{"id":753826,"date":"2024-11-18T21:36:15","date_gmt":"2024-11-18T20:36:15","guid":{"rendered":"https:\/\/www.thermal-engineering.org\/?p=753826"},"modified":"2024-11-18T21:36:15","modified_gmt":"2024-11-18T20:36:15","slug":"%e8%92%b8%e6%b1%bd%e5%8f%91%e7%94%9f%e5%99%a8%e5%a6%82%e4%bd%95%e4%ba%a7%e7%94%9f%e8%92%b8%e6%b1%bd","status":"publish","type":"post","link":"https:\/\/www.thermal-engineering.org\/zh-hans\/%e8%92%b8%e6%b1%bd%e5%8f%91%e7%94%9f%e5%99%a8%e5%a6%82%e4%bd%95%e4%ba%a7%e7%94%9f%e8%92%b8%e6%b1%bd\/","title":{"rendered":"\u84b8\u6c7d\u53d1\u751f\u5668\u5982\u4f55\u4ea7\u751f\u84b8\u6c7d"},"content":{"rendered":"<p class=\"sidekick\">\u5173\u952e\u8bcd\uff1a\u84b8\u6c7d\u53d1\u751f\u5668\u5982\u4f55\u4ea7\u751f\u84b8\u6c7d\u3002\u8fd9\u7bc7\u6587\u7ae0\u89e3\u91ca\u4e86\u84b8\u6c7d\u53d1\u751f\u5668\u7684\u5de5\u4f5c\u539f\u7406\uff0c\u901a\u8fc7\u52a0\u70ed\u6c34\u4ea7\u751f\u84b8\u6c7d\uff0c\u9002\u7528\u4e8e\u65e5\u5e38\u5e94\u7528\u548c\u5de5\u4e1a\u573a\u666f\u3002<\/p>\n<p><img src=\"https:\/\/www.thermal-engineering.org\/wp-content\/uploads\/2024\/07\/\u84b8\u6c7d\u53d1\u751f\u5668\u5982\u4f55\u4ea7\u751f\u84b8\u6c7d.png\" alt=\"\u84b8\u6c7d\u53d1\u751f\u5668\u5982\u4f55\u4ea7\u751f\u84b8\u6c7d\" style=\"display: block; margin-left: auto; margin-right: 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= \\Delta U + W\\)<\/p>\n<p>\u5176\u4e2d<\/p>\n<p><u1><\/p>\n<li>\\(Q\\)\uff1a\u8f93\u5165\u7684\u70ed\u91cf<\/li>\n<li>\\(\\Delta U\\)\uff1a\u7cfb\u7edf\u5185\u80fd\u7684\u53d8\u5316<\/li>\n<li>\\(W\\)\uff1a\u5bf9\u73af\u5883\u505a\u7684\u529f<\/li>\n<p><\/u1><\/p>\n<h2>\u6c34\u7684\u6cb8\u70b9\u548c\u538b\u5f3a\u5173\u7cfb<\/h2>\n<p>\u6c34\u7684\u6cb8\u70b9\u4e0d\u4ec5\u53d7\u6e29\u5ea6\u5f71\u54cd\uff0c\u8fd8\u4e0e\u73af\u5883\u538b\u5f3a\u6709\u5173\u3002\u5728\u9ad8\u538b\u4e0b\uff0c\u6c34\u7684\u6cb8\u70b9\u4f1a\u5347\u9ad8\u3002\u4f8b\u5982\uff0c\u5728\u9505\u7089\u8fd9\u79cd\u9ad8\u538b\u73af\u5883\u4e2d\uff0c\u6c34\u53ef\u4ee5\u5728\u9ad8\u4e8e100\u2103\u7684\u6e29\u5ea6\u4e0b\u6cb8\u817e\u3002\u989c\u8001\u5e08<\/p>\n<p>\u8fd9\u4e2a\u5173\u7cfb\u53ef\u4ee5\u7528\u514b\u62c9\u8d1d\u9f99-\u514b\u52b3\u4fee\u65af\u65b9\u7a0b\u8868\u793a\uff1a<\/p>\n<p>\\(\\frac{dP}{dT} = \\frac{L}{T \\Delta 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