\u00e7\u00f5es, consulte o artigo em ingl\u00eas. Voc\u00ea pode nos ajudar. Se voc\u00ea deseja corrigir a tradu\u00e7\u00e3o, envie-a para: translations@nuclear-power.com ou preencha o formul\u00e1rio de tradu\u00e7\u00e3o on-line. Agradecemos sua ajuda, atualizaremos a tradu\u00e7\u00e3o o mais r\u00e1pido poss\u00edvel. Obrigado.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Libras por polegada quadrada &#8211; psi &#8211; psig &#8211; psia. A unidade padr\u00e3o no sistema ingl\u00eas \u00e9 a for\u00e7a da libra por polegada quadrada (psi). 1 psi \u00e9 aproximadamente 6895 Pa. Engenharia T\u00e9rmica O que \u00e9 press\u00e3o Press\u00e3o\u00a0\u00e9 uma medida da\u00a0for\u00e7a exercida\u00a0por unidade de \u00e1rea nos limites de uma subst\u00e2ncia.\u00a0A unidade padr\u00e3o de\u00a0press\u00e3o\u00a0no sistema SI &#8230; <a title=\"Libra por polegada quadrada &#8211; psi &#8211; Defini\u00e7\u00e3o\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/libra-por-polegada-quadrada-psi-definicao\/\" aria-label=\"More on Libra por polegada quadrada &#8211; psi &#8211; Defini\u00e7\u00e3o\">Ler mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[14],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Libra por polegada quadrada - psi - Defini\u00e7\u00e3o<\/title>\n<meta name=\"description\" content=\"Libras por polegada quadrada - psi - psig - psia. 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