{"id":49077,"date":"2019-11-14T09:58:52","date_gmt":"2019-11-14T08:58:52","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/o-que-e-diametro-hidraulico-definicao\/"},"modified":"2020-02-01T17:33:16","modified_gmt":"2020-02-01T16:33:16","slug":"o-que-e-diametro-hidraulico-definicao","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-diametro-hidraulico-definicao\/","title":{"rendered":"O que \u00e9 di\u00e2metro hidr\u00e1ulico &#8211; defini\u00e7\u00e3o"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">O di\u00e2metro hidr\u00e1ulico, Dh, \u00e9 um termo comumente usado ao manipular o fluxo em tubos n\u00e3o circulares.\u00a0O di\u00e2metro hidr\u00e1ulico transforma dutos n\u00e3o circulares em tubos de di\u00e2metro equivalente.\u00a0Engenharia T\u00e9rmica<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Di\u00e2metro hidr\u00e1ulico<\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-equation.png\"><img loading=\"lazy\" class=\"aligncenter size-full wp-image-14418 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-equation.png\" alt=\"Di\u00e2metro hidr\u00e1ulico - equa\u00e7\u00e3o\" width=\"99\" height=\"70\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-equation.png\" \/><\/a><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-non-circular-tubes.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-14421 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-non-circular-tubes-232x300.png\" alt=\"Di\u00e2metro hidr\u00e1ulico\" width=\"232\" height=\"300\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter-non-circular-tubes-232x300.png\" \/><\/a><strong>O di\u00e2metro hidr\u00e1ulico, D\u00a0<sub>h<\/sub><\/strong>\u00a0, \u00e9 um termo comumente usado ao manipular o fluxo em\u00a0<strong>tubos e canais n\u00e3o circulares<\/strong>\u00a0.\u00a0O di\u00e2metro hidr\u00e1ulico transforma dutos n\u00e3o circulares em tubos de\u00a0<strong>di\u00e2metro equivalente<\/strong>\u00a0.\u00a0Usando este termo, pode-se calcular muitas coisas da mesma maneira que para um tubo redondo.\u00a0Nesta equa\u00e7\u00e3o, A \u00e9 a\u00a0<strong>\u00e1rea da se\u00e7\u00e3o transversal<\/strong>\u00a0e P \u00e9 o\u00a0<strong>per\u00edmetro \u00famido<\/strong>\u00a0da se\u00e7\u00e3o.<\/p>\n<div class=\"su-spacer\"><\/div>\n<\/div>\n<\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Exemplo: n\u00famero de Reynolds para uma tubula\u00e7\u00e3o prim\u00e1ria e um pacote de combust\u00edvel<\/h2>\n<pre>\u00c9 um exemplo ilustrativo, os dados a seguir n\u00e3o correspondem a nenhum projeto de reator.<\/pre>\n<p><a title=\"PWR - Reator de \u00e1gua pressurizada\" href=\"https:\/\/www.nuclear-power.com\/pwr-pressurized-water-reactor\/\"><strong><span>Os reatores de \u00e1gua pressurizada<\/span><\/strong><\/a><span>\u00a0s\u00e3o resfriados e<\/span><a title=\"Moderador de n\u00eautrons\" href=\"https:\/\/www.nuclear-power.com\/neutron-moderator\/\"><span>\u00a0moderados<\/span><\/a><span>\u00a0por \u00e1gua l\u00edquida de alta press\u00e3o (por exemplo, 16MPa).\u00a0A essa press\u00e3o, a \u00e1gua ferve a aproximadamente 350 \u00b0 C (662 \u00b0 F).\u00a0A temperatura de entrada da \u00e1gua \u00e9 de cerca de 290 \u00b0 C (~ ~ 720 kg \/ m<\/span><sup><span>\u00a03<\/span><\/sup><span>\u00a0).