{"id":670545,"date":"2024-10-12T20:23:38","date_gmt":"2024-10-12T19:23:38","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/?p=670545"},"modified":"2024-10-12T20:23:38","modified_gmt":"2024-10-12T19:23:38","slug":"pitot-tupu-ile-hiz-nasil-olculur","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/tr\/pitot-tupu-ile-hiz-nasil-olculur\/","title":{"rendered":"Pitot T\u00fcp\u00fc ile H\u0131z Nas\u0131l \u00d6l\u00e7\u00fcl\u00fcr?"},"content":{"rendered":"

Pitot T\u00fcp\u00fc ile H\u0131z Nas\u0131l \u00d6l\u00e7\u00fcl\u00fcr? Pitot t\u00fcp\u00fc kullanarak hava ak\u0131m\u0131 ve ak\u0131\u015fkanlar\u0131n h\u0131z\u0131n\u0131 do\u011fru bir \u015fekilde \u00f6l\u00e7menin temel prensiplerini a\u00e7\u0131kl\u0131yoruz.<\/p>\n

\"Pitot<\/p>\n

Pitot T\u00fcp\u00fc ile H\u0131z Nas\u0131l \u00d6l\u00e7\u00fcl\u00fcr?<\/h2>\n

Pitot t\u00fcp\u00fc, ak\u0131\u015fkanlar\u0131n h\u0131z\u0131n\u0131 \u00f6l\u00e7mek i\u00e7in s\u0131k\u00e7a kullan\u0131lan bir cihazd\u0131r. \u0130lk olarak Henri Pitot taraf\u0131ndan 18. y\u00fczy\u0131lda geli\u015ftirilmi\u015ftir ve g\u00fcn\u00fcm\u00fczde \u00f6zellikle hava ve su ak\u0131\u015f\u0131 h\u0131zlar\u0131n\u0131n belirlenmesinde kullan\u0131lmaktad\u0131r. Bu basit ama etkili cihaz, u\u00e7aklarda, sualt\u0131 ara\u00e7lar\u0131nda ve fabrika boru hatlar\u0131nda yayg\u0131n olarak kullan\u0131l\u0131r.<\/p>\n

Pitot T\u00fcp\u00fcn\u00fcn Yap\u0131s\u0131<\/h2>\n

Pitot t\u00fcp\u00fc genellikle iki ana b\u00f6l\u00fcmden olu\u015fur:<\/p>\n

<\/p>\n

  • Statik bas\u0131n\u00e7 portu:<\/b> Ak\u0131\u015fkan\u0131n durgun haldeki bas\u0131nc\u0131n\u0131 \u00f6l\u00e7er.<\/li>\n
  • Toplam bas\u0131n\u00e7 portu:<\/b> Ak\u0131\u015fkan\u0131n hareket halindeki toplam bas\u0131nc\u0131n\u0131 \u00f6l\u00e7er.<\/li>\n

    <\/u1><\/p>\n

    Bu iki de\u011fer aras\u0131ndaki fark, ak\u0131\u015fkan\u0131n h\u0131z\u0131n\u0131 hesaplamak i\u00e7in kullan\u0131l\u0131r.<\/p>\n

    H\u0131z\u0131n Hesaplanmas\u0131<\/h2>\n

    H\u0131z belirlemesi Bernoulli denklemi ve bas\u0131n\u00e7 fark\u0131 prensibine g\u00f6re yap\u0131l\u0131r. Bernoulli denklemi temel olarak \u015fu \u015fekildedir:<\/p>\n

    \\( P_t = P_s + \\frac{1}{2} \\rho v^2 \\)<\/p>\n

    Burada:<\/p>\n

    <\/p>\n

  • \\( P_t \\): Toplam bas\u0131n\u00e7<\/li>\n
  • \\( P_s \\): Statik bas\u0131n\u00e7<\/li>\n
  • \\( \\rho \\): Ak\u0131\u015fkan\u0131n yo\u011funlu\u011fu<\/li>\n
  • \\( v \\): Ak\u0131\u015fkan\u0131n h\u0131z\u0131<\/li>\n

    <\/u1><\/p>\n

    E\u011fer toplam bas\u0131n\u00e7 (\\( P_t \\)) ve statik bas\u0131n\u00e7 (\\( P_s \\)) biliniyorsa, h\u0131z (\\( v \\)) \u015fu form\u00fclle hesaplanabilir:<\/p>\n

    \\( v = \\sqrt{ \\frac{2 (P_t – P_s)}{\\rho} } \\)<\/p>\n

    \u00d6rnek Hesaplama<\/h2>\n

    Bir \u00f6rnekle bu hesaplamay\u0131 daha iyi anlayabiliriz. Diyelim ki bir Pitot t\u00fcp\u00fc kullanarak toplam bas\u0131nc\u0131 1200 Pa ve statik bas\u0131nc\u0131 1000 Pa olarak \u00f6l\u00e7t\u00fck. Ak\u0131\u015fkan\u0131n yo\u011funlu\u011fu ise 1.2 kg\/m3<\/sup> olsun. Bu de\u011ferleri yukar\u0131daki form\u00fclde yerine koyarsak:<\/p>\n

    \\( v = \\sqrt{ \\frac{2 (1200 – 1000)}{1.2} } \\)<\/p>\n

    \\( v = \\sqrt{ \\frac{2 \\times 200}{1.2} } \\)<\/p>\n

    \\( v = \\sqrt{ \\frac{400}{1.2} } \\)<\/p>\n

    \\( v = \\sqrt{333.33} \\approx 18.26 \\, \\text{m\/s} \\)<\/p>\n

    Sonu\u00e7<\/h2>\n

    Pitot t\u00fcp\u00fc, basit bir cihaz olmas\u0131na ra\u011fmen, ak\u0131\u015fkanlar\u0131n h\u0131z\u0131n\u0131 belirlemede olduk\u00e7a etkili bir y\u00f6ntem sunar. Statik ve toplam bas\u0131n\u00e7 \u00f6l\u00e7\u00fcmleri kullan\u0131larak, Bernoulli denklemi yard\u0131m\u0131yla h\u0131z kolayca hesaplanabilir. Bu y\u00f6ntem \u00f6zellikle havac\u0131l\u0131k ve denizcilik gibi alanlarda b\u00fcy\u00fck \u00f6nem ta\u015f\u0131maktad\u0131r.<\/p>\n","protected":false},"excerpt":{"rendered":"

    Pitot T\u00fcp\u00fc ile H\u0131z Nas\u0131l \u00d6l\u00e7\u00fcl\u00fcr? Pitot t\u00fcp\u00fc kullanarak hava ak\u0131m\u0131 ve ak\u0131\u015fkanlar\u0131n h\u0131z\u0131n\u0131 do\u011fru bir \u015fekilde \u00f6l\u00e7menin temel prensiplerini a\u00e7\u0131kl\u0131yoruz.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[131],"tags":[],"yoast_head":"\nPitot T\u00fcp\u00fc ile H\u0131z Nas\u0131l \u00d6l\u00e7\u00fcl\u00fcr?<\/title>\n<meta name=\"description\" content=\"Pitot T\u00fcp\u00fc ile H\u0131z Nas\u0131l \u00d6l\u00e7\u00fcl\u00fcr? 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