{"id":49173,"date":"2019-11-14T20:38:38","date_gmt":"2019-11-14T19:38:38","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/o-que-e-forca-em-um-cotovelo-defletor-definicao\/"},"modified":"2020-02-02T09:42:18","modified_gmt":"2020-02-02T08:42:18","slug":"o-que-e-forca-em-um-cotovelo-defletor-definicao","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-forca-em-um-cotovelo-defletor-definicao\/","title":{"rendered":"O que \u00e9 for\u00e7a em um cotovelo defletor &#8211; Defini\u00e7\u00e3o"},"content":{"rendered":"<div class=\"su-quote su-quote-style-default\">\n<div class=\"su-quote-inner su-clearfix\">Um cotovelo (digamos, da tubula\u00e7\u00e3o prim\u00e1ria) \u00e9 usado para desviar o fluxo de \u00e1gua a uma velocidade de 17 m \/ s.\u00a0Calcule a for\u00e7a na parede de um cotovelo defletor.\u00a0Engenharia T\u00e9rmica<\/div>\n<\/div>\n<div class=\"su-divider su-divider-style-dotted\"><\/div>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<div class=\"su-spacer\"><\/div>\n<h2>Exemplo: a for\u00e7a que atua sobre um cotovelo defletor<\/h2>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-control-volume.png\"><img loading=\"lazy\" class=\"alignright size-medium wp-image-14368 lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-control-volume-300x255.png\" alt=\"Equa\u00e7\u00e3o do momento - volume de controle\" width=\"300\" height=\"255\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-control-volume-300x255.png\" \/><\/a><strong>Um cotovelo<\/strong>\u00a0(digamos, da tubula\u00e7\u00e3o prim\u00e1ria) \u00e9 usado para desviar o fluxo de \u00e1gua a uma velocidade de\u00a0<strong>17 m \/ s<\/strong>\u00a0.\u00a0O di\u00e2metro da tubula\u00e7\u00e3o \u00e9 igual a\u00a0<strong>700 mm<\/strong>\u00a0.\u00a0A press\u00e3o manom\u00e9trica no interior do tubo \u00e9 de cerca de\u00a0<strong>16 MPa<\/strong>\u00a0\u00e0 temperatura de 290 \u00b0 C.\u00a0Fluido \u00e9 de densidade constante\u00a0<strong>\u2374 ~ 720 kg \/ m\u00a0<sup>3<\/sup><\/strong>\u00a0(a 290 \u00b0 C).\u00a0O \u00e2ngulo do cotovelo \u00e9 de\u00a0<strong>45 \u00b0<\/strong>\u00a0.<\/p>\n<p>Calcule a\u00a0<strong>for\u00e7a na parede<\/strong>\u00a0de um cotovelo defletor (ou seja, calcule o vetor F\u00a0<sub>3<\/sub>\u00a0).<\/p>\n<p><strong>Premissas:<\/strong><\/p>\n<ul>\n<li>O fluxo \u00e9 constante.<\/li>\n<li>As perdas por atrito s\u00e3o insignificantes.<\/li>\n<li>O peso do cotovelo \u00e9 insignificante.<\/li>\n<li>O peso da \u00e1gua no cotovelo \u00e9 insignificante.<\/li>\n<\/ul>\n<p>Tomamos o cotovelo como o\u00a0<strong>volume de controle<\/strong>\u00a0.\u00a0O volume de controle \u00e9 mostrado na imagem.\u00a0A equa\u00e7\u00e3o do momento \u00e9 uma equa\u00e7\u00e3o vetorial, portanto possui tr\u00eas componentes.\u00a0Tomamos as coordenadas x e z como mostrado e resolveremos o problema separadamente, de acordo com essas coordenadas.<\/p>\n<div class=\"lgc-column lgc-grid-parent lgc-grid-100 lgc-tablet-grid-100 lgc-mobile-grid-100 lgc-equal-heights  lgc-first lgc-last\">\n<div class=\"inside-grid-column\">\n<p><span>Primeiro, vamos considerar o componente na\u00a0<\/span><strong><span>coordenada x<\/span><\/strong><span>\u00a0.\u00a0A conserva\u00e7\u00e3o da equa\u00e7\u00e3o do momento linear se torna:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-x-coordinate.png\"><img loading=\"lazy\" class=\"size-full wp-image-14367 alignleft lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-x-coordinate.png\" alt=\"Equa\u00e7\u00e3o do momento - coordenada x\" width=\"603\" height=\"371\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-x-coordinate.png\" \/><\/a><\/p>\n<p><span>Segundo, vamos considerar o componente na\u00a0<\/span><strong><span>coordenada y<\/span><\/strong><span>\u00a0.\u00a0A conserva\u00e7\u00e3o da equa\u00e7\u00e3o do momento linear se torna:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-y-coordinate.png\"><img loading=\"lazy\" class=\"size-full wp-image-14365 alignleft lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-y-coordinate.png\" alt=\"Equa\u00e7\u00e3o do momento - coordenada y\" width=\"566\" height=\"383\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-y-coordinate.png\" \/><\/a><\/p>\n<p><span>A for\u00e7a final que atua na parede de um cotovelo defletor ser\u00e1:<\/span><\/p>\n<p><a href=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-resulting-force.png\"><img loading=\"lazy\" class=\"size-full wp-image-14366 alignleft lazy-loaded\" src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-resulting-force.png\" alt=\"Equa\u00e7\u00e3o do momento - for\u00e7a resultante\" width=\"294\" height=\"51\" data-lazy-type=\"image\" data-src=\"https:\/\/thermal-engineering.org\/wp-content\/uploads\/2019\/05\/Momentum-equation-resulting-force.png\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"inside-grid-column\"><\/div>\n<div><\/div>\n<div><\/div>\n<div><\/div>\n<p>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.<\/p>\n<p>Este artigo \u00e9 baseado na tradu\u00e7\u00e3o autom\u00e1tica do artigo original em ingl\u00eas. Para mais informa\u00e7\u00f5es, consulte o artigo em ingl\u00eas. Voc\u00ea pode nos ajudar. Se voc\u00ea deseja corrigir a tradu\u00e7\u00e3o, envie-a para: translations@nuclear-power.com ou preencha o formul\u00e1rio de tradu\u00e7\u00e3o on-line. Agradecemos sua ajuda, atualizaremos a tradu\u00e7\u00e3o o mais r\u00e1pido poss\u00edvel. Obrigado.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Um cotovelo (digamos, da tubula\u00e7\u00e3o prim\u00e1ria) \u00e9 usado para desviar o fluxo de \u00e1gua a uma velocidade de 17 m \/ s.\u00a0Calcule a for\u00e7a na parede de um cotovelo defletor.\u00a0Engenharia T\u00e9rmica Exemplo: a for\u00e7a que atua sobre um cotovelo defletor Um cotovelo\u00a0(digamos, da tubula\u00e7\u00e3o prim\u00e1ria) \u00e9 usado para desviar o fluxo de \u00e1gua a uma &#8230; <a title=\"O que \u00e9 for\u00e7a em um cotovelo defletor &#8211; Defini\u00e7\u00e3o\" class=\"read-more\" href=\"https:\/\/www.thermal-engineering.org\/pt-br\/o-que-e-forca-em-um-cotovelo-defletor-definicao\/\" aria-label=\"More on O que \u00e9 for\u00e7a em um cotovelo defletor &#8211; Defini\u00e7\u00e3o\">Ler mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[14],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v15.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>O que \u00e9 for\u00e7a em um cotovelo defletor - Defini\u00e7\u00e3o<\/title>\n<meta name=\"description\" content=\"Um cotovelo (digamos, da tubula\u00e7\u00e3o prim\u00e1ria) \u00e9 usado para desviar o fluxo de \u00e1gua a uma velocidade de 17 m \/ s. 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