\u00a0A \u00e1gua (refrigerante) \u00e9 aquecido no n\u00facleo do reactor para cerca de 325 \u00b0 C (\u2374 ~ 654 kg \/ m<\/span><sup><span>\u00a03<\/span><\/sup><span>\u00a0) medida que a \u00e1gua flui atrav\u00e9s<\/span><a title=\"N\u00facleo do reator\" href=\"https:\/\/www.reactor-physics.com\/what-is-reactor-core-definition\/\"><span>\u00a0do n\u00facleo<\/span><\/a><span>\u00a0.<\/span><\/p>\n<figure id=\"attachment_14387\" class=\"wp-caption alignright\" aria-describedby=\"caption-attachment-14387\"><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter.png\"><img loading=\"lazy\" class=\"wp-image-14387 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter.png\" alt=\"Di\u00e2metro hidr\u00e1ulico\" width=\"399\" height=\"293\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Hydraulic-Diameter.png\" \/><\/a><figcaption id=\"caption-attachment-14387\" class=\"wp-caption-text\"><span>O di\u00e2metro hidr\u00e1ulico das barras de combust\u00edvel \u00e9 fornecido.<\/span><\/figcaption><\/figure>\n<p><span>O circuito prim\u00e1rio dos PWRs t\u00edpicos \u00e9 dividido em\u00a0<\/span><strong><span>4 circuitos independentes<\/span><\/strong><span>\u00a0(di\u00e2metro da tubula\u00e7\u00e3o ~ 700 mm), cada circuito compreende um\u00a0<\/span><a title=\"Gerador de vapor\" href=\"https:\/\/www.nuclear-power.com\/steam-generator\/\"><strong><span>gerador de vapor<\/span><\/strong>\u00a0<\/a><span>e uma\u00a0<\/span><a title=\"Bomba de refrigera\u00e7\u00e3o do reator\" href=\"https:\/\/www.nuclear-power.com\/reactor-coolant-pump\/\"><strong><span>bomba de refrigera\u00e7\u00e3o principal<\/span><\/strong><\/a><span>\u00a0.\u00a0Dentro do vaso de press\u00e3o do reator (RPV), o l\u00edquido de arrefecimento flui primeiro para fora do n\u00facleo do reator (atrav\u00e9s do\u00a0<\/span><strong><span>descendente<\/span><\/strong><span>\u00a0).\u00a0Do fundo do vaso de press\u00e3o, o fluxo \u00e9 revertido atrav\u00e9s do n\u00facleo, onde a temperatura do l\u00edquido de refrigera\u00e7\u00e3o aumenta \u00e0 medida que passa pelas barras de combust\u00edvel e pelos conjuntos formados por elas.<\/span><\/p>\n<p><span>Presumir:<\/span><\/p>\n<ul>\n<li><span>a velocidade do fluxo da tubula\u00e7\u00e3o prim\u00e1ria \u00e9 constante e igual a 17 m \/ s,<\/span><\/li>\n<li><span>a velocidade de fluxo do n\u00facleo \u00e9 constante e igual a 5 m \/ s,<\/span><\/li>\n<li><span>o\u00a0<\/span><strong><span>di\u00e2metro hidr\u00e1ulico do canal de combust\u00edvel<\/span><\/strong><span>\u00a0,\u00a0<\/span><em><span>D\u00a0<\/span><\/em><em><sub><span>h<\/span><\/sub><\/em><span>\u00a0, \u00e9 igual a 1 cm<\/span><\/li>\n<li><span>a viscosidade cinem\u00e1tica da \u00e1gua a 290 \u00b0 C \u00e9 igual a 0,12 x 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0m\u00a0<\/span><sup><span>2<\/span><\/sup><span>\u00a0\/ s<\/span><\/li>\n<\/ul>\n<p><span>Veja tamb\u00e9m:\u00a0<\/span><a title=\"Equa\u00e7\u00e3o de continuidade\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-equacao-de-continuidade-definicao\/\"><span>Exemplo:\u00a0<\/span><strong><span>Vaz\u00e3o atrav\u00e9s do n\u00facleo de um reator<\/span><\/strong><\/a><\/p>\n<p><span>Determinar<\/span><\/p>\n<ul>\n<li><span>o regime de fluxo e o n\u00famero de Reynolds dentro do\u00a0<\/span><strong><span>canal de combust\u00edvel<\/span><\/strong><\/li>\n<li><span>o regime de fluxo e o n\u00famero de Reynolds dentro da\u00a0<\/span><strong><span>tubula\u00e7\u00e3o prim\u00e1ria<\/span><\/strong><\/li>\n<\/ul>\n<p><span>O n\u00famero de Reynolds dentro da tubula\u00e7\u00e3o prim\u00e1ria \u00e9 igual a:<\/span><\/p>\n<p><strong><span>Re\u00a0<\/span><sub><span>D<\/span><\/sub><\/strong><span>\u00a0= 17 [m \/ s] x 0,7 [m] \/ 0,12 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0[m\u00a0<\/span><sup><span>2<\/span><\/sup><span>\u00a0\/ s] =\u00a0<\/span><strong><span>99 000 000<\/span><\/strong><\/p>\n<p><span>Isso satisfaz plenamente as\u00a0<\/span><strong><span>condi\u00e7\u00f5es turbulentas<\/span><\/strong><span>\u00a0.<\/span><\/p>\n<p><span>O n\u00famero de Reynolds dentro do canal de combust\u00edvel \u00e9 igual a:<\/span><\/p>\n<p><strong><span>Re\u00a0<\/span><sub><span>DH<\/span><\/sub><\/strong><span>\u00a0= 5 [m \/ s] x 0,01 [m] \/ 0,12 \u00d7 10\u00a0<\/span><sup><span>-6<\/span><\/sup><span>\u00a0[m\u00a0<\/span><sup><span>2<\/span><\/sup><span>\u00a0\/ s] =\u00a0<\/span><strong><span>416 600<\/span><\/strong><\/p>\n<p><span>Isso tamb\u00e9m satisfaz plenamente as\u00a0<\/span><strong><span>condi\u00e7\u00f5es turbulentas.<\/span><\/strong><\/p>\n<\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Este artigo \u00e9 baseado na tradu\u00e7\u00e3o autom\u00e1tica do artigo original em ingl\u00eas. Para mais informa\u00e7\u00f5es, consulte o artigo em ingl\u00eas. Voc\u00ea pode nos ajudar. Se voc\u00ea deseja corrigir a tradu\u00e7\u00e3o, envie-a para: translations@nuclear-power.com ou preencha o formul\u00e1rio de tradu\u00e7\u00e3o on-line. Agradecemos sua ajuda, atualizaremos a tradu\u00e7\u00e3o o mais r\u00e1pido poss\u00edvel. Obrigado.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>O di\u00e2metro hidr\u00e1ulico, Dh, \u00e9 um termo comumente usado ao manipular o fluxo em tubos n\u00e3o circulares.\u00a0O di\u00e2metro hidr\u00e1ulico transforma dutos n\u00e3o circulares em tubos de di\u00e2metro equivalente.\u00a0Engenharia T\u00e9rmica Di\u00e2metro hidr\u00e1ulico O di\u00e2metro hidr\u00e1ulico, D\u00a0h\u00a0, \u00e9 um termo comumente usado ao manipular o fluxo em\u00a0tubos e canais n\u00e3o circulares\u00a0.\u00a0O di\u00e2metro hidr\u00e1ulico transforma dutos n\u00e3o circulares &#8230; <a title=\"O que \u00e9 di\u00e2metro hidr\u00e1ulico &#8211; defini\u00e7\u00e3o\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-diametro-hidraulico-definicao\/\" aria-label=\"More on O que \u00e9 di\u00e2metro hidr\u00e1ulico &#8211; defini\u00e7\u00e3o\">Ler mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[14],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>O que \u00e9 di\u00e2metro hidr\u00e1ulico - defini\u00e7\u00e3o<\/title>\n<meta name=\"description\" content=\"O di\u00e2metro hidr\u00e1ulico, Dh, \u00e9 um termo comumente usado ao manipular o fluxo em tubos n\u00e3o circulares. 